IB MYP 4-5 Physics- Mass and acceleration- Study Notes - New Syllabus
IB MYP 4-5 Physics-Mass and acceleration- Study Notes
Key Concepts
- Mass and acceleration
 
Mass and Acceleration
Concept of Mass:
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- Mass is a measure of the amount of matter in an object.
 - It is a scalar quantity, meaning it has magnitude only.
 - SI unit: kilogram (kg).
 - Mass remains constant regardless of location (unlike weight).
 
Concept of Acceleration:
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- Acceleration is the rate of change of velocity with respect to time.
 - It is a vector quantity, meaning it has both magnitude and direction.
 - SI unit: \( \text{m/s}^2 \).
 - Formula:
\( a = \dfrac{\Delta v}{\Delta t} \)
 
Relationship Between Mass and Acceleration:
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- According to Newton’s Second Law of Motion:
\( F = m \times a \)
 - For a constant force, acceleration is inversely proportional to mass:
\( a \propto \dfrac{1}{m} \)
 - For a given mass, acceleration is directly proportional to the applied force.
 
Key Notes:
- A larger mass will experience less acceleration for the same applied force.
 - Smaller mass objects accelerate more under the same force.
 - This relationship is crucial in vehicle design, spacecraft motion, and sports science.
 
Example:
A force of \( 20 \ \text{N} \) is applied to a mass of \( 4 \ \text{kg} \). Calculate the acceleration.
▶️ Answer/Explanation
From Newton’s Second Law:
\( F = m \times a \)
Rearranging for \( a \):
\( a = \dfrac{F}{m} = \dfrac{20}{4} = 5 \ \text{m/s}^2 \)
Final Answer: \( \boxed{5 \ \text{m/s}^2} \)
Example:
A \( 1500 \ \text{kg} \) car accelerates at \( 3 \ \text{m/s}^2 \). Calculate the net force acting on the car.
▶️ Answer/Explanation
From Newton’s Second Law:
\( F = m \times a = 1500 \times 3 = 4500 \ \text{N} \)
Final Answer: \( \boxed{4500 \ \text{N}} \)
