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Generators and alternating current IB DP Physics Study Notes

Generators and alternating current IB DP Physics Study Notes - 2025 Syllabus

Generators and alternating current IB DP Physics Study Notes

Generators and alternating current IB DP Physics Study Notes at  IITian Academy  focus on  specific topic and type of questions asked in actual exam. Study Notes focus on IB Physics syllabus with Students should understand

  • that a uniform magnetic field induces a sinusoidal varying emf in a coil rotating within it

  • the effect on induced emf caused by changing the frequency of rotation.

Standard level and higher level: There is no standard level content.
Additional higher level: 6 hours

IB DP Physics 2025 -Study Notes -All Topics

Self-Induction

  • If moving a coil in a magnetic field induces a current and that current induces a magnetic field, then the induced magnetic field will also have an effect on the coil’s own induced current.
  • This self-induction will decrease the efficiency of the generation of a voltage.
  • The self-induced emf produced is also known as “back-emf”. The effects of back-emf are more significant at higher currents so it needs to be considered as part of the design parameters.

Example: 

A coil of wire is connected to a battery. When the switch is closed, current begins to flow, but it takes a moment to reach full value. Why?

▶️ Answer/Explanation

∙ When current starts flowing, the changing current induces a changing magnetic field.

∙ This changing magnetic field induces a self-emf (called back-emf) that opposes the original change in current (Lenz’s Law).

∙ This slows the rate at which the current increases, delaying the time it takes to reach steady-state.

Alternating Current (AC) Generators

∙ Recall Faraday’s law:

∙ From the formula we see that there are three ways to increase the induced emf of a rotating coil:
(1) Increase the number of turns \( N \) in the coil.
(2) Increase the flux change \( \Delta\Phi \).
(3) Decrease the time \( \Delta t \) over which the flux changes.

FYI

∙ Recall that \( \Phi = BA \cos \theta \). Given the uniform magnetic field and rotating coil, \( B \) and \( A \) are constant. Thus the flux change \( \Delta \Phi \) will be due only to the change in angle \( \Delta \theta \).

Example:

List three ways a power plant could increase the emf produced by its turbine-driven generator.

▶️ Answer/Explanation
  • Increase the number of turns \( N \) of the wire coil.
  • Use stronger magnets to increase magnetic field strength \( B \).
  • Spin the turbine faster to reduce \( \Delta t \), increasing rate of change of flux.

Alternating Current (AC) Generators – Flux and emf Variation

∙ Consider the rectangular loop of wire made to rotate in the fixed magnetic field:

  • At this instant: \( \Phi = BA \cos 0^\circ = BA \)
  • Later when \( \theta = 45^\circ \): \( \Phi = BA \cos 45^\circ = 0.7BA \)
  • When \( \theta = 90^\circ \): \( \Phi = BA \cos 90^\circ = 0 \)
  • As \( \theta \) continues, \( \Phi \) becomes negative → sinusoidal variation emerges

∙ Since \( \varepsilon = -\frac{\Delta \Phi}{\Delta t} \), the induced emf is the negative slope of the flux.
∙ Slope of cosine graph is a sine graph → \( \varepsilon \propto BA \sin \theta \)

This is the basis for how rotating coils in magnetic fields generate AC current.

Example:

A rectangular coil rotates in a magnetic field and produces a sinusoidal emf. If the maximum emf is \( 10 \, \text{V} \), what is the emf when the angle \( \theta = 30^\circ \)?

▶️ Answer/Explanation

\( \varepsilon = \varepsilon_{\text{max}} \sin \theta = 10 \sin(30^\circ) = 10 \times 0.5 = \boxed{5 \, \text{V}} \)

IB Physics Generators and alternating current Exam Style Worked Out Questions

Question

An ac generator rotating with period T is placed into a circuit with a resistor, a diode, and a capacitor.

▶️Answer/Explanation

Ans B

Question

A single loop of wire of resistance $10 \Omega$ has its plane perpendicular to a changing magnetic field.
The graph shows the variation with time of the magnetic flux linked through the loop of wire.

What is the maximum current in the loop of wire?
A. $1.0 \mathrm{~A}$
B. $2.0 \mathrm{~A}$
C. $4.0 \mathrm{~A}$
D. $20 \mathrm{~A}$

▶️Answer/Explanation

Ans:B

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