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IBDP Chemistry -Reactivity 1.3 Energy from fuels - IB Style Questions For SL Paper 2 -FA 2025

Question

Ethanol is a biofuel that can be made from glucose. Glucose is formed by the biological fixation of carbon through photosynthesis.
(a) (i) State the equation for photosynthesis.
(ii) Outline two advantages of using ethanol as a fuel instead of gasoline (petrol).
(b) Calculate the increase in temperature of a sample of 500.0 cm3 of water heated by the combustion of 4.00 g of ethanol. Use sections 2 and 14 of the data booklet.
(Section 2: specific heat capacity of water, c = 4.18 J g−1 K−1.)
(Section 14: standard enthalpy of combustion of ethanol, ΔH°c(ethanol) = −1367 kJ mol−1.)

Most-appropriate topic codes (IB Chemistry 2025):

Reactivity 1.3:parts (a)(i), (a)(ii)
Reactivity 1.1:part (b)
Reactivity 1.2:part (b)
▶️ Answer/Explanation

(a)(i)
The balanced equation for photosynthesis is:
\( 6\text{CO}_2(g) + 6\text{H}_2\text{O}(l) \rightarrow \text{C}_6\text{H}_{12}\text{O}_6(aq) + 6\text{O}_2(g) \)
\(\boxed{6\text{CO}_2 + 6\text{H}_2\text{O} \rightarrow \text{C}_6\text{H}_{12}\text{O}_6 + 6\text{O}_2}\)

(a)(ii)
Any two of the following advantages:
1. Renewable/Sustainable: Ethanol is produced from plant biomass, unlike finite fossil fuels. ✓
2. Lower Carbon Footprint: The CO₂ released during combustion is roughly equal to the CO₂ absorbed by the plants during growth, making it closer to carbon neutral. ✓
3. Reduced Sulfur Emissions: Produces less sulfur dioxide, leading to less acid rain compared to gasoline. ✓
4. Biodegradable/Less Toxic: Generally less harmful to the environment if spilled than gasoline. ✓
Two valid advantages.

(b)
1. Find the energy released from combusting 4.00 g of ethanol.
• Molar mass of ethanol (C₂H₅OH) = (2×12.01) + (6×1.01) + 16.00 = 46.08 g mol⁻¹
• Moles of ethanol = \( \frac{4.00}{46.08} = 0.0868 \, \text{mol} \)
• From data booklet (Section 14), the standard enthalpy of combustion of ethanol (ΔH°c) is –1367 kJ mol⁻¹.
• Energy released, Q = \( 0.0868 \times 1367 = 118.6 \, \text{kJ} = 118600 \, \text{J} \) ✓
2. Calculate the temperature increase of the water.
• Mass of water = 500.0 g (since density of water ~1 g cm⁻³)
• Specific heat capacity of water (from data booklet, Section 2), c = 4.18 J g⁻¹ K⁻¹
• Using Q = mcΔT
• \( \Delta T = \frac{Q}{mc} = \frac{118600}{500.0 \times 4.18} = 56.8 \, \text{K} \) ✓
\(\boxed{56.8}\) K (or °C)

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