Home / IB MYP 4-5 / IB MYP 4-5 Maths-Calculating network pathways- Study Notes

IB MYP 4-5 Maths-Calculating network pathways- Study Notes

IB MYP 4-5 Maths- Calculating network pathways- Study Notes - New Syllabus

IB MYP 4-5 Maths- Calculating network pathways – Study Notes

Extended

  • Calculating network pathways

IB MYP 4-5 Maths- Calculating network pathways – Study Notes – All topics

Calculating Network Pathways

Calculating Network Pathways

Network Pathways

A pathway in a network is a sequence of edges connecting nodes. Counting the number of possible pathways between two nodes helps in planning routes, communication systems, and transportation networks.

Key Concepts

  • Path: A sequence of edges connecting distinct nodes.
  • Trail: A path where edges are not repeated.
  • Walk: A sequence of nodes where repetition of nodes and edges is allowed.
  • Cycle: A closed path starting and ending at the same node without repeating an edge.
  • Network Pathways: The total number of possible paths between two nodes in a network.

How to Calculate Pathways

There are two main methods:

  1. Listing Method: List all possible paths manually (works for small networks).
  2. Adjacency Matrix Method:
    • Create a matrix showing direct connections between nodes (1 for connection, 0 for none).
    • Raise the matrix to a power \( n \) to find the number of paths of length \( n \).

Example:

A network has nodes A, B, and C. Connections: A-B, B-C, and A-C. How many different paths exist from A to C?

▶️ Answer/Explanation

Solution:

Connections: A → B → C, and A → C directly.

Total paths: 2 (A → C and A → B → C).

Example:

A network has 3 nodes (1, 2, 3) with edges: 1-2, 2-3, 1-3. Find the number of paths of length 2 from node 1 to node 3 using an adjacency matrix.

▶️ Answer/Explanation

Solution:

Adjacency Matrix \( A \):

\( A = \begin{bmatrix} 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 0 \end{bmatrix} \)

Compute \( A^2 \):

\( A^2 = \begin{bmatrix} 2 & 1 & 1 \\ 1 & 2 & 1 \\ 1 & 1 & 2 \end{bmatrix} \)

The entry (1, 3) in \( A^2 \) = 1 → There is 1 path of length 2 from node 1 to node 3.

Scroll to Top