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IB MYP 4-5 Maths- Quadratic functions- Study Notes

IB MYP 4-5 Maths- Quadratic functions - Study Notes - New Syllabus

IB MYP 4-5 Maths- Quadratic functions – Study Notes

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  • Quadratic functions

IB MYP 4-5 Maths- Quadratic functions – Study Notes – All topics

Quadratic Functions

Quadratic Functions

A quadratic function is a function of the form:

\( f(x) = ax^2 + bx + c \), where \( a, b, c \) are real numbers and \( a \neq 0 \).

Key Features of Quadratic Functions:

Graph Shape: A parabola (U-shaped curve).

Direction:

    • If \( a > 0 \), parabola opens upward.
    • If \( a < 0 \), parabola opens downward.

 

Axis of Symmetry: Vertical line \( x = -\frac{b}{2a} \).

Vertex (Turning Point): \(\text{Vertex: } \left( -\frac{b}{2a}, f\left(-\frac{b}{2a}\right) \right) \)

Y-intercept: \( (0, c) \).

X-intercepts (Roots): Solutions of \( ax^2 + bx + c = 0 \).

Forms of Quadratic Functions:

  • Standard Form: \( y = ax^2 + bx + c \)
  • Factorized Form: \( y = a(x – p)(x – q) \), where p and q are roots.
  • Vertex Form: \( y = a(x – h)^2 + k \), where (h, k) is the vertex.

Axis of Symmetry and Vertex Formula:

\( x = -\frac{b}{2a}, \quad y = f\left(-\frac{b}{2a}\right) \)

Nature of Roots (Discriminant):

\(\Delta = b^2 – 4ac \)

  • If \( \Delta > 0 \): Two distinct real roots.
  • If \( \Delta = 0 \): One real root (repeated).
  • If \( \Delta < 0 \): No real roots (complex roots).

Example :

For \( y = 2x^2 – 4x + 1 \), find the axis of symmetry and vertex.

▶️ Answer/Explanation

Axis of symmetry: \( x = -\frac{b}{2a} = -\frac{-4}{2 \cdot 2} = 1 \).

Vertex y-coordinate: \( y = 2(1)^2 – 4(1) + 1 = 2 – 4 + 1 = -1 \).

Vertex: (1, -1).

Example : 

Solve \( x^2 – 5x + 6 = 0 \).

▶️ Answer/Explanation

\( a = 1, b = -5, c = 6 \).

\( \Delta = b^2 – 4ac = (-5)^2 – 4(1)(6) = 25 – 24 = 1 \).

\( x = \frac{-b \pm \sqrt{\Delta}}{2a} = \frac{5 \pm 1}{2} \).

\( x = 3 \) or \( x = 2 \).

Example : 

A ball is thrown upward. Its height is given by \( h(t) = -5t^2 + 20t + 1 \), where t is time in seconds. Find the maximum height.

▶️ Answer/Explanation

Vertex formula: \( t = -\frac{b}{2a} = -\frac{20}{2(-5)} = 2 \) seconds.

Height: \( h(2) = -5(2)^2 + 20(2) + 1 = -20 + 40 + 1 = 21 \).

Maximum height: 21 meters at t = 2 s.

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