IB Mathematics AA SL The rational function Study Notes
IB Mathematics AA SL The rational function Study Notes Offer a clear explanation of The rational function , including various formula, rules, exam style questions as example to explain the topics. Worked Out examples and common problem types provided here will be sufficient to cover for topic The rational function
Rational Functions
The study of reciprocal and rational functions is essential for understanding complex relationships in algebra and graphing. These functions are foundational in various fields such as calculus, physics, and economics.
1. Reciprocal Function
The reciprocal function is defined as:
\( f(x) = \frac{1}{x} \), where \( x \neq 0 \)
Properties:
- Self-Inverse Nature: The reciprocal function is its own inverse. Applying the function twice returns the original value: \( f(f(x)) = x \).
- Graph: The graph of \( f(x) = \frac{1}{x} \) consists of two branches, located in the first and third quadrants. It is a hyperbola with asymptotes.
2. Rational Functions
A rational function is a ratio of two linear expressions, given by:
\( f(x) = \frac{ax + b}{cx + d} \)
where \( a, b, c, \) and \( d \) are constants, and \( cx + d \neq 0 \) to avoid division by zero.
Graphical Features:
Vertical Asymptotes: The vertical asymptote occurs where the denominator is zero, i.e., \( cx + d = 0 \). Solving for \( x \) gives:
\( x = -\frac{d}{c} \)
Horizontal Asymptotes: The horizontal asymptote is determined by the ratio of the leading coefficients as \( x \) approaches infinity:
\( y = \frac{a}{c} \)
3. Example Problem
Sketch the graph of \( f(x) = \frac{2x – 3}{x + 4} \).
- Vertical Asymptote: Set \( x + 4 = 0 \), so \( x = -4 \).
- Horizontal Asymptote: As \( x \to \infty \), the horizontal asymptote is \( y = \frac{2}{1} = 2 \).
- Intercepts:
- x-intercept: Set \( f(x) = 0 \), so \( 2x – 3 = 0 \); solving gives \( x = 1.5 \).
- y-intercept: Set \( x = 0 \); solving gives \( y = \frac{-3}{4} = -0.75 \).
Graph Analysis: The graph approaches \( x = -4 \) as a vertical asymptote and \( y = 2 \) as a horizontal asymptote. It passes through the points \( (1.5, 0) \) and \( (0, -0.75) \).
4. Connections to Transformations
The graph of a rational function can be transformed similarly to other functions. For instance, translating \( f(x) = \frac{1}{x} \) by \( h \) units horizontally and \( k \) units vertically results in:
\( f(x) = \frac{1}{x – h} + k \)
This transformation affects the position of the asymptotes and the overall shape of the graph.
5. Historical Development
The concept of functions and graphing has been developed by notable mathematicians such as:
- René Descartes (France): Known for Cartesian coordinates and the use of algebra to represent geometric shapes.
- Gottfried Wilhelm Leibniz (Germany): Co-founder of calculus, contributed significantly to the notation and analysis of functions.
- Leonhard Euler (Switzerland): Made profound contributions to graph theory, analysis, and introduced the concept of a function as a fundamental part of mathematics.
6. Use of Technology
Dynamic graphing software, such as Desmos or GeoGebra, can be used to explore rational functions interactively. Using sliders to adjust \( a, b, c, \) and \( d \) helps visualize the effect on the graph’s shape and position of asymptotes.
7.Enrichment: Deriving Horizontal Asymptote Formula
To derive the horizontal asymptote for \( f(x) = \frac{ax + b}{cx + d} \), consider the limit as \( x \to \infty \):
\( \lim_{x \to \infty} \frac{ax + b}{cx + d} = \frac{a}{c} \)
This approach shows why the horizontal asymptote is \( y = \frac{a}{c} \).
Examples of Reciprocal and Rational Functions
To better understand reciprocal and rational functions, let’s look at some specific examples and their solutions.
Example 1: Solving a Rational Equation
Problem: Solve the equation \( \frac{2x + 3}{x – 1} = 4 \).
