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IB MYP 4-5 Physics- Mass and acceleration- Study Notes

IB MYP 4-5 Physics- Mass and acceleration- Study Notes - New Syllabus

IB MYP 4-5 Physics-Mass and acceleration- Study Notes

Key Concepts

  • Mass and acceleration

IB MYP 4-5 Physics Study Notes – All topics

Mass and Acceleration

Concept of Mass:

  

  • Mass is a measure of the amount of matter in an object.
  • It is a scalar quantity, meaning it has magnitude only.
  • SI unit: kilogram (kg).
  • Mass remains constant regardless of location (unlike weight).

Concept of Acceleration:

  • Acceleration is the rate of change of velocity with respect to time.
  • It is a vector quantity, meaning it has both magnitude and direction.
  • SI unit: \( \text{m/s}^2 \).
  • Formula:

    \( a = \dfrac{\Delta v}{\Delta t} \)

Relationship Between Mass and Acceleration:

  • According to Newton’s Second Law of Motion:

    \( F = m \times a \)

  • For a constant force, acceleration is inversely proportional to mass:

    \( a \propto \dfrac{1}{m} \)

  • For a given mass, acceleration is directly proportional to the applied force.

Key Notes:

  • A larger mass will experience less acceleration for the same applied force.
  • Smaller mass objects accelerate more under the same force.
  • This relationship is crucial in vehicle design, spacecraft motion, and sports science.

Example:

A force of \( 20 \ \text{N} \) is applied to a mass of \( 4 \ \text{kg} \). Calculate the acceleration.

▶️ Answer/Explanation

From Newton’s Second Law:

\( F = m \times a \)

Rearranging for \( a \):

\( a = \dfrac{F}{m} = \dfrac{20}{4} = 5 \ \text{m/s}^2 \)

Final Answer: \( \boxed{5 \ \text{m/s}^2} \)

Example:

A \( 1500 \ \text{kg} \) car accelerates at \( 3 \ \text{m/s}^2 \). Calculate the net force acting on the car.

▶️ Answer/Explanation

From Newton’s Second Law:

\( F = m \times a = 1500 \times 3 = 4500 \ \text{N} \)

Final Answer: \( \boxed{4500 \ \text{N}} \)

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