A lawyer’s rank depends on the number of cases they have won.
The information about the number of cases won by each lawyer in the last four years is stored in a 2D array, casesWon, as shown in Figure 11. Rows represent the number of cases won by a lawyer, and columns represent the year.
Figure 11: An excerpt from the 2D array, casesWon
A lawyer’s rank is set to 1 only if the number of cases won by the lawyer in any two consecutive years is greater than 6.
For example: the rank for lawyer 1 will remain 0, whereas the rank for lawyer 2 will be set to 1 as the number of cases they won is greater than 6 in both 2022 and 2021.
updateLawyerRank(int[][] casesWon) to update lawyerRank for all the lawyers in the firm. The method should output a suitable message if no lawyer’s rank changes to 1. [7]The law firm can have more than one criminal lawyer. A criminal lawyer gets only criminal cases.
ArrayList of criminal cases that the law firm currently has and store all criminal cases to this array list. [3]Most-appropriate topic code
(a)
Award [7 max]
The method should use a flag to determine whether at least one lawyer’s rank has been changed. It must compare each pair of consecutive years and set the lawyer’s rank to 1 if both values are greater than 6.
public static void updateLawyerRank(int[][] casesWon)
{
boolean flag = false;
for(int i = 0; i < 20; i++)
{
for(int j = 0; j < 3; j++)
{
if(casesWon[i][j] > 6 && casesWon[i][j + 1] > 6)
{
allLawyers[i].setLawyerRank(1);
flag = true;
}
}
}
if(flag == false)
{
System.out.println("No lawyer rank was changed to 1");
}
}The inner loop stops at j < 3 because j + 1 must remain within the four year columns.
(b)
Award [3 max]
ArrayList of Case objects, for example criminalCases, to store all criminal cases.allLawyers[] array from the first lawyer to the last lawyer.lawyerType is "criminal", loop through their lawyerCases[] array.null before accessing the case.ArrayList.ArrayList<Case> criminalCases = new ArrayList<Case>();
for(int i = 0; i < allLawyers.length; i++)
{
if(allLawyers[i].getLawyerType().equals("criminal"))
{
for(int j = 0; j < allLawyers[i].getLawyerCases().length; j++)
{
if(allLawyers[i].getLawyerCases()[j] != null)
{
criminalCases.add(allLawyers[i].getLawyerCases()[j]);
}
}
}
}