Home / IB MYP 3 Mathematics Study Notes / IB MYP 3 Mathematics 9.8 Probability from Tables and Venn Diagrams Study Notes

IB MYP 3 Mathematics 9.8 Probability from Tables and Venn Diagrams Study Notes - New Syllabus

IB MYP 3 Mathematics 9.8 Probability from Tables and Venn Diagrams Study Notes

IB MYP 3 Mathematics 9.8 Probability from Tables and Venn Diagrams Study Notes at IITian Academy focus on specific topics and types of questions asked in the actual exam. Study Notes focus on the IB MYP 3 Mathematics syllabus with guiding questions of

Two-way table: A table that organises data using two categories, with one category represented by rows and the other by columns.
Cell: An individual entry in a two-way table showing the number of observations belonging to both the corresponding row and column categories.
Marginal totals: The totals along the edges of a two-way table showing the total number in each row or column.
Probability from a table: \(P(\text{event})=\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}\).
Both events: The intersection of two categories, found from the cell where their row and column meet.
Venn diagram: A representation of events using circles inside a rectangle representing the universal set.
Universal set: The complete group or collection of all possible outcomes being considered.
Overlap: The region common to two circles, representing outcomes where both events occur.
Only: A region belonging to one event but not the other, such as \(A\) only or \(B\) only.
Neither: The region outside both circles, representing outcomes where neither event occurs.
“A or B”: Includes all outcomes in \(A\), all outcomes in \(B\), and the overlap. If \(A\) and \(B\) overlap, the overlap is counted only once.
“A and B”: Refers only to the overlap of \(A\) and \(B\).
At least one: Means that an outcome belongs to \(A\), \(B\), or both.
Completing a Venn diagram: Find the overlap first, subtract it from each group total to find the “only” regions, then subtract all regions inside the circles from the total to find “neither”.
Checking totals: For a Venn diagram, \(\text{A only}+\text{Both}+\text{B only}+\text{Neither}=\text{Total}\). For a two-way table, row totals and column totals must agree with the grand total.
Key rule: Identify exactly which region or table cell the question describes, use the correct total as the denominator, and never count the overlap twice when finding “A or B”.

IB MYP 3 Mathematics – Study Notes – All Topics

9.8 – Probability from Tables and Venn Diagrams

Probability questions can involve more than one category or event. Two-way tables and Venn diagrams are useful ways to organise this information and calculate probabilities.

Both representations help us identify outcomes such as:

  • an event occurring
  • two events occurring together
  • an event occurring but not another event
  • at least one event occurring
  • neither event occurring

Two-Way Tables

A two-way table organises data using two categories. One category is placed in the rows and the other category is placed in the columns.

For example, suppose \(40\) students are asked whether they play football and whether they play basketball.

 BasketballNot BasketballTotal
Football12820
Not Football101020
Total221840

 Reading a Two-Way Table

Each cell gives the number of students belonging to both the row and column categories.

Example of interpreting a cell:
The value \(12\) means that \(12\) students play football and basketball.

The totals along the edges are called marginal totals. They tell us the total number in each row or column.

Finding Probability from a Two-Way Table

When a person is selected at random, the probability of an event is:

 Formula

\(P(\text{event})=\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}\)

From the table above:

There are \(20\) students who play football.

\(P(\text{Football})=\frac{20}{40}=\frac{1}{2}\)

There are \(22\) students who play basketball.

\(P(\text{Basketball})=\frac{22}{40}=\frac{11}{20}\)

Probability of Both Events

To find the probability that a student plays both football and basketball, use the cell where the two categories intersect.

From the table, \(12\) students play both sports.

\(P(\text{Football and Basketball})=\frac{12}{40}=\frac{3}{10}\)

 Venn Diagrams

A Venn diagram represents events using circles inside a rectangle representing the entire group or universal set.

For two events \(A\) and \(B\):

RegionMeaning
Inside A onlyA occurs but B does not.
Inside B onlyB occurs but A does not.
OverlapBoth A and B occur.
Outside both circlesNeither A nor B occurs.

Important Probability Language

WordsMeaning
A and BThe overlap of A and B.
A onlyA but not B.
B onlyB but not A.
A or BA, B, or both.
Neither A nor BOutside both circles.

Finding Probability from a Venn Diagram

The same basic probability rule applies:

\(P(\text{event})=\frac{\text{number in the required region(s)}}{\text{total number}}\)
The main skill is identifying which region or regions represent the event.

 Finding “A or B”

“A or B” means that A occurs, B occurs, or both occur. Therefore, include all regions inside either circle.

⚠️ Important:
When A and B overlap, the overlap must be counted only once.

If \(A\) has \(18\) students, \(B\) has \(14\) students, and \(7\) students belong to both:

\(n(A\text{ or }B)=18+14-7=25\)

If there are \(30\) students altogether:

\(P(A\text{ or }B)=\frac{25}{30}=\frac{5}{6}\)

Finding “Neither A nor B”

“Neither A nor B” means that the outcome is outside both circles.

