IB MYP 4-5 Physics- Total internal reflection and critical angle- Study Notes - New Syllabus
IB MYP 4-5 Physics-Total internal reflection and critical angle- Study Notes
Key Concepts
- Total internal reflection and critical angle
Critical Angle and Total Internal Reflection
Critical Angle and Total Internal Reflection
Critical Angle (\(c\)):
The critical angle is the angle of incidence in the denser medium for which the angle of refraction in the rarer medium is \(90^\circ\).
- At this point, the refracted ray just skims along the boundary between the two media.
- Formula for the critical angle when moving from medium of refractive index \(n_1\) to air (with refractive index \(\approx 1\)):
\(\sin c = \dfrac{1}{n}\)
where \(n\) is the refractive index of the denser medium relative to air.
- More generally, between two media:
\(\sin c = \dfrac{n_2}{n_1}\)
where \(n_1 > n_2\).
Key Points:
- If angle of incidence \(< c\): Refraction occurs.
- If angle of incidence \(= c\): Ray emerges along the boundary (at \(90^\circ\)).
- If angle of incidence \(> c\): Total internal reflection occurs.
Total Internal Reflection (TIR):
TIR occurs when light tries to move from a denser medium (higher refractive index, e.g. glass or water) to a less dense medium (lower refractive index, e.g. air).
- Instead of refracting into the second medium, the light is reflected entirely back inside the denser medium.
- Thus, no light escapes; it is 100% reflected at the boundary.
Conditions for Total Internal Reflection:
- Light must travel from a denser medium to a rarer medium.
- The angle of incidence must be greater than the critical angle.
Applications of Total Internal Reflection:
- Optical fibres: Used in medical endoscopes and telecommunication to transmit light signals with very little loss.
- Prisms: Used in binoculars, periscopes, and cameras to reflect light efficiently without mirrors.
- Sparkling effect in diamonds: Diamonds have a very high refractive index (≈ 2.4), which creates a very small critical angle and enhances total internal reflection, making them sparkle.
Example:
Light travels from glass (\(n_1 = 1.5\)) into air (\(n_2 = 1.0\)). Find the critical angle.
▶️ Answer/Explanation
Using the formula: \(\sin \theta_c = \dfrac{n_2}{n_1}\)
\(\sin \theta_c = \dfrac{1.0}{1.5} = 0.667\)
Thus, \(\theta_c = \arcsin(0.667) \approx 41.8^\circ\)
Final Answer: \(\boxed{41.8^\circ}\)
Example:
An optical fiber is made of plastic with refractive index \(n_1 = 1.6\), surrounded by air (\(n_2 = 1.0\)). What is the minimum angle of incidence required inside the fiber for TIR?
▶️ Answer/Explanation
First, calculate critical angle:
\(\sin \theta_c = \dfrac{1.0}{1.6} = 0.625\)
\(\theta_c = \arcsin(0.625) \approx 38.7^\circ\)
Thus, any angle of incidence \(>\,38.7^\circ\) will cause TIR.
Final Answer: Minimum incidence angle = \(\boxed{38.7^\circ}\)
Example:
Why does a diamond sparkle more than ordinary glass?
▶️ Answer/Explanation
Diamonds have a much higher refractive index (\(n \approx 2.4\)) compared to glass (\(n \approx 1.5\)).
This means the critical angle is very small (\(\theta_c \approx 24.6^\circ\)), so light entering the diamond undergoes multiple total internal reflections inside before escaping.
This repeated TIR causes light to reflect at many angles, producing intense sparkle.