IB MYP 4-5 Maths- Pythagoras’ theorem- Study Notes - New Syllabus
IB MYP 4-5 Maths- Pythagoras’ theorem – Study Notes
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- Pythagoras’ theorem
IB MYP 4-5 Maths- Pythagoras’ theorem – Study Notes – All topics
Pythagoras’ Theorem
Pythagoras’ Theorem
Pythagoras’ Theorem applies to right-angled triangles and states that:
“The square of the hypotenuse is equal to the sum of the squares of the other two sides.”
Formula: \( a^2 + b^2 = c^2 \)
- \( c \) = hypotenuse (longest side, opposite the 90° angle)
- \( a, b \) = other two sides (legs)
Important Properties and Notes:
- Only applies to right-angled triangles.
- The hypotenuse is always the longest side and opposite the right angle.
- The theorem can be used to:
- Find the length of a missing side.
- Check if a triangle is right-angled by verifying \( a^2 + b^2 = c^2 \).
- The converse of Pythagoras’ theorem: If \( a^2 + b^2 = c^2 \), then the triangle is right-angled.
- Extended to 3D: \( d = \sqrt{x^2 + y^2 + z^2} \) for the distance in 3D space.
Steps to Use Pythagoras’ Theorem:
- Check if the triangle is right-angled (or if given).
- Identify the hypotenuse (longest side).
- Apply the formula: \( a^2 + b^2 = c^2 \).
- Solve for the unknown side (take square root if needed).
Common Uses in Real Life:
- Finding the shortest distance between two points (straight line).
- Construction and architecture for ensuring right angles.
- Navigation and mapping (finding distances using coordinates).
Example :
A right-angled triangle has sides of 6 cm and 8 cm. Find the hypotenuse.
▶️ Answer/Explanation
\( c^2 = a^2 + b^2 = 6^2 + 8^2 = 36 + 64 = 100 \)
\( c = \sqrt{100} = \boxed{10 \text{ cm}} \)
Example :
The hypotenuse of a right-angled triangle is 13 cm, and one side is 5 cm. Find the other side.
▶️ Answer/Explanation
\( c^2 = a^2 + b^2 \)
\( 13^2 = 5^2 + b^2 \Rightarrow 169 = 25 + b^2 \Rightarrow b^2 = 144 \Rightarrow b = 12 \)
Answer: \( \boxed{12 \text{ cm}} \)
Example :
Check whether a triangle with sides 7 cm, 24 cm, and 25 cm is right-angled.
▶️ Answer/Explanation
Longest side = 25 cm, so check \( a^2 + b^2 = c^2 \):
\( 7^2 + 24^2 = 49 + 576 = 625 \)
\( c^2 = 25^2 = 625 \), so the triangle is right-angled.
Example :
A ladder 10 m long is leaning against a wall. The bottom of the ladder is 6 m away from the wall. Find how high the ladder reaches on the wall.
▶️ Answer/Explanation
\( c^2 = a^2 + b^2 \), where c = 10 m (ladder), a = 6 m (distance from wall).
\( 10^2 = 6^2 + h^2 \Rightarrow 100 = 36 + h^2 \Rightarrow h^2 = 64 \Rightarrow h = 8 \)
Answer: Ladder reaches \(\boxed{8 \text{ m}}\).
Example :
Find the diagonal of a cuboid with sides 4 cm, 3 cm, and 12 cm.
▶️ Answer/Explanation
Diagonal \( d = \sqrt{x^2 + y^2 + z^2} = \sqrt{4^2 + 3^2 + 12^2} = \sqrt{16 + 9 + 144} = \sqrt{169} = 13 \text{ cm}\).
Answer: \( \boxed{13 \text{ cm}} \).
Example:
The shape $ABCDEFGH$ is a cuboid.
$AB = 6\,\text{cm},\quad BG = 3\,\text{cm},\quad FG = 2\,\text{cm}$
$AF = 7\,\text{cm}$
Calculate the angle between $AF$ and the plane $ABCD$.
▶️ Answer/Explanation
Construct right triangle $\triangle AFC$:
$AF = 7\,\text{cm}$ (hypotenuse)
$FC = 3\,\text{cm}$ (perpendicular to base)
Let angle between $AF$ and base $ABCD$ be $x$
Using:
$
\sin x = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{FC}{AF} = \frac{3}{7}
$
$
\sin x \approx 0.428571
$
$
x = \sin^{-1}(0.428571) \approx \boxed{25.4^\circ}
\quad \text{(3 significant figures)}
$