Home / IBDP Physics- D.1 Gravitational fields- IB Style Questions For HL Paper 2

IBDP Physics- D.1 Gravitational fields- IB Style Questions For HL Paper 2 -FA 2025

Question

Venus is one of the planets orbiting the Sun. The following information is provided:
Orbital period of Venus \(= 225\) days
Orbital period of Earth \(= 365\) days
(a) Determine the ratio \(\displaystyle \frac{\text{orbital radius of Venus}}{\text{orbital radius of Earth}}\).
(b) Describe how measurements of planetary motion can be used to find the mass of the Sun.
(c) The difference between the greatest and smallest Earth–Sun separations is \(5.0 \times 10^{9}\,m\). The corresponding change in gravitational potential due to the Sun is \(3.0 \times 10^{7}\,J\,kg^{-1}\). Estimate the mean gravitational field strength due to the Sun at Earth’s orbit.

Most-appropriate topic code (IB Physics):

Topic D.1: Gravitational fields — parts (a), (b), (c)
▶️ Answer/Explanation
Detailed solution

(a)
From Kepler’s third law, \(T^{2} \propto r^{3}\). Hence, \[ \frac{r_{V}^{3}}{r_{E}^{3}} = \frac{T_{V}^{2}}{T_{E}^{2}} \] so \[ \frac{r_{V}}{r_{E}} = \left(\frac{T_{V}}{T_{E}}\right)^{2/3} = \left(\frac{225}{365}\right)^{2/3} \approx 0.72 . \]

(b)
The gravitational attraction of the Sun supplies the centripetal force that keeps a planet in orbit. The orbital radius \(r\) and period \(T\) can be measured observationally. Equating gravitational and centripetal forces, \[ \frac{GMm}{r^{2}} = \frac{mv^{2}}{r} = m\left(\frac{4\pi^{2}}{T^{2}}\right)r . \] Rearranging gives \[ M = \frac{4\pi^{2}r^{3}}{GT^{2}} . \] Since \(G\) is known, measuring \(r\) and \(T\) allows the mass of the Sun to be determined.

(c)
The gravitational field strength is the rate of change of gravitational potential with distance: \[ g = \frac{\Delta V}{\Delta r} . \] Using the given values, \[ g = \frac{3.0 \times 10^{7}}{5.0 \times 10^{9}} = 6.0 \times 10^{-3}\,m\,s^{-2} \] (or \(6.0 \times 10^{-3}\,N\,kg^{-1}\)).

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