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IB MYP 4-5 Physics- Light rays and ray diagrams- Study Notes

IB MYP 4-5 Physics- Light rays and ray diagrams- Study Notes - New Syllabus

IB MYP 4-5 Physics- Light rays and ray diagrams- Study Notes

Key Concepts

  • Light rays and ray diagrams

IB MYP 4-5 Physics Study Notes – All topics

Light rays and ray diagrams

Light Rays

  • Light travels in straight lines in a uniform medium (e.g., air, vacuum).
  • A ray of light is represented by a straight line with an arrow showing the direction of light propagation.
  • Rays are used in diagrams to represent how light travels, reflects, or refracts.
  • Types of rays include:
  •  
    • Incident ray: The incoming ray that strikes a surface.
    • Reflected ray: The ray that bounces off a reflective surface.
    • Refracted ray: The ray that bends when passing into a different medium.
    • Emergent ray: The ray leaving after passing through a medium.
  • Light rays are often used to locate images in mirrors and lenses using ray diagrams.

Ray Diagrams

  • Ray diagrams are graphical methods to show the path of light rays as they interact with optical elements.
  • They help in predicting image position, size, orientation, and nature (real or virtual).
  • Common applications:

Plane Mirrors

A plane mirror is a flat reflecting surface.

  • The image formed is:
    • Virtual (cannot be formed on a screen)
    • Same size as the object
    • Laterally inverted (left appears right, right appears left)
    • Same distance behind the mirror as the object is in front

Concave Mirrors

A concave mirror is a spherical mirror with its reflecting surface curved inward.

  • It can form real or virtual images depending on the object’s position.
  • Important positions:
    • Object beyond center of curvature (\(C\)): Real, inverted, diminished image between \(C\) and focus (\(F\)).
    • Object at \(C\): Real, inverted, same size at \(C\).
    • Object between \(C\) and \(F\): Real, inverted, magnified image beyond \(C\).
    • Object at \(F\): Image at infinity (no clear image).
    • Object between \(F\) and mirror: Virtual, upright, magnified image behind the mirror.

Mirror formula: \(\dfrac{1}{f} = \dfrac{1}{u} + \dfrac{1}{v}\)

  • \(f\) = focal length
  • \(u\) = object distance
  • \(v\) = image distance

Convex Mirrors

A convex mirror is a spherical mirror with its reflecting surface curved outward.

    • It always forms:
      • Virtual image
      • Upright image
      • Diminished image
      • Located behind the mirror
    • Uses: Vehicle rear-view mirrors (give a wider field of view).

Sign Convention:

Rules for Drawing Ray Diagrams (Lenses/Mirrors)

  • For converging lenses:
    • A ray parallel to the principal axis passes through the focal point after refraction.
    •   
    • A ray passing through the center of the lens continues in a straight line.
    • A ray through the focal point emerges parallel to the axis.
  • For concave/convex mirrors:
    • Use the same rules with reflection instead of refraction.

Example:

An object is placed 10 cm in front of a plane mirror. Where will the image be formed, and what are its properties?

▶️ Answer/Explanation

The image is formed 10 cm behind the mirror, upright, virtual, laterally inverted, and the same size as the object.

Example:

A concave mirror has a focal length of 15 cm. An object is placed 30 cm from the mirror. Use ray diagrams to describe the image formed.

▶️ Answer/Explanation

Since the object is at \(2f\) (twice the focal length), the image is real, inverted, the same size as the object, and formed at \(2f\) on the other side.

Example:

A convex lens with focal length 20 cm is used. An object is placed 40 cm from the lens. Determine the image position and its properties using a ray diagram.

▶️ Answer/Explanation

Object at \(2f\). The image is real, inverted, same size as the object, and located at \(2f\) on the other side of the lens.

Example:

A boy stands 2 m in front of a plane mirror. Where will his image be formed, and what are its properties?

▶️ Answer/Explanation

In a plane mirror, the image is formed the same distance behind the mirror as the object is in front.

Image distance = 2 m behind mirror

Properties: Virtual, upright, laterally inverted, same size.

Final Answer: Image at \(\boxed{2 \,\text{m behind the mirror}}\)

Example:

An object is placed 30 cm in front of a concave mirror of focal length 15 cm. Find the position and nature of the image.

▶️ Answer/Explanation

Using mirror formula:

\(\dfrac{1}{f} = \dfrac{1}{u} + \dfrac{1}{v}\)

\(\dfrac{1}{15} = \dfrac{1}{30} + \dfrac{1}{v}\)

\(\dfrac{1}{v} = \dfrac{1}{15} – \dfrac{1}{30} = \dfrac{2-1}{30} = \dfrac{1}{30}\)

So, \(v = 30 \, \text{cm}\).

Image formed: At 30 cm in front of mirror (same as object), real, inverted, same size (since object at \(2f\)).

Final Answer: \(\boxed{\text{Real, inverted, same size, at 30 cm}}\)

Example:

A shopkeeper uses a convex mirror of focal length 20 cm. An object is placed 40 cm in front of the mirror. Find the image position.

▶️ Answer/Explanation

Mirror formula: \(\dfrac{1}{f} = \dfrac{1}{u} + \dfrac{1}{v}\)

Here \(f = +20\) cm (convex), \(u = -40\) cm (object in front).

\(\dfrac{1}{20} = \dfrac{1}{-40} + \dfrac{1}{v}\)

\(\dfrac{1}{v} = \dfrac{1}{20} + \dfrac{1}{40} = \dfrac{3}{40}\)

\(v \approx 13.3 \, \text{cm}\) (positive, behind the mirror).

So the image is virtual, upright, diminished, behind the mirror.

Final Answer: \(\boxed{\text{Virtual, upright, diminished, at 13.3 cm behind mirror}}\)

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