If there are \(30\) students altogether and \(25\) are in A or B, then the number in neither group is:

\(30-25=5\)

Therefore:

\(P(\text{neither})=\frac{5}{30}=\frac{1}{6}\)

 Completing a Venn Diagram

When a question gives totals instead of every individual region, work from the overlap first, then find the “only” regions, and finally find the number outside both circles.

Useful method:

  1. Find the number in both groups.
  2. Subtract the overlap from each group total to find the “only” regions.
  3. Add all regions inside the circles.
  4. Subtract from the total to find the number outside both circles.
  5. Use the required region(s) to calculate the probability.

 Connecting Two-Way Tables and Venn Diagrams

A two-way table and a Venn diagram can represent the same information in different ways.

Two-Way TableVenn Diagram Region
A and BOverlap
A and not BA only
Not A and BB only
Not A and not BNeither

 Checking Your Table or Venn Diagram

A useful way to check your work is to make sure that all outcomes have been accounted for.

For a Venn diagram:

\(\text{A only}+\text{Both}+\text{B only}+\text{Neither}=\text{Total}\)

For a two-way table:

\(\text{Row totals and column totals must agree with the grand total}\)

 Common Mistakes

MistakeCorrect Approach
Using the total for a row when the question asks for “both”.Use the intersection cell or overlap.
Counting the overlap twice when finding “A or B”.Count the overlap only once.
Forgetting the students outside both circles.Remember that “neither” is represented outside both circles.
Using the wrong denominator.Use the total number of possible outcomes unless the question gives a different sample group.
Confusing “and” with “or”.“And” means the overlap; “or” includes all regions belonging to either event.

 MYP 3 Exam Tips

  • Always identify the total number of outcomes.
  • For a two-way table, carefully identify the correct row and column.
  • For a Venn diagram, identify whether the question refers to only, both, at least one, or neither.
  • The overlap represents both events.
  • “At least one” means everything inside either circle, including the overlap.
  • “Neither” means outside both circles.
  • Check that all regions add to the total before calculating the probability.
  • Give your final probability in a simplified fraction, decimal, or percentage as requested.

Example 1:

A school surveys \(50\) students about whether they play football and basketball.

 BasketballNot BasketballTotal
Football151025
Not Football81725
Total232750

Find the probability that a randomly selected student:

a) plays football

b) plays both football and basketball

c) plays football but not basketball

d) does not play either sport

e) plays football or basketball

▶️ Answer/Explanation

Answer

a) Plays football

There are \(25\) students who play football out of \(50\).

\(P(\text{Football})=\frac{25}{50}=\frac{1}{2}\)

Answer: \(\frac{1}{2}\)

b) Plays both football and basketball

The intersection of the two categories is \(15\).

\(P(\text{Football and Basketball})=\frac{15}{50}=\frac{3}{10}\)

Answer: \(\frac{3}{10}\)

c) Plays football but not basketball

Use the Football and Not Basketball cell: \(10\).

\(P(\text{Football but not Basketball})=\frac{10}{50}=\frac{1}{5}\)

Answer: \(\frac{1}{5}\)

d) Does not play either sport

This is the Not Football and Not Basketball cell: \(17\).

\(P(\text{neither})=\frac{17}{50}\)

Answer: \(\frac{17}{50}\)

e) Plays football or basketball

Count everyone who plays at least one of the two sports:

\(25+8=33\)

Therefore:

\(P(\text{Football or Basketball})=\frac{33}{50}\)

Answer: \(\frac{33}{50}\)

Example 2:

In a class of \(40\) students, \(24\) students study French, \(18\) students study Spanish, and \(10\) students study both languages.

a) Find the number of students who study French only.

b) Find the number of students who study Spanish only.

c) Find the number of students who study neither language.

d) Find the probability that a randomly selected student studies at least one of the two languages.

e) Find the probability that the student studies French but not Spanish.

▶️ Answer/Explanation

Answer

a) French only

The \(10\) students studying both languages are included in the total of \(24\) French students.

\(\text{French only}=24-10=14\)

Answer: \(14\) students

b) Spanish only

\(\text{Spanish only}=18-10=8\)

Answer: \(8\) students

c) Neither language

First find the number studying at least one language:

\(14+10+8=32\)

Therefore:

\(\text{Neither}=40-32=8\)

Answer: \(8\) students

d) Probability of at least one language

There are \(32\) students who study at least one language.

\(P(\text{at least one})=\frac{32}{40}=\frac{4}{5}\)

Answer: \(\frac{4}{5}\)

e) Probability of French but not Spanish

French only \(=14\).

\(P(\text{French only})=\frac{14}{40}=\frac{7}{20}\)

Answer: \(\frac{7}{20}\)

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