IBDP Physics- D.3 Motion in electromagnetic fields- IB Style Questions For HL Paper 1A -FA 2025
Question
▶️ Answer/Explanation
Negative charges moving counter-clockwise = conventional current flows clockwise
Using right-hand rule for magnetic force on current loops:
• Field into page
• Current clockwise
This creates an outward magnetic force on all parts of the loop, tending to expand it
✅ Answer: (C) The diameter of the coil will tend to increase
Question
▶️ Answer / Explanation
With the velocity perpendicular to the magnetic field, the magnetic force provides the centripetal force:
\(F_B = qvB\) and \(F_C = \dfrac{mv^2}{r}\)
Equate them:
\(qvB = \dfrac{mv^2}{r}\)
Cancel one \(v\) and solve for \(v\):
\(qB = \dfrac{mv}{r}\)
\(v = \dfrac{qB}{m}\,r\)
So \(v \propto r\): a straight line through the origin.
✅ Answer: A
Question
(B) To the right of the page
(C) Out of the page
(D) Into the page
▶️ Answer / Explanation
A moving charged particle in a magnetic field experiences a magnetic force given by:
\( \vec{F} = q\,\vec{v} \times \vec{B} \)
The sphere is negatively charged, so the direction of the magnetic force is opposite to the direction given by the right-hand rule for positive charge.
The velocity of the sphere is downward, and the magnetic field is directed from the north pole to the south pole as shown in the diagram.
Using Fleming’s left-hand rule (or reversing the right-hand rule for a negative charge), the magnetic force is directed into the page.
✅ Answer: (D)
