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IB Mathematics AI AHL The derivatives of sin x MAI Study Notes - New Syllabus

IB Mathematics AI AHL The derivatives of sin x MAI Study Notes

LEARNING OBJECTIVE

  • The derivatives of standard functions.

Key Concepts: 

  • Common Derivatives
  • Derivative Rules
  • Related Rates of Change

MAI HL and SL Notes – All topics

COMMON DERIVATIVES

Common Derivatives

Below are the standard derivatives of common functions:

FunctionDerivative
\( f(x) = x^n \)\( f'(x) = nx^{n-1} \), where \( n \in \mathbb{Q} \)
\( f(x) = \sin x \)\( f'(x) = \cos x \)
\( f(x) = \cos x \)\( f'(x) = -\sin x \)
\( f(x) = \tan x \)\( f'(x) = \sec^2 x \) (where \( x \ne \frac{\pi}{2} + n\pi \))
\( f(x) = e^x \)\( f'(x) = e^x \)
\( f(x) = \ln x \)\( f'(x) = \frac{1}{x} \), \( x > 0 \)

Example

Differentiate each of the following:

  1. \( f(x) = x^5 \)
  2. \( g(x) = e^x + \ln x \)
  3. \( h(x) = \sin x – \cos x \)
▶️Answer/Explanation
  • \( f^\prime (x) = 5x^4 \)     (Power Rule)
  • \( g^\prime (x) = e^x + \frac{1}{x} \)     (Derivative of \( e^x \) and \( \ln x \))
  • \( h^\prime (x) = \cos x + \sin x \)     (Derivatives of sine and cosine)

 DERIVATIVE RULES

 Chain Rule

The chain rule is used to differentiate a function that is composed of two or more functions. If one function is inside another, we take the derivative of the outer function and multiply it by the derivative of the inner function.

If \( y = f(u) \) and \( u = g(x) \), then:

\( \displaystyle \frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx} \)

In Leibniz notation, :

\( \displaystyle \frac{d}{dx}[f(g(x))] = f'(g(x)) \cdot g'(x) \)

 

 Product Rule

When you multiply two functions together, the product rule helps you find the derivative. It states that you take the first function times the derivative of the second, and add the second function times the derivative of the first.

If \( y = u(x)v(x) \), then:

\( \displaystyle \frac{dy}{dx} = u \frac{dv}{dx} + v \frac{du}{dx} \)

Or in more compact notation:

\( (uv)’ = u’v + uv’ \)

Quotient Rule

If you have a function that is the ratio of two other functions, the quotient rule allows you to differentiate it. The rule says you take the denominator times the derivative of the numerator, subtract the numerator times the derivative of the denominator, and divide the whole result by the square of the denominator.

If \( y = \frac{u(x)}{v(x)} \), then:

\( \displaystyle \frac{dy}{dx} = \frac{v \frac{du}{dx} – u \frac{dv}{dx}}{v^2} \)

Or in more compact notation:

\( \left( \frac{u}{v} \right)’ = \frac{u’v – uv’}{v^2} \)

Example 

Differentiate \( y = \frac{x^2 \sin(x)}{e^x} \)

▶️ Answer/Explanation
  • Let \( u = x^2 \sin x \), \( v = e^x \)
  • \( u’ = 2x \sin x + x^2 \cos x \), \( v’ = e^x \)
  • Quotient rule: \( \frac{dy}{dx} = \frac{u’v – uv’}{v^2} \)
  • Simplifies to:
    \( \frac{dy}{dx} = \frac{e^x(2x \sin x + x^2 \cos x – x^2 \sin x)}{e^{2x}} \)
    Final answer: \( \frac{2x \sin x + x^2 \cos x – x^2 \sin x}{e^x} \)

RELATED RATES OF CHANGE

Related Rates of Change

Used when two or more variables are changing over time. 

For example:

If \( x \) and \( y \) are related by a function and both are functions of \( t \), then:

\( \frac{dy}{dt} = \frac{dy}{dx} \cdot \frac{dx}{dt} \)

This is a direct application of the chain rule where time is the independent variable. Related rates are useful in geometry, physics, and motion problems.

Example

Air is pumped into a spherical balloon. Volume increases at 100 cm³/s. How fast is the radius increasing when \( r = 5 \) cm?

▶️ Answer/Explanation
  • Given: \( \frac{dV}{dt} = 100 \), \( r = 5 \)
  • Use: \( V = \frac{4}{3}\pi r^3 \)
  • \( \frac{dV}{dt} = 4\pi r^2 \cdot \frac{dr}{dt} \)
  • Substitute: \( 100 = 4\pi (25) \cdot \frac{dr}{dt} \Rightarrow \frac{dr}{dt} = \frac{1}{\pi} \) cm/s

 Maximum and Minimum Points & Optimisation

  • Set derivative \( f'(x) = 0 \) to find stationary points.
  • Use second derivative \( f”(x) \) to classify the points:
    • \( f”(x) > 0 \) → local minimum
    • \( f”(x) < 0 \) → local maximum
  • Apply in optimisation problems: minimize cost, maximize area/volume, etc.

Example 

Find the local maximum and minimum points of the function \( f(x) = x^3 – 6x^2 + 9x + 1 \).

▶️ Answer/Explanation
  • \( f'(x) = 3x^2 – 12x + 9 \)
  •  \( f'(x) = 0 \):
    \( 3x^2 – 12x + 9 = 0 \Rightarrow x^2 – 4x + 3 = 0 \Rightarrow x = 1 \) or \( x = 3 \)
  • Second derivative: \( f”(x) = 6x – 12 \)
  • At \( x = 1 \), \( f”(1) = -6 < 0 \) → Local maximum
  • At \( x = 3 \), \( f”(3) = 6 > 0 \) → Local minimum
  • \( f(1) = 1 – 6 + 9 + 1 = 5 \)
    \( f(3) = 27 – 54 + 27 + 1 = 1 \)
  • Final Answer:
    Local maximum at \( (1, 5) \), Local minimum at \( (3, 1) \)
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