IB MYP Physics Mock Tests 3 – 2026 Edition
IB MYP Physics Mock Tests 3 – April/May 2026 Exam
IB MYP Physics Mock Tests 3: Prepare for the MYP exams with subject-specific Prediction questions, model answers. All topics covered.
Prepared by MYP teachers: Access our IB MYP Physics Mock Tests 3 Mock with model answer. Students: Practice with exam-style papers for MYP Exam
Question : Horses and Physics [11 marks]
Horses can perform work for farming activities. In the past, they were used to loosen the soil before planting. Physics can be used to explore the ways in which horses complete these tasks.
a Speed Calculation [2 marks]
A horse covers a distance of 3 km in 45 minutes. Calculate its speed in km per hour (km h⁻¹).
Calculation space:
Speed = Distance / Time = ___________ / ___________ = ___________ km h⁻¹
▶️Answer/Explanation
Correct answer: 4 km h⁻¹
- Convert time to hours: 45 minutes = 45 / 60 = 0.75 hours
- Distance = 3 km
- Speed = Distance / Time = 3 km / 0.75 h = 4 km h⁻¹
Key Concept:
Speed is calculated as distance divided by time. Consistent units (km for distance, hours for time) are crucial for correct calculations.
b Energy Formula [1 mark]
Power is the rate of transforming energy or the rate of doing work. Select the formula for energy transformed.
▶️Answer/Explanation
Correct answer: C. energy transformed = power × time
Key Concept:
Power is defined as the rate of energy transfer (Power = Energy / Time). Rearranging gives Energy = Power × Time.
c Complete the Table [2 marks]
The table below gives some data about two horses A and B. Calculate the missing values and complete the table. You should assume the value of g = 10 N kg⁻¹.
Calculation space:
Horse A: Weight = Mass × g = ___________ × ___________ = ___________ N
Horse B: Mass = Weight / g = ___________ / ___________ = ___________ kg
▶️Answer/Explanation
Correct answer:
- Horse A: Weight = Mass × g = 450 kg × 10 N kg⁻¹ = 4500 N
- Horse B: Mass = Weight / g = 5100 N / 10 N kg⁻¹ = 510 kg
Key Concept:
Weight is the force due to gravity (Weight = Mass × g). Mass is calculated as Weight / g. The gravitational field strength g is given as 10 N kg⁻¹.
d Energy Transformation [1 mark]
Select the correct terms to complete the energy transformation diagram for a horse that starts from rest at the bottom of a hill, runs up the hill, and then stops at the top of the hill.
▶️Answer/Explanation
Correct answer: Chemical to Kinetic to Gravitational Potential
Key Concept:
The horse uses chemical energy (from food) to produce kinetic energy (motion). As it climbs the hill, kinetic energy is converted to gravitational potential energy due to increased height.
e Power Calculation [3 marks]
The hill in part (d) is 12 m high. Horse B reaches the top of the hill in 5.50 s. Use information from part (c) and the formula sheet to calculate the minimum power required for horse B to reach this height. You should give your answer in kW.
Calculation space:
GPE = Mass × g × Height = ___________ × ___________ × ___________ = ___________ J
Power = Energy / Time = ___________ / ___________ = ___________ W
Power in kW = ___________ / 1000 = ___________ kW
▶️Answer/Explanation
Correct answer: 11 kW
- From part (c), Horse B’s mass = 510 kg
- GPE = Mass × g × Height = 510 kg × 10 N kg⁻¹ × 12 m = 61,200 J
- Power = Energy / Time = 61,200 J / 5.50 s ≈ 11,127.27 W
- Convert to kW: 11,127.27 W / 1000 = 11.127 kW ≈ 11 kW (to 2 significant figures)
Key Concept:
Power is the rate of energy transfer. Gravitational potential energy (GPE = mgh) is used to calculate the minimum energy required to lift the horse, and power is Energy / Time.
f Current Calculation [2 marks]
The power of some modern devices is given in horsepower (hp), where 1.0 hp is equivalent to 746 W. An example of such a device is an electric water pump. Calculate the current that would be needed by a water pump with a power of 2.0 hp operating at a voltage of 230 V.
Calculation space:
Power in W = Horsepower × 746 = ___________ × ___________ = ___________ W
Current = Power / Voltage = ___________ / ___________ = ___________ A
▶️Answer/Explanation
Correct answer: 6.5 A
- Convert horsepower to watts: 2.0 hp × 746 W/hp = 1492 W
- Power = Voltage × Current, so Current = Power / Voltage
- Current = 1492 W / 230 V ≈ 6.48696 A ≈ 6.5 A (to 2 significant figures)
Key Concept:
Electrical power is given by P = V × I. Converting units (hp to W) and rearranging the formula allows calculation of current.
Syllabus Reference
Forces and Energy
- Speed, motion graphs
- Work and power, efficiency
- Transfer and transformation of energy
- Gravity and gravitational fields
Electromagnetism
- Current, voltage, power
Assessment Criteria: A (Knowledge), C (Communication), D (Scientific Thinking)