IB MYP 4-5 Physics- Pressure in solids - Study Notes - New Syllabus
IB MYP 4-5 Physics- Pressure in solids – Study Notes
Key Concepts
- Mappings
Pressure in Solids
Pressure in Solids
Pressure in solids refers to the force exerted per unit area when a solid object is in contact with a surface.
It is given by:
\( P = \dfrac{F}{A} \)
- Where:
- \( P \) = Pressure (Pa or N/m\(^2\))
- \( F \) = Force applied (N)
- \( A \) = Contact area (m\(^2\))
Key Points:
- Pressure is directly proportional to the applied force and inversely proportional to the area.
- For a given force, a smaller contact area produces greater pressure.
- For solids, pressure acts perpendicular to the contact surface.
- Changing the shape or orientation of the solid changes the pressure it exerts on a surface.
Factors Affecting Pressure in Solids:
- Magnitude of Force: Increasing the applied force increases the pressure.
- Contact Area: Smaller areas increase pressure; larger areas reduce pressure.
- Distribution of Force: Uneven force distribution causes variable pressure across the surface.
Applications:
- Knife edges are made sharp to increase pressure for cutting.
- Snowshoes have large surface areas to reduce pressure and prevent sinking into snow.
- Bulldozer tracks are wide to reduce pressure on soft ground.
Example:
A box weighing \( 200 \, \text{N} \) has a base area of \( 0.5 \, \text{m}^2 \). Find the pressure exerted on the floor.
▶️ Answer/Explanation
Using \( P = \dfrac{F}{A} \):
\( P = \dfrac{200}{0.5} = 400 \, \text{Pa} \)
Final Answer: \(\boxed{400 \, \text{Pa}}\)
Example:
A woman of weight \( 600 \, \text{N} \) stands on stiletto heels with a total contact area of \( 4 \, \text{cm}^2 \). Calculate the pressure exerted.
▶️ Answer/Explanation
Convert \( 4 \, \text{cm}^2 \) to \( \text{m}^2 \):
\( 4 \, \text{cm}^2 = 4 \times 10^{-4} \, \text{m}^2 \)
Using \( P = \dfrac{F}{A} \):
\( P = \dfrac{600}{4 \times 10^{-4}} = 1.5 \times 10^{6} \, \text{Pa} \)
Final Answer: \(\boxed{1.5 \times 10^{6} \, \text{Pa}}\)