IB MYP 4-5 Physics- Speed of sound and its measurement- Study Notes - New Syllabus
IB MYP 4-5 Physics-Speed of sound and its measurement- Study Notes
Key Concepts
- Speed of sound and its measurement
 
Speed of sound and its measurement
Speed of Sound
Sound is a mechanical wave, and its speed depends on the medium (air, water, solid) through which it travels.
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General formula for wave speed:
\( v = \dfrac{d}{t} \)
\( v = f \lambda \)
Where:
- \( v \) = speed of sound (m/s)
 - \( d \) = distance traveled (m)
 - \( t \) = time taken (s)
 - \( f \) = frequency (Hz)
 - \( \lambda \) = wavelength (m)
 
Factors affecting speed of sound
- Medium: Sound travels fastest in solids, slower in liquids, and slowest in gases because particle density and bonding affect vibration transfer.
 - Temperature: In gases, speed increases with temperature because particles move faster.
\( v \approx 331 + 0.6T \, \, \text{(m/s, with T in °C)} \)
 - Pressure: At constant temperature, pressure has little effect since both pressure and density change proportionally.
 
Measurement of Speed of Sound
1. Echo Method
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- Clap or produce a loud sound near a large wall/cliff.
 - Measure time taken for the echo to return.
 - Total distance covered = \( 2d \) (to wall and back).
 
\( v = \dfrac{2d}{t} \)
2. Resonance Tube Method
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- A tuning fork of known frequency is struck and placed above a vertical resonance tube (partially filled with water).
 - When resonance occurs, sound becomes loudest → air column length \( L \) = \(\dfrac{\lambda}{4}\) (first resonance).
 - Speed is calculated as:
 
\( v = f \lambda \)
- where \(\lambda = 4L\).
 
3. Time-of-Flight Method (modern)
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- Microphones and sensors are used to record the time taken for sound to travel a known distance.
 - This is more precise than echo method.
 
Example:
A student shouts near a cliff 170 m away. The echo is heard after 1 second. Calculate the speed of sound.
▶️ Answer/Explanation
Total distance = \(2d = 2 \times 170 = 340 \, \text{m}\)
Speed \(v = \dfrac{2d}{t} = \dfrac{340}{1} = 340 \, \text{m/s}\)
Final Answer: \(\boxed{340 \, \text{m/s}}\)
Example:
A tuning fork of frequency \(f = 512 \, \text{Hz}\) produces resonance in a tube when air column length is \(L = 0.165 \, \text{m}\). Find the speed of sound.
▶️ Answer/Explanation
At first resonance, \(\lambda = 4L = 4 \times 0.165 = 0.66 \, \text{m}\)
\(v = f \lambda = 512 \times 0.66 \approx 338 \, \text{m/s}\)
Final Answer: \(\boxed{338 \, \text{m/s}}\)
Example:
Find the speed of sound in air at 25°C using the formula \( v = 331 + 0.6T \).
▶️ Answer/Explanation
\(v = 331 + 0.6 \times 25 = 331 + 15 = 346 \, \text{m/s}\)
Final Answer: \(\boxed{346 \, \text{m/s}}\)
