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IB MYP 4-5 Chemistry -Formation of ions and ionic lattices- Study Notes - New Syllabus

IB MYP 4-5 Chemistry -Formation of ions and ionic lattices- Study Notes

Key Concepts

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IB MYP 4-5 Chemistry Study Notes – All topics

Formation of Ions and Ionic Lattices

When atoms lose or gain electrons to achieve a stable outer electron configuration (usually a full valence shell), they form ions. The electrostatic attraction between oppositely charged ions results in the formation of ionic compounds arranged in a repeating ionic lattice structure.

Formation of Ions

 An ion is a charged particle formed when an atom loses or gains electrons.

  • Cation: A positively charged ion formed by losing electrons.
  • Anion: A negatively charged ion formed by gaining electrons.

Why Atoms Form Ions:

  • To achieve a stable electron configuration (like noble gases).
  • To minimize potential energy and become more stable.

Examples of Ion Formation:

AtomElectron ChangeIon FormedType of Ion
\( \mathrm{Na} \) (2,8,1)Loses 1 e⁻\( \mathrm{Na^+} \)Cation
\( \mathrm{Cl} \) (2,8,7)Gains 1 e⁻\( \mathrm{Cl^-} \)Anion
\( \mathrm{Mg} \) (2,8,2)Loses 2 e⁻\( \mathrm{Mg^{2+}} \)Cation

Equation Example:

\( \mathrm{Na \rightarrow Na^+ + e^-} \)

\( \mathrm{Cl + e^- \rightarrow Cl^-} \)

\( \mathrm{Na^+ + Cl^- \rightarrow NaCl} \)

 Formation of Ionic Compounds

Ionic compounds form through electrostatic attraction between positive and negative ions. This attraction is known as an ionic bond.

Steps in Ionic Compound Formation:

  1. Metal atom loses electrons → forms cation.
  2. Non-metal atom gains those electrons → forms anion.
  3. Oppositely charged ions attract → form neutral compound.

Example – Formation of Magnesium Chloride (\( \mathrm{MgCl_2} \)):

  • \( \mathrm{Mg} \) loses two electrons → \( \mathrm{Mg^{2+}} \).
  • Each \( \mathrm{Cl} \) gains one electron → \( \mathrm{Cl^-} \).
  • Two chloride ions are needed to balance charge: \( \mathrm{Mg^{2+} + 2Cl^- \rightarrow MgCl_2} \).

Properties of Ionic Compounds:

  • High melting and boiling points (strong ionic bonds).
  • Solid at room temperature.
  • Conduct electricity when molten or dissolved (ions move freely).
  • Usually soluble in water.
  • Form crystalline solids.

Ionic Lattice Structure

An ionic lattice is a giant 3D structure formed by the regular repeating arrangement of positive and negative ions held together by strong electrostatic forces.

Key Features:

  • Each ion is surrounded by oppositely charged ions in a fixed pattern.
  • Forces act in all directions — giving ionic solids strength and stability.
  • Example: In sodium chloride, each \( \mathrm{Na^+} \) is surrounded by 6 \( \mathrm{Cl^-} \) ions and vice versa (6:6 coordination).

Diagram Description (MYP-level): Imagine a cube-like 3D arrangement where \( \mathrm{Na^+} \) and \( \mathrm{Cl^-} \) alternate in all directions. The repeating pattern forms a crystal lattice — strong, symmetrical, and stable.

Properties Due to Ionic Lattice:

  • High melting/boiling points: Large energy needed to overcome strong electrostatic attractions.
  • Brittle: When like charges align during stress, they repel and the lattice breaks.
  • Electrical conductivity: Only when ions are free to move (molten/solution state).

Formation and Properties of Ionic Compounds

FeatureDescriptionReason/Explanation
Bond TypeIonic (electrostatic attraction)Between oppositely charged ions
StructureGiant 3D latticeRepeating ion arrangement with strong forces
Melting PointHighStrong ionic bonds require much energy to break
ConductivityOnly when molten or aqueousIons free to move and carry charge
BrittlenessBrittle under forceLike charges align and repel when lattice shifts

Example:

Write the electronic structures of sodium and chlorine, and show how they form ions in sodium chloride.

▶️ Answer / Explanation

Sodium: 2,8,1 → loses 1 electron → \( \mathrm{Na^+} \) (2,8).

Chlorine: 2,8,7 → gains 1 electron → \( \mathrm{Cl^-} \) (2,8,8).

Result: \( \mathrm{Na^+Cl^-} \) held by electrostatic attraction → \( \mathrm{NaCl} \).

Example :

Explain why magnesium oxide (\( \mathrm{MgO} \)) has a higher melting point than sodium chloride (\( \mathrm{NaCl} \)).

▶️ Answer / Explanation

Step 1: \( \mathrm{MgO} \) has ions with charges \( \mathrm{Mg^{2+}} \) and \( \mathrm{O^{2-}} \).

Step 2: \( \mathrm{NaCl} \) has ions with charges \( \mathrm{Na^+} \) and \( \mathrm{Cl^-}} \).

Step 3: Stronger electrostatic forces exist between ions with higher charges.

Final Answer: \( \mathrm{MgO} \) has a higher melting point because its ionic bonds are stronger than those in \( \mathrm{NaCl} \).

Example :

Explain why ionic compounds conduct electricity when molten but not when solid, using the concept of the ionic lattice.

▶️ Answer / Explanation

Step 1: In solid state, ions are fixed in a lattice → cannot move.

Step 2: When molten, the lattice breaks and ions become mobile.

Step 3: Moving ions carry electric current.

Final Answer: Ionic solids do not conduct because ions are immobile; conductivity occurs when molten or dissolved due to free ion movement.

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