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IB DP Biology Mock Exam HL Paper 1B Set 5 - 2025 Syllabus

IB DP Biology Mock Exam HL Paper 1B Set 5

Prepare for the IB DP Biology Exam with our comprehensive IB DP Biology Exam Mock Exam HL Paper 1B Set 5. Test your knowledge and understanding of key concepts with challenging questions covering all essential topics. Identify areas for improvement and boost your confidence for the real exam

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Question 

The micrograph shows a buttercup (Ranunculus bulbosus) stem viewed in transverse section. Region T has been enlarged below to illustrate the internal tissues more clearly.
(a) In the right-hand box, draw a labelled plan diagram of region T to show the layout of tissues. [3]
(b)(i) Determine the actual thickness of the stem along line AB, given the image has been magnified 100×. [1]
(b)(ii) Describe how the true thickness of the stem could be measured using a microscope fitted with an eyepiece graticule. [1]
(c) Give one way in which plants can protect themselves against herbivores. [1]
(d) Describe two adaptations of desert plants’ leaves that help them survive in hot, dry environments. [2]
▶️ Answer/Explanation

(a)
A correct plan diagram should include the following labelled tissues (no individual cells shown):
• vascular bundle
• xylem
• phloem
• epidermis
• cortex

The vascular bundles should be positioned near the outer edge, with the cortex outside them and the epidermis forming the outermost layer.

(b)(i)
To find the real thickness:
• Measure AB on the printed image (for example, suppose AB = 45 mm).
• Divide by the magnification (100×).

Example calculation:
If measured AB = 45 mm:
Actual thickness = \( \frac{45\ \text{mm}}{100} = 0.45\ \text{mm} \)
Which is also:
0.045 cm or 450 μm.

Any value in the acceptable range of 0.42–0.47 mm (420–470 μm) gains credit.

(b)(ii)
• Count how many eyepiece graticule divisions span the stem’s thickness.
• Use the calibrated value of one division (from the stage micrometer).
• Multiply the number of divisions by the micrometre value per division.

Alternatively: determine the true length of one graticule unit, then multiply by the number of units covering the stem.

(c)
One valid defence strategy:
• sharp structures such as spines or thorns
OR • chemical defences (toxins, secondary compounds, irritants)

(d)
Two correct adaptations with explanation may include:
• a thick waxy cuticle — reduces evaporation and water loss
• small leaves or spines — decreases surface area for transpiration
• sunken stomata or hairy surfaces — trap moist air and lower water loss
• rolled leaves — keep humidity close to the surface
• succulent tissues — store water for drought periods
• CAM photosynthesis — stomata open at night to reduce water loss

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