(i) To find \( f(4) \), locate \( x = 4 \) on the x-axis and trace vertically to the curve. The graph shows \( y \approx 1 \).

Answer: \( f(4) = 1 \)

(ii) To find \( f \circ f(4) \), first use \( f(4) = 1 \). Then, find \( f(1) \) by locating \( x = 1 \) on the x-axis and tracing vertically. The graph shows \( y \approx 3 \).

Answer: \( f \circ f(4) = f(1) = 3 \)

(iii) To find \( f^{-1}(3) \), find the \( x \)-value where \( f(x) = 3 \). Locate \( y = 3 \) on the y-axis and trace horizontally to the curve. The graph shows \( x \approx 1 \).

Answer: \( f^{-1}(3) = 1 \)

As per the markscheme, sketch the graph of \( y = f^{-1}(x) \):

– The graph is a concave up curve.

– It has a \( y \)-intercept at \( (0, 10) \).

– It has an \( x \)-intercept at \( (5, 0) \).

– The curve passes through either \( (2, 2) \) or both \( (1, 4) \) and \( (3, 1) \).