Home / IB Mathematics SL 4.6 Venn and tree diagrams, counting principles AA SL Paper 2- Exam Style Question

IB Mathematics SL 4.6 Venn and tree diagrams, counting principles AA SL Paper 2- Exam Style Question

IB Mathematics SL 4.6 Venn and tree diagrams, counting principles AA SL Paper 2- Exam Style Questions- New Syllabus

Question

Ann and Bob play a game with eight-sided dice. Ann’s die has 3 green faces and 5 red faces; Bob’s die has 4 green faces and 4 red faces. They take turns rolling their own die, noting the color that faces up. The first player to roll green wins, with Ann rolling first. Part of the game’s tree diagram is shown below.

Dice game tree diagram

Part (a):
Find the probability that Ann wins on her first roll. [2]

Part (b):

(i) The probability that Ann wins on her third roll is \( \frac{5}{8} \times \frac{4}{8} \times p \times q \times \frac{3}{8} \). Write down the value of \( p \) and of \( q \).

(ii) The probability that Ann wins on her tenth roll is \( \frac{3}{8} r^k \), where \( r \in \mathbb{Q}, k \in \mathbb{Z} \). Find the value of \( r \) and of \( k \). [6]

Part (c):
Find the probability that Ann wins the game. [7]

▶️ Answer/Explanation
Markscheme

Part (a)

Recognize Ann rolls green on her first roll, using her die with 3 green faces out of 8 (M1)

eg \( \text{P(G)} = \frac{\text{number of green faces}}{\text{total faces}} \)

\( \frac{3}{8} \) (A1) (N2)

[2 marks]

Part (b)

(i) For Ann to win on her third roll, the sequence is: Ann red (\( \frac{5}{8} \)), Bob red (\( \frac{4}{8} \)), Ann red (\( \frac{5}{8} \)), Bob red (\( \frac{4}{8} \)), Ann green (\( \frac{3}{8} \)). Thus, \( p = \frac{5}{8}, q = \frac{4}{8} \) or \( q = \frac{4}{8}, p = \frac{5}{8} \) (A1A1) (N2)

(ii) Recognize Ann wins on her tenth roll after 9 losses (Ann red, Bob red) (M1)

eg Sequence: \( \left( \frac{5}{8} \times \frac{4}{8} \right)^9 \times \frac{3}{8} \)

\( k = 9 \) (number of loss pairs before Ann’s tenth roll) (A1) (N2)

Correct working to express probability: \( \frac{3}{8} \left( \frac{5}{8} \times \frac{4}{8} \right)^9 = \frac{3}{8} \left( \frac{20}{64} \right)^9 \) (A1)

\( r = \frac{20}{64} \left( = \frac{5}{16} \right) \) (A1) (N2)

[6 marks]

Part (c)

Recognize the probability is an infinite sum of Ann winning on her 1st, 2nd, 3rd, … roll (M1)

eg Sum of probabilities: Ann wins on \( 1^{\text{st}} \) roll or \( 2^{\text{nd}} \) roll or \( 3^{\text{rd}} \) roll…, \( S_\infty \)

Recognize geometric progression with first term and common ratio (M1)

First term: \( u_1 = \frac{3}{8} \) (Ann wins on first roll) (A1)

Common ratio: \( r = \frac{5}{8} \times \frac{4}{8} = \frac{20}{64} = \frac{5}{16} \) (probability both lose per round) (A1)

Correct substitution into infinite geometric series sum: \( \frac{u_1}{1 – r} = \frac{\frac{3}{8}}{1 – \frac{5}{16}} \) (A1)

Correct working: \( \frac{\frac{3}{8}}{\frac{11}{16}} = \frac{3}{8} \times \frac{16}{11} \) (A1)

\( \text{P (Ann wins)} = \frac{48}{88} \left( = \frac{6}{11} \right) \) (A1) (N1)

[7 marks]

Total [15 marks]

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