Home / IBDP Physics- D.4 Induction- IB Style Questions For HL Paper 1A

IBDP Physics- D.4 Induction- IB Style Questions For HL Paper 1A -FA 2025

 Question

A circuit consists of a cell, two parallel conducting rails, and a movable metal rod of length \(L\). When a uniform magnetic field \(B\) is applied out of the plane of the page through the circuit, the metal rod moves to the right with speed \(v\). The initial current flowing in the circuit is \(I\).
What are the direction of the current in the circuit and the initial force acting on the metal rod?
 Direction of IInitial force on the metal rod
(A)anti-clockwise\(BIL \sin(90^{\circ})\)
(B)clockwise\(BIL \sin(90^{\circ})\)
(C)anti-clockwise\(BIL \sin(0^{\circ})\)
(D)clockwise\(BIL \sin(0^{\circ})\)
▶️ Answer/Explanation

The magnetic force on the rod is \(F = BIL\sin\theta\). Here the rod (current direction) is perpendicular to \(B\) (out of the page), so \(\theta=90^\circ\) and \(F = BIL\sin(90^\circ)\).
For the rod to be pushed to the right by \(\vec{F}=I\vec{L}\times\vec{B}\) with \(\vec{B}\) out of the page, the current in the rod must be upward, which corresponds to an anti-clockwise current around the circuit.

Answer: (A)

Question

Wire XY moves perpendicular to a magnetic field in the direction shown.
Wire XY moving in a magnetic field
The graph shows the variation with time of the displacement of XY.
Displacement–time graph
What is the graph of the electromotive force \(\varepsilon\) induced across \(\mathrm{XY}\)?
Possible emf–time graphs
▶️ Answer/Explanation
Detailed solution

When a straight conductor of length \(L\) moves with speed \(v\) perpendicular to a uniform magnetic field \(B\), an emf is induced given by:
\[ \varepsilon = B L v \]

Hence, the induced emf is directly proportional to the velocity of the wire.

The given graph is a displacement–time graph. The velocity of the wire at any instant is equal to the gradient of this graph.

From \(0\) to \(t_1\), the gradient increases, so the velocity increases and the induced emf increases.
From \(t_1\) to \(t_2\), the gradient is constant, so the velocity and emf are constant.
After \(t_2\), the gradient decreases to zero, so the velocity and emf decrease to zero.

Relation between velocity and induced emf

The direction of motion does not reverse, so the emf does not change sign. The correct emf–time graph therefore rises, remains constant, and then falls to zero.

Answer: (C)

Question

Which law is equivalent to the law of conservation of energy?
A. Coulomb’s law
B. Ohm’s law
C. Newton’s first law
D. Lenz’s law
▶️ Answer/Explanation
Detailed solution

Lenz’s law states that the direction of an induced emf and the resulting current is such that it opposes the change in magnetic flux that produces it.

This opposition ensures that energy is not created from nothing. Any induced current requires work to be done by an external agent, and this work is converted into electrical energy.

If the induced current were to assist the change in flux rather than oppose it, energy would be produced without any external work, violating the law of conservation of energy.

Therefore, Lenz’s law is a direct consequence of the law of conservation of energy.

Answer: (D)

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