IB MYP 4-5 Physics- Electric motors - Study Notes - New Syllabus
IB MYP 4-5 Physics-Electric motors – Study Notes
Key Concepts
- Electric motors
 
Electric Motors
Electric Motors
- An electric motor is a device that converts electrical energy into mechanical energy (rotation or motion).
 - It works on the principle that a current-carrying conductor placed in a magnetic field experiences a force.
 
![]()
Principle (Motor Effect)
A conductor carrying current in a magnetic field experiences a force given by:
 ![]()
\(F = B \, I \, L \, \sin\theta\)
- \(F\) = force on conductor
 - \(B\) = magnetic field strength
 - \(I\) = current in conductor
 - \(L\) = length of conductor in field
 - \(\theta\) = angle between conductor and field
 
This force is due to the interaction between the magnetic field of the conductor and the external magnetic field.
Construction of a Simple DC Motor
![]()
- Armature (coil): A rectangular coil of wire through which current flows.
 - Magnet: Provides a uniform magnetic field (between north and south poles).
 - Commutator (split-ring): Reverses the current every half turn to keep the coil rotating in the same direction.
 - Brushes: Provide electrical contact between the power supply and the rotating coil.
 
Working of a DC Motor
- When current flows through the coil → forces act on the two sides of the coil (one up, one down).
 - This creates a turning effect (torque) on the coil, causing it to rotate.
 - The commutator reverses current every half turn → ensures continuous rotation in the same direction.
 
Factors Affecting the Strength of Motor
- Strength of magnetic field (\(B\))
 - Current in the coil (\(I\))
 - Number of turns in the coil
 - Area of the coil (\(A\))
 
Applications of Electric Motors
- Electric fans and mixers
 - Electric cars and trains
 - Industrial machines
 - Robotics
 
Example:
A wire of length 0.2 m carrying 5 A of current is placed perpendicular to a 0.3 T magnetic field. Find the force acting on the wire.
▶️ Answer/Explanation
Step 1: Use the formula \(F = BIL\sin\theta\).
Step 2: \(B = 0.3 \,T\), \(I = 5 \,A\), \(L = 0.2 \,m\), \(\theta = 90^\circ\).
Step 3: \(F = 0.3 \times 5 \times 0.2 \times \sin 90^\circ = 0.3 \, N\).
Final Answer: \(\boxed{0.3 \, N}\)
Example
Explain why a split-ring commutator is necessary in a DC motor.
▶️ Answer/Explanation
Step 1: Without a commutator, the current direction in the coil would remain constant.
Step 2: After half a turn, the forces would reverse → the coil would oscillate instead of rotating continuously.
Final Answer: The commutator reverses current every half turn, ensuring continuous rotation in one direction.
Example:
List two ways to increase the turning effect in an electric motor.
▶️ Answer/Explanation
Step 1: Increase the strength of magnetic field (\(B\)).
Step 2: Increase the current (\(I\)) supplied to the coil.
Step 3: Increase the number of turns in the coil or its area.
Final Answer: Use a stronger magnet and higher current (or larger/more turns coil) to increase torque.
