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IB MYP Integrated Science- Physics- Motion and motion graphs-Study Notes - New Syllabus

IB MYP Integrated Science- Physics – Motion and motion graphs -Study Notes – New syllabus

IB MYP Integrated Science- Physics – Motion and motion graphs -Study Notes -As per latest Syllabus.

Key Concepts:

 Motion and motion graphs

IB MYP Integrated Science -Concise Summary Notes- All Topics

Distance and Displacement

Distance is the total path length travelled by an object, regardless of direction.

Displacement is the shortest straight-line distance from the initial to the final position, including direction.

Key Concepts

  • Distance is a scalar quantity (only magnitude)
  • Displacement is a vector quantity (magnitude + direction)
  • Distance is always positive
  • Displacement can be positive, negative, or zero
  • Distance is always greater than or equal to displacement
  • If an object returns to its starting point:
    • Distance ≠ 0
    • Displacement = 0

Formula

\( \text{Displacement} = \text{Final Position} – \text{Initial Position} \)

Comparison of Distance and Displacement

FeatureDistanceDisplacement
TypeScalarVector
DirectionNoYes
ValueAlways positiveCan be +, −, or 0
PathActual pathShortest path

Example:

A student walks 5 m east and then 5 m west. Find distance and displacement.

▶️ Answer/Explanation

Total distance = \( 5 + 5 = 10 \, \text{m} \)

Final position = starting position → displacement = 0

Final Answer: \( \boxed{\text{Distance = 10 m, Displacement = 0}} \)

Example:

A car moves 20 m north. What are its distance and displacement?

▶️ Answer/Explanation

Distance = 20 m

Displacement = 20 m north (includes direction)

Final Answer: \( \boxed{\text{Distance = 20 m, Displacement = 20 m north}} \)

Speed and Velocity

Speed is the rate at which distance is covered.

Velocity is the rate of change of displacement, including direction.

Formula

\( \text{Speed} = \dfrac{\text{Distance}}{\text{Time}} \)

\( \text{Velocity} = \dfrac{\text{Displacement}}{\text{Time}} \)

Key Concepts

  • Speed is a scalar quantity
  • Velocity is a vector quantity
  • Speed has only magnitude, velocity has magnitude and direction
  • Speed is always positive
  • Velocity can be positive, negative, or zero
  • If direction changes, velocity changes even if speed remains constant

Average Speed and Velocity

\( \text{Average Speed} = \dfrac{\text{Total Distance}}{\text{Total Time}} \)

\( \text{Average Velocity} = \dfrac{\text{Total Displacement}}{\text{Total Time}} \)

Comparison of Speed and Velocity

FeatureSpeedVelocity
TypeScalarVector
DirectionNot includedIncluded
SignAlways positiveCan be + or −
Based onDistanceDisplacement

Example:

A car travels 100 m in 20 s. Find its speed.

▶️ Answer/Explanation

\( \text{Speed} = \dfrac{100}{20} = 5 \, \text{m/s} \)

Final Answer: \( \boxed{5 \, \text{m/s}} \)

Example:

A person walks 50 m east in 10 s. Find velocity.

▶️ Answer/Explanation

\( \text{Velocity} = \dfrac{50}{10} = 5 \, \text{m/s east} \)

Final Answer: \( \boxed{5 \, \text{m/s east}} \)

Acceleration

Acceleration is the rate of change of velocity with respect to time.

Formula

\( a = \dfrac{v – u}{t} \)

  • \( a \) = acceleration (m/s²)
  • \( v \) = final velocity
  • \( u \) = initial velocity
  • \( t \) = time (s)

Key Concepts

  • Acceleration is a vector quantity (has direction)
  • It occurs when:
    • Speed increases
    • Speed decreases (deceleration)
    • Direction changes
  • If velocity is constant → acceleration is zero
  • Negative acceleration is called deceleration

Types of Acceleration

  • Uniform acceleration → velocity changes at a constant rate
  • Non-uniform acceleration → velocity changes at varying rate

Example:

A car increases its velocity from 10 m/s to 30 m/s in 5 s. Find acceleration.

▶️ Answer/Explanation

\( a = \dfrac{30 – 10}{5} = \dfrac{20}{5} = 4 \, \text{m/s}^2 \)

Final Answer: \( \boxed{4 \, \text{m/s}^2} \)

Example:

A car slows down from 20 m/s to 10 m/s in 5 s. Find acceleration.

▶️ Answer/Explanation

\( a = \dfrac{10 – 20}{5} = \dfrac{-10}{5} = -2 \, \text{m/s}^2 \)

The negative sign shows deceleration.

Final Answer: \( \boxed{-2 \, \text{m/s}^2} \)

Motion Graphs (Distance-Time & Velocity-Time)

Distance–Time Graph

A distance–time graph shows how the distance travelled by an object changes with time.

Key Concepts

  • Time is plotted on the x-axis
  • Distance is plotted on the y-axis
  • The slope (gradient) of the graph represents speed

Formula (Gradient)

\( \text{Speed} = \dfrac{\text{Change in distance}}{\text{Time}} \)

Types of Distance–Time Graphs

  • Straight line (constant slope) → constant speed
  • Horizontal line → object at rest
  • Curved line → changing speed (acceleration)

Example:

A graph shows a straight line with constant slope. What does this indicate?

▶️ Answer/Explanation

A constant slope means constant speed.

Final Answer: \( \boxed{\text{Uniform motion (constant speed)}} \)

Example:

An object remains at the same position for some time. How will this appear on the graph?

▶️ Answer/Explanation

No change in distance means zero slope.

Final Answer: \( \boxed{\text{Horizontal line}} \)

Velocity–Time Graph

Definition

A velocity–time graph shows how velocity changes with time.

Key Concepts

  • Time is plotted on the x-axis
  • Velocity is plotted on the y-axis
  • The slope represents acceleration
  • The area under the graph represents displacement

Formulas

\( \text{Acceleration} = \dfrac{\text{Change in velocity}}{\text{Time}} \)

\( \text{Displacement} = \text{Area under graph} \)

Types of Velocity–Time Graphs

  • Straight sloping line → constant acceleration
  • Horizontal line → constant velocity
  • Downward slope → deceleration

Example:

A velocity–time graph is a straight line sloping upwards. What does this indicate?

▶️ Answer/Explanation

Slope represents acceleration.

Upward slope means velocity is increasing.

Final Answer: \( \boxed{\text{Uniform acceleration}} \)

Example:

An object moves at constant velocity. How will this appear on a velocity–time graph?

▶️ Answer/Explanation

Constant velocity means no change in velocity.

Slope = 0

Final Answer: \( \boxed{\text{Horizontal line}} \)

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