IB Mathematics AA HL Polynomials Study Notes
IB Mathematics AA HL Polynomials Study Notes
IB Mathematics AA HL Polynomials Study Notes Offer a clear explanation of Polynomials , including various formula, rules, exam style questions as example to explain the topics. Worked Out examples and common problem types provided here will be sufficient to cover for topic Polynomials.
Polynomials
Polynomial functions are mathematical expressions involving a sum of powers in one or more variables multiplied by coefficients. The general form of a polynomial function of degree \( n \) is:
\( f(x) = a_nx^n + a_{n-1}x^{n-1} + \ldots + a_1x + a_0 \)
Guidance, Clarification:
- Graphs of Polynomial Functions:
- The graph of a polynomial function of degree \( n \) will intersect the x-axis at most \( n \) times.
- The behavior of the graph near the x-axis depends on the roots (real and complex) of the polynomial.
- Zeros, Roots, and Factors:
- Zeros/Roots: The values of \( x \) for which \( f(x) = 0 \).
- Factors: If \( r \) is a root of \( f(x) \), then \( (x – r) \) is a factor of the polynomial.
- Factor Theorem:
- If \( f(r) = 0 \), then \( (x – r) \) is a factor of \( f(x) \).
- Remainder Theorem:
- When a polynomial \( f(x) \) is divided by \( (x – r) \), the remainder is \( f(r) \).
- Sum and Product of Roots:
- For a polynomial equation of degree \( n \): \( a_nx^n + a_{n-1}x^{n-1} + \ldots + a_1x + a_0 = 0 \).
- Sum of the roots: \( -\frac{a_{n-1}}{a_n} \).
- Product of the roots: \( (-1)^n \cdot \frac{a_0}{a_n} \).
Examples of Polynomial Concepts
Example 1: Using the Factor Theorem
Determine if \( (x – 3) \) is a factor of \( f(x) = 2x^3 – 9x^2 + 12x – 9 \).
Solution:
Calculate \( f(3) \):
\( f(3) = 2(3)^3 – 9(3)^2 + 12(3) – 9 = 0 \)
Since \( f(3) = 0 \), \( (x – 3) \) is a factor of \( f(x) \).
Example 2: Using the Remainder Theorem
Find the remainder when \( f(x) = 4x^4 – 2x^3 + 5x – 1 \) is divided by \( (x – 2) \).
Solution:
Calculate \( f(2) \):
\( f(2) = 4(2)^4 – 2(2)^3 + 5(2) – 1 = 31 \)
The remainder is 31.
Example 3: Sum and Product of Roots
For the polynomial equation \( 2x^2 – 5x + 3 = 0 \), find the sum and product of the roots.
- Sum of the roots: \( -\frac{-5}{2} = \frac{5}{2} \).
- Product of the roots: \( \frac{3}{2} \).
Example 4: Graphing Polynomial Functions
Sketch the graph of \( f(x) = x^3 – 6x^2 + 11x – 6 \).
- Find the roots using the factor theorem: \( f(x) = (x – 1)(x – 2)(x – 3) \).
- The graph intersects the x-axis at \( x = 1, 2, 3 \).
The polynomial graph is a cubic curve crossing the x-axis at the given roots.
IB Mathematics AA SL Polynomial Exam Style Worked Out Questions
Question
The same remainder is found when \(2{x^3} + k{x^2} + 6x + 32\) and \({x^4} – 6{x^2} – {k^2}x + 9\) are divided by \(x + 1\) . Find the possible values of k .
▶️Answer/Explanation
Markscheme
let \(f(x) = 2{x^3} + k{x^2} + 6x + 32\)
let \(g(x) = {x^4} – 6{x^2} – {k^2}x + 9\)
\(f( – 1) = – 2 + k – 6 + 32( = 24 + k)\) A1
\(g( – 1) = 1 – 6 + {k^2} + 9( = 4 + {k^2})\) A1
\( \Rightarrow 24 + k = 4 + {k^2}\) M1
\( \Rightarrow {k^2} – k – 20 = 0\)
\( \Rightarrow (k – 5)(k + 4) = 0\) (M1)
\( \Rightarrow k = 5,\, – 4\) A1A1
[6 marks]
Question
Consider the polynomial \(q(x) = 3{x^3} – 11{x^2} + kx + 8\).
Given that \(q(x)\) has a factor \((x – 4)\), find the value of \(k\).[3]
Hence or otherwise, factorize \(q(x)\) as a product of linear factors.[3]
▶️Answer/Explanation
Markscheme
\(q(4) = 0\) (M1)
\(192 – 176 + 4k + 8 = 0{\text{ }}(24 + 4k = 0)\) A1
\(k = – 6\) A1
[3 marks]
\(3{x^3} – 11{x^2} – 6x + 8 = (x – 4)(3{x^2} + px – 2)\)
equate coefficients of \({x^2}\): (M1)
\( – 12 + p = – 11\)
\(p = 1\)
\((x – 4)(3{x^2} + x – 2)\) (A1)
\((x – 4)(3x – 2)(x + 1)\) A1
Note: Allow part (b) marks if any of this work is seen in part (a).
Note: Allow equivalent methods (eg, synthetic division) for the M marks in each part.
[3 marks]