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IB Mathematics AA HL Flashcards- SL 3.1 Distance volume and Surface Area

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[h] SL 3.1 Distance volume and Surface Area

[q] Distance between two points.

[a] This is found by creating a right-angled traingle and using Pythagorean Theorem to find the distance (hypotenuse).
2D: d = \(\sqrt{(x_{1}-x_{2})^{2}+(y_{1}-y_{2})^{2}}\)
3D: d = \(\sqrt{(x_{1}-x_{2})^{2}+(y_{1}-y_{2})^{2}+(z_{1}-z_{2})^{2}}\)

[q] Cylinder ” Circular Prism”

[a] Volume = \(\Pi(r)^2h\)
Curved Surface Area = \(2\Pi(rh)\)
Total Surface Area = \(2\Pi(rh)+2\Pi(r^2)\)

[q] Cone 

[a] Volume = \(\frac{1}{3}\Pi(r)^2h\)
Curved Surface Area = \(\Pi(rL)\)
Total Surface Area = \(\Pi(rL)+2\Pi(r^2)\)

[q] Sphere

[a] Volume = \(\frac{4}{3}\Pi(r)^3\)
Curved Surface Area = Total Surface Area = \(4\Pi(r^2)\)

[q] Pyramid

[a] Volume = \(\frac{1}{3}×Base Area×Height\)
Curved Surface Area = Total Surface Area = Sum of areas of all faces
 

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IB Mathematics AA HL Flashcards- SL 3.1 Distance volume and Surface Area

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