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IB MYP 4-5 Physics- Lenses- Study Notes

IB MYP 4-5 Physics- Lenses- Study Notes - New Syllabus

IB MYP 4-5 Physics-Lenses- Study Notes

Key Concepts

  • Lenses

IB MYP 4-5 Physics Study Notes – All topics

Lenses

Lenses

A lens is a transparent piece of glass or plastic that refracts light rays to form an image.

Types of Lenses:

    • Convex Lens (Converging Lens): Thicker at the center than at the edges. It brings parallel rays of light together (converges them) to a point called the principal focus.
    • Concave Lens (Diverging Lens): Thinner at the center than at the edges. It spreads parallel rays of light outward (diverges them) as if they are coming from a point called the principal focus.

Key Terms:

    • Principal Axis: A straight line passing through the optical center and the centers of curvature of the lens surfaces.
    • Optical Center (O): A point on the lens through which light passes without deviation.
    • Principal Focus (F): The point where parallel rays of light either converge (convex lens) or appear to diverge from (concave lens).
    • Focal Length (f): The distance between the optical center and the principal focus.

Lens Formula:

\(\dfrac{1}{f} = \dfrac{1}{v} – \dfrac{1}{u}\)

where \(f\) = focal length, \(v\) = image distance, \(u\) = object distance (sign convention applied).

Magnification (M):

\( M =- \dfrac{\text{Image height}}{\text{Object height}} =- \dfrac{v}{u} \)

Ray Diagrams for Lenses:

For converging lenses:

  • A ray parallel to the principal axis passes through the focal point after refraction.
    •   
  • A ray passing through the center of the lens continues in a straight line.
  • A ray through the focal point emerges parallel to the axis.

For concave lenses:

    • Parallel ray → appears to diverge from the focus.
    • Ray through optical center → passes undeviated.

Applications of Lenses:

    • Convex lenses: magnifying glasses, cameras, microscopes, human eye.
    • Concave lenses: spectacles for short-sightedness, peepholes in doors.

Example:

An object is placed 30 cm from a convex lens of focal length 15 cm. Find the image distance and state the nature of the image.

▶️ Answer/Explanation

Lens formula: \(\dfrac{1}{f} = \dfrac{1}{v} – \dfrac{1}{u}\) \(\dfrac{1}{15} = \dfrac{1}{v} – \dfrac{1}{(-30)}\)

\(\dfrac{1}{15} = \dfrac{1}{v} + \dfrac{1}{30}\) \(\dfrac{1}{v} = \dfrac{1}{15} – \dfrac{1}{30} = \dfrac{1}{30}\) \( v = 30 \, \text{cm} \).

Example:

An object is placed 20 cm from a concave lens of focal length 15 cm. Find the image distance.

▶️ Answer/Explanation

Lens formula: \(\dfrac{1}{f} = \dfrac{1}{v} – \dfrac{1}{u}\) Here, \(f = -15 \, \text{cm}, \, u = -20 \, \text{cm}\). \(\dfrac{1}{-15} = \dfrac{1}{v} – \dfrac{1}{-20}\) \(\dfrac{1}{-15} = \dfrac{1}{v} + \dfrac{1}{20}\) \(\dfrac{1}{v} = -\dfrac{1}{15} – \dfrac{1}{20} = -\dfrac{7}{60}\) \( v = -8.57 \, \text{cm} \).
The image is virtual, upright, and smaller.
Final Answer: \(\boxed{v = -8.6 \, \text{cm}, \, \text{Virtual, Upright, Diminished}}\)

Example:

A magnifying glass is a convex lens of focal length 10 cm. An object is placed 6 cm from the lens. Calculate the magnification.

▶️ Answer/Explanation

Lens formula: \(\dfrac{1}{f} = \dfrac{1}{v} – \dfrac{1}{u}\) \(\dfrac{1}{10} = \dfrac{1}{v} – \dfrac{1}{(-6)}\) \(\dfrac{1}{10} = \dfrac{1}{v} + \dfrac{1}{6}\) \(\dfrac{1}{v} = \dfrac{1}{10} – \dfrac{1}{6} = -\dfrac{2}{15}\) \( v = -7.5 \, \text{cm} \).
Magnification: \( M = \dfrac{v}{u} = \dfrac{-7.5}{-6} = 1.25 \).
Final Answer: \(\boxed{M = 1.25, \, \text{Virtual, Upright, Enlarged}}

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