Solution:
Multiply both sides by \( x – 1 \):
\( 2x + 3 = 4(x – 1) \)
Expand and simplify:
\( 2x + 3 = 4x – 4 \)
\( -2x = -7 \)
Solving for \( x \):
\( x = 3.5 \)
Check the solution:
Substitute \( x = 3.5 \) back into the original equation to verify:
\( \frac{2(3.5) + 3}{3.5 – 1} = 4 \)
The equation holds true, so \( x = 3.5 \) is the solution.
Example 2: Identifying Asymptotes of a Rational Function
Problem: Find the vertical and horizontal asymptotes of \( f(x) = \frac{3x + 5}{2x – 7} \).
Solution:
Vertical Asymptote: The vertical asymptote occurs where the denominator is zero:
\( 2x – 7 = 0 \implies x = \frac{7}{2} \).
Horizontal Asymptote: As \( x \to \infty \) or \( x \to -\infty \), the horizontal asymptote is determined by the ratio of the leading coefficients:
\( y = \frac{3}{2} \).
Thus, the vertical asymptote is \( x = \frac{7}{2} \) and the horizontal asymptote is \( y = \frac{3}{2} \).
Example 3: Application of Rational Function in Real Life
Problem: The cost \( C \) (in dollars) of producing \( x \) units of a product is given by \( C(x) = \frac{500x}{x + 100} \). Find the horizontal asymptote and interpret its meaning in the context of production cost.
Solution:
Horizontal Asymptote: As \( x \to \infty \), the horizontal asymptote is:
\( y = \lim_{x \to \infty} \frac{500x}{x + 100} = 500 \).
Interpretation: The horizontal asymptote \( y = 500 \) implies that as production increases, the cost per unit approaches $500. This indicates a limiting average cost per unit as the number of units produced becomes very large.
IB Mathematics AA SL Rational Function Exam Style Worked Out Questions
Question
Let \(f(x) = p + \frac{9}{{x – q}}\), for \(x \ne q\). The line \(x = 3\) is a vertical asymptote to the graph of \(f\).
Write down the value of \(q\).[1]
The graph of \(f\) has a \(y\)-intercept at \((0,{\text{ }}4)\).
Find the value of \(p\).[4]
The graph of \(f\) has a \(y\)-intercept at \((0,{\text{ }}4)\).
Write down the equation of the horizontal asymptote of the graph of \(f\).[1]
▶️Answer/Explanation
Markscheme
\(q = 3\) A1 N1
[1 mark]
correct expression for \(f(0)\) (A1)
eg\(\;\;\;p + \frac{9}{{0 – 3}},{\text{ }}4 = p + \frac{9}{{ – q}}\)
recognizing that \(f(0) = 4\;\;\;\)(may be seen in equation) (M1)
correct working (A1)
eg\(\;\;\;4 = p – 3\)
\(p = 7\) A1 N3
[3 marks]
\(y = 7\;\;\;\)(must be an equation, do not accept \(p = 7\) A1 N1
[1 mark]
Total [6 marks]
Question
Let \(f(x) = p + \frac{9}{{x – q}}\), for \(x \ne q\). The line \(x = 3\) is a vertical asymptote to the graph of \(f\).
Write down the value of \(q\).[1]
The graph of \(f\) has a \(y\)-intercept at \((0,{\text{ }}4)\).
Find the value of \(p\).[4]
The graph of \(f\) has a \(y\)-intercept at \((0,{\text{ }}4)\).
Write down the equation of the horizontal asymptote of the graph of \(f\).[1]
▶️Answer/Explanation
Markscheme
\(q = 3\) A1 N1
[1 mark]
correct expression for \(f(0)\) (A1)
eg\(\;\;\;p + \frac{9}{{0 – 3}},{\text{ }}4 = p + \frac{9}{{ – q}}\)
recognizing that \(f(0) = 4\;\;\;\)(may be seen in equation) (M1)
correct working (A1)
eg\(\;\;\;4 = p – 3\)
\(p = 7\) A1 N3
[3 marks]
\(y = 7\;\;\;\)(must be an equation, do not accept \(p = 7\) A1 N1
[1 mark]
Total [6 marks]