IB Mathematics SL 4.9 The normal distribution -AI HL Paper 1- Exam Style Questions- New Syllabus
Question
In a reaction test, the time, \(T\) seconds, taken to complete the test can be modelled by a normal distribution with a mean of \(5\) seconds and a standard deviation of \(1\) second.
(a) Find the probability that a randomly selected person completes the reaction test in less than \(4\) seconds. [2]
The graph of the distribution of \(T\) is shown in the following diagram.
The slowest \(15\%\) of participants will be given training to reduce their time to complete the test.
(b)
(i) Shade the region on the given diagram that corresponds to these participants.
(ii) Find the least time taken to complete the test by a person who will be given training. [3]
Most-appropriate topic code (IB DP Mathematics: Applications and Interpretation):
▶️ Answer/Explanation
The reaction time is normally distributed as
\(T\sim N(5,1^2)\).
(a)
We need to calculate
\(P(T<4)\).
Using the normal cumulative distribution function with mean \(5\) and standard deviation \(1\),
\(P(T<4)=0.158655\ldots\)
\(\therefore P(T<4)\approx 0.159\).
✅ Answer: \(0.159\)
(b)(i)
The slowest participants take the longest time to complete the test. Therefore, the required \(15\%\) is represented by the right-hand tail of the normal distribution.
Shade the region under the curve to the right of the cutoff value \(k\), where \(k>5\).
✅ Answer: Shade the rightmost \(15\%\) of the distribution.
(b)(ii)
Let \(k\) be the least completion time of a participant who will receive training.
Since the slowest \(15\%\) are selected,
\(P(T>k)=0.15\).
Equivalently,
\(P(T<k)=0.85\).
Using the inverse normal function with mean \(5\), standard deviation \(1\) and cumulative probability \(0.85\),
\(k=\operatorname{invNorm}(0.85,5,1)\)
\(k=6.03643\ldots\)
\(k\approx 6.04\text{ seconds}\).
This means that participants taking approximately \(6.04\) seconds or longer are among the slowest \(15\%\).
✅ Answer: \(6.04\) seconds
