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IB MYP 4-5 Physics- Motion graphs- Study Notes

IB MYP 4-5 Physics- Motion graphs- Study Notes - New Syllabus

IB MYP 4-5 Physics- Motion graphs- Study Notes

Key Concepts

  • Position–Time Graph (Displacement–Time Graph)
  • Velocity–Time Graph
  • Acceleration–Time Graph

IB MYP 4-5 Physics Study Notes – All topics

Position–Time Graph (Displacement–Time Graph)

Position–Time Graph (Displacement–Time Graph)

This graph shows how the position (or displacement) of an object changes with time. Time is plotted on the x-axis and position/displacement on the y-axis.

Key Features:

  • Gradient = Velocity: A steeper gradient means a higher speed.
  • Positive Slope: Motion in the forward direction (positive velocity).
  • Negative Slope: Motion in the reverse direction (negative velocity).
  • Zero Slope (Flat line): Object is stationary.
  • Curved Line: Changing velocity → Acceleration is present.

Typical Shapes and Their Meaning:

Graph ShapeInterpretation
Straight line with positive slopeConstant velocity (uniform motion)
Flat horizontal lineObject is stationary
Straight line with negative slopeMoving in opposite direction at constant speed
Curved upward lineObject is accelerating
Curved downward lineObject is decelerating

Example:

An object moves such that its displacement-time graph is a straight line sloping upwards. What can you say about its motion?

▶️ Answer/Explanation

Since the displacement increases uniformly over time, the object is moving at constant velocity.

The graph’s straight-line nature and constant slope confirm there is no acceleration.

Final Answer: \( \boxed{\text{Constant velocity motion}} \)

Velocity–Time Graph

Velocity–Time Graph

This graph shows how an object’s velocity changes with time. Time is plotted on the x-axis and velocity on the y-axis.

Key Features:

  • Gradient = Acceleration: A steeper slope means greater acceleration.
  • Positive Gradient: Object is accelerating.
  • Negative Gradient: Object is decelerating (slowing down).
  • Zero Gradient (flat line): Constant velocity.
  • Area under the graph = Displacement

Typical Shapes and Their Meaning:

Graph ShapeInterpretation
Horizontal line above time axisConstant positive velocity
Line sloping upwards from zeroUniform acceleration
Line sloping downwards to zeroUniform deceleration
Line below time axisNegative velocity (moving in opposite direction)

Example:

An object accelerates uniformly from rest to a velocity of \( 20\,\text{m/s} \) in 4 seconds. Calculate its acceleration and the displacement covered in this time.

▶️ Answer/Explanation

Step 1: Find acceleration

Using the formula: \( a = \dfrac{v – u}{t} \)

\( a = \dfrac{20 – 0}{4} = \dfrac{20}{4} = 5\,\text{m/s}^2 \)

Step 2: Find displacement using area under graph

This is a triangle: \( \text{Area} = \dfrac{1}{2} \times \text{base} \times \text{height} \)

\( s = \dfrac{1}{2} \times 4 \times 20 = 40\,\text{m} \)

Final Answers:

  • Acceleration = \( \boxed{5\,\text{m/s}^2} \)
  • Displacement = \( \boxed{40\,\text{m}} \)

Acceleration–Time Graph

Acceleration–Time Graph

This graph shows how the acceleration of an object changes over time. Time is on the x-axis and acceleration is on the y-axis.

Key Features:

  • Horizontal Line Above Time Axis: Constant positive acceleration.
  • Horizontal Line on Time Axis: Zero acceleration (uniform motion).
  • Horizontal Line Below Time Axis: Constant negative acceleration (deceleration).
  • Area Under the Graph = Change in Velocity

Typical Shapes and Their Meaning:

Graph ShapeInterpretation
Horizontal line above x-axisConstant acceleration
Horizontal line below x-axisConstant deceleration
Line on x-axisNo acceleration (zero, steady velocity)

Example:

An acceleration-time graph shows a constant value of \( 2\,\text{m/s}^2 \) over 5 seconds. Find the total change in velocity over this time.

▶️ Answer/Explanation

Step 1: Use area under the graph (rectangle):

\( \Delta v = a \times t = 2 \times 5 = 10\,\text{m/s} \)

Final Answer: \( \boxed{10\,\text{m/s}} \)

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