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IB MYP 4-5 Physics- Current in a simple circuit- Study Notes

IB MYP 4-5 Physics- Current in a simple circuit- Study Notes - New Syllabus

IB MYP 4-5 Physics-Current in a simple circuit- Study Notes

Key Concepts

  • Current in a simple circuit

IB MYP 4-5 Physics Study Notes – All topics

Current in a Simple Circuit

Current in a Simple Circuit

An electric circuit is a closed loop that allows charges (usually electrons) to flow. The rate of flow of electric charge is called electric current.

 

  • Electric current (\( I \)) is defined as the rate of flow of charge.
  • It flows from the positive terminal of the power source to the negative terminal (conventional current direction).
  • In metals, the actual moving charges are electrons, which flow in the opposite direction to conventional current.

Formula for current:

\( I = \dfrac{Q}{t} \)

where:

  • \( I \) = current (A, amperes) 
  • \( Q \) = charge (C, coulombs) 
  • \( t \) = time (s)

Key Points in a Simple Circuit

  • A circuit must be closed (complete path) for current to flow.
  • A power source (e.g., cell, battery) provides the potential difference that drives charges.
  • Resistors, lamps, or other components use electrical energy.
  • An ammeter is connected in series to measure current.
  • In a series circuit, current is the same at all points.

Example:

A total charge of \( 12 \, C \) passes through a wire in \( 4 \, s \). What is the current in the wire?

▶️ Answer/Explanation

Using \( I = \dfrac{Q}{t} \):

\( I = \dfrac{12}{4} = 3.0 \, A \).

Final Answer: \( \boxed{3.0 \, A} \).

Example: 

A current of \( 0.5 \, A \) flows for \( 10 \, s \). How many electrons pass through the circuit? (Charge of electron: \( e = 1.6 \times 10^{-19} \, C \)).

▶️ Answer/Explanation

Step 1: Total charge moved \( Q = I t = 0.5 \times 10 = 5.0 \, C \).

Step 2: Number of electrons \( N = \dfrac{Q}{e} = \dfrac{5.0}{1.6 \times 10^{-19}} \).

\( N = 3.1 \times 10^{19} \) electrons.

Final Answer: \( \boxed{3.1 \times 10^{19} \, \text{electrons}} \).

Example: 

A series circuit consists of a \( 9.0 \, V \) battery and two resistors. An ammeter reads \( 0.3 \, A \) near the battery. What is the current through each resistor?

▶️ Answer/Explanation

In a series circuit, current is the same at all points. Therefore, each resistor has a current of \( 0.3 \, A \).

Final Answer: \( \boxed{0.3 \, A \, \text{through each resistor}} \).

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