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IBDP Maths MAA SL 1.4 Financial applications HL Paper 1- Exam Style Questions

Question

Bob places 1000 dinar into a bank account that offers a nominal annual interest rate of 4%, compounded quarterly.
After one full year, the value of the investment can be written in the form \( 1000(1 + k)^4 \), where \( k \in \mathbb{Q} \).
(a) State the value of \( k \).
(b) Expand and simplify \( (1 + x)^4 \).
(c) Hence, or otherwise, calculate the amount of money in the account after one complete year, giving your answer correct to the nearest dinar.

Most-appropriate topic codes (IB Mathematics Analysis and Approaches 2021):

SL 1.4: Financial applications of geometric sequences and series: compound interest — parts (a), (c)
SL 1.9: The binomial theorem: expansion of \( (a + b)^n \), \( n \in \mathbb{N} \) — part (b)
▶️ Answer/Explanation

(a) Determining \( k \):

Nominal annual interest rate = 4% = 0.04
Compounded quarterly ⇒ interest rate per quarter = \( \frac{0.04}{4} = 0.01 \)
Thus \( k = 0.01 \) or \( \frac{1}{100} \).
\( \boxed{k = 0.01} \)

(b) Expanding \( (1 + x)^4 \):

Using the binomial theorem:
\( (1 + x)^4 = 1 + 4x + 6x^2 + 4x^3 + x^4 \)
\( \boxed{1 + 4x + 6x^2 + 4x^3 + x^4} \)

(c) Amount after one year:

Amount = \( 1000(1 + k)^4 = 1000(1 + 0.01)^4 \)
Using the expansion from (b) with \( x = 0.01 \):
\( (1.01)^4 = 1 + 4(0.01) + 6(0.01)^2 + 4(0.01)^3 + (0.01)^4 \)
\( = 1 + 0.04 + 0.0006 + 0.000004 + 0.00000001 \)
\( = 1.04060401 \)
Multiply by 1000:
\( 1000 \times 1.04060401 = 1040.60401 \)
Nearest dinar ⇒ 1041 dinar.
\( \boxed{1041} \) dinar

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