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IB MYP 4-5 Physics- Astronomical telescope and its Ray diagrams- Study Notes

IB MYP 4-5 Physics- Astronomical telescope and its Ray diagrams- Study Notes - New Syllabus

IB MYP 4-5 Physics-Astronomical telescope and its Ray diagrams- Study Notes

Key Concepts

  • Astronomical telescope and its Ray diagrams

IB MYP 4-5 Physics Study Notes – All topics

Astronomical Telescope

Astronomical Telescope

An astronomical telescope is an optical instrument used to observe distant celestial objects such as stars, planets, and galaxies.It produces a magnified image of a distant object using two lenses: the objective and the eyepiece.

Components:

  • Objective lens: Large convex lens; forms a real, inverted image of a distant object.
  • Eyepiece lens: Convex lens; acts as a magnifier to produce a virtual image.
  • Tube: Holds lenses in position and prevents external light interference.

Working Principle:

  • The objective lens collects light from a distant object and forms a real, inverted image at its focal plane.
  • The eyepiece lens magnifies this image to produce a virtual, magnified image that can be viewed by the eye.
  • Used for astronomical observation, so the final image is usually inverted (not a problem for stars and planets).

Ray Diagram of an Astronomical Telescope (Normal Adjustment):

  • In normal adjustment, the final image is at infinity, making it easier for the relaxed human eye to view.
  • Diagram explanation:
    • Parallel rays from a distant object pass through the objective lens and converge at its focal point F₀, forming a real image.
    • The eyepiece lens is positioned such that its focal point Fₑ coincides with F₀ of the objective.
    • Rays emerging from the eyepiece are parallel, producing a virtual image at infinity.

Magnification of an Astronomical Telescope:

Angular magnification \( M \) is given by:

\( M = \dfrac{\text{Focal length of objective}}{\text{Focal length of eyepiece}} = \dfrac{f_o}{f_e} \)

  • It shows how much larger the telescope makes the observed object appear compared to the naked eye.

Key Points:

  • Used for observing distant stars, planets, and moons.
  • The image is inverted, but for astronomy this usually does not matter.
  • Can be adjusted to normal vision (final image at infinity) or for near vision (final image at finite distance).

Example:

An astronomical telescope has an objective lens with focal length 120 cm and an eyepiece lens with focal length 10 cm. Calculate the angular magnification of the telescope in normal adjustment.

▶️ Answer/Explanation

Step 1: Use the formula for angular magnification:

\( M = \dfrac{f_o}{f_e} \)

Step 2: Substitute the values:

\( M = \dfrac{120}{10} = 12 \)

\(\boxed{M = 12}\)

Example:

A distant star is observed through an astronomical telescope. If the focal length of the objective lens is 100 cm and the focal length of the eyepiece is 5 cm, what is the magnification? If the eyepiece is replaced with one of focal length 10 cm, how does the magnification change?

▶️ Answer/Explanation

Step 1: Original magnification:

\( M_1 = \dfrac{f_o}{f_e} = \dfrac{100}{5} = 20 \)

Step 2: With new eyepiece:

\( M_2 = \dfrac{f_o}{f_e} = \dfrac{100}{10} = 10 \)

Step 3: Conclusion: Replacing the eyepiece with a longer focal length lens **reduces the magnification**.

\(\boxed{M_1 = 20, \ M_2 = 10}\)

Example:

An astronomical telescope is used to observe a planet. The focal length of the objective is 150 cm and that of the eyepiece is 15 cm. Draw the ray diagram for the telescope in normal adjustment and determine its magnification.

▶️ Answer/Explanation

Step 1: Draw the ray diagram:

Parallel rays from the planet enter the objective lens and converge at its focal point.

Eyepiece lens is positioned so that its focal point coincides with the objective’s image.

Rays emerge parallel from the eyepiece, forming a magnified virtual image at infinity.

Step 2: Calculate angular magnification:

\( M = \dfrac{f_o}{f_e} = \dfrac{150}{15} = 10 \)

\(\boxed{M = 10}\)

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