Home / IB MYP Practice Questions and Resources / 4-5 Chemistry – Carboxylic acids- Study Notes

IB MYP 4-5 Chemistry -Carboxylic acids- Study Notes - New Syllabus

IB MYP 4-5 Chemistry -Carboxylic acids- Study Notes

Key Concepts

  •  Carboxylic Acids (Structure, Properties, and Reactions)

IB MYP 4-5 Chemistry Study Notes – All topics

 Carboxylic Acids (Structure, Properties, and Reactions)

 Carboxylic Acids (Structure, Properties, and Reactions)

Carboxylic acids are organic compounds that contain the carboxyl functional group (–COOH). They are weak acids that partially ionize in water to release hydrogen ions (\( \mathrm{H^+} \)). Their general formula is \( \mathrm{C_{n}H_{2n+1}COOH} \).

 Structure and General Formula

  • Functional group: Carboxyl group (–COOH)
  • General formula: \( \mathrm{C_{n}H_{2n+1}COOH} \)
  • Homologous series: Carboxylic acids

Structural representation:

\( \mathrm{R–COOH} \), where R = alkyl group such as \( \mathrm{CH_3, C_2H_5, C_3H_7} \)

Examples:

  • Methanoic acid (formic acid): \( \mathrm{HCOOH} \)
  • Ethanoic acid (acetic acid): \( \mathrm{CH_3COOH} \)
  • Propanoic acid: \( \mathrm{C_2H_5COOH} \)

 Physical Properties

  • Colorless liquids (lower members) with sharp, pungent odor.
  • Soluble in water — due to hydrogen bonding with water molecules.
  • Boiling points increase with molecular mass (due to strong intermolecular hydrogen bonding).
  • Weakly acidic in nature (partially ionize in water).

Ionization in water:

\( \mathrm{CH_3COOH \rightleftharpoons CH_3COO^- + H^+} \)

Chemical Properties

  • (a) Reaction with Metals: React with active metals (like magnesium or zinc) to form a salt and hydrogen gas.

    \( \mathrm{2CH_3COOH + Mg \rightarrow (CH_3COO)_2Mg + H_2} \)

  • (b) Reaction with Bases (Neutralization): Form a salt and water when reacting with metal hydroxides.

    \( \mathrm{CH_3COOH + NaOH \rightarrow CH_3COONa + H_2O} \)

  • (c) Reaction with Carbonates / Bicarbonates: Produce a salt, water, and carbon dioxide.

    \( \mathrm{2CH_3COOH + Na_2CO_3 \rightarrow 2CH_3COONa + H_2O + CO_2} \)

  • (d) Oxidation: Alcohols can be oxidized to carboxylic acids using acidified potassium dichromate.

    \( \mathrm{CH_3CH_2OH \xrightarrow{[O]} CH_3COOH + H_2O} \)

  • (e) Esterification: React with alcohols in the presence of concentrated \( \mathrm{H_2SO_4} \) to form esters and water.

    \( \mathrm{CH_3COOH + C_2H_5OH \xrightarrow{conc.\ H_2SO_4} CH_3COOC_2H_5 + H_2O} \)

 Functional Group: –COOH (Carboxyl Group)

  • Contains both a carbonyl (C=O) and a hydroxyl (–OH) group bonded to the same carbon atom.
  • This combination allows it to release \( \mathrm{H^+} \), giving acidic properties.
  • Carboxylic acids form hydrogen bonds easily — leading to high boiling points and solubility.

 Uses of Carboxylic Acids

  • Ethanoic acid is used in vinegar (about 4–8% solution).
  • Used in making esters, plastics, and perfumes.
  • Used in food preservation and as a cleaning agent.
  • Higher acids are used in soap and detergent manufacture.

 Comparison: Alcohols vs. Carboxylic Acids

PropertyAlcoholsCarboxylic Acids
Functional Group–OH (Hydroxyl)–COOH (Carboxyl)
NatureNeutralAcidic (weak acid)
Reaction with MetalsSlow or no reactionProduces hydrogen gas
Ester FormationReact with acidsReact with alcohols

Example 

Write the chemical equation for the neutralization of ethanoic acid with sodium hydroxide.

▶️ Answer / Explanation

Step 1: Ethanoic acid reacts with NaOH to form sodium ethanoate and water.

Step 2: \( \mathrm{CH_3COOH + NaOH \rightarrow CH_3COONa + H_2O} \)

Final Answer: Sodium ethanoate and water are formed in the neutralization reaction.

Example 

Describe a chemical test to distinguish between ethanol and ethanoic acid.

▶️ Answer / Explanation

Step 1: Add sodium carbonate (\( \mathrm{Na_2CO_3} \)) to both samples.

Step 2: Effervescence (bubbling) indicates the release of \( \mathrm{CO_2} \) gas with ethanoic acid.

Step 3: No gas is produced with ethanol.

Final Answer: Effervescence occurs only with ethanoic acid, confirming its acidic nature.

Example 

Calculate the volume of carbon dioxide produced when 10 g of ethanoic acid reacts completely with sodium carbonate.

▶️ Answer / Explanation

Step 1: Equation: \( \mathrm{2CH_3COOH + Na_2CO_3 \rightarrow 2CH_3COONa + H_2O + CO_2} \)

Step 2: Molar mass of \( \mathrm{CH_3COOH} = 60\ g/mol \)

Step 3: \( \mathrm{10\ g\ CH_3COOH = \dfrac{10}{60} = 0.1667\ mol} \)

Step 4: 2 mol acid → 1 mol \( \mathrm{CO_2} \), so \( 0.1667\ mol \) acid → \( 0.0833\ mol\ CO_2 \)

Step 5: Volume at STP = \( \mathrm{0.0833 \times 22.4 = 1.87\ L} \)

Final Answer: \( \mathrm{1.87\ L} \) of \( \mathrm{CO_2} \) is produced.

Scroll to Top