IBDP Chemistry -Structure 1.2 The nuclear atom - IB Style Questions For SL Paper 2 -FA 2025
Question
Iron has three main naturally occurring isotopes which can be investigated using a mass spectrometer.
A sample of iron has the following isotopic composition by mass.
| Isotope | \(^{54}\mathrm{Fe}\) | \(^{56}\mathrm{Fe}\) | \(^{57}\mathrm{Fe}\) |
|---|---|---|---|
| Relative abundance / % | 5.95 | 91.88 | 2.17 |
a. Calculate the relative atomic mass of iron based on this data, giving your answer to two decimal places. [2]
b. Calculate the number of electrons in the ion \(^{56}\mathrm{Fe}^{2+}\). [1]
c. Describe the bonding in iron and explain the electrical conductivity and malleability of the metal. [4]
Most-appropriate topic codes (IB Chemistry 2025):
• Structure 1.1: Introduction to the particulate nature of matter — part a
• Structure 1.2: Atomic structure and electron configuration — part b
• Structure 2.1: Metallic bonding and properties — part c
• Structure 1.2: Atomic structure and electron configuration — part b
• Structure 2.1: Metallic bonding and properties — part c
▶️ Answer/Explanation
Detailed solution
a. [2]
\[ \text{Relative atomic mass} = \frac{(54 \times 5.95) + (56 \times 91.88) + (57 \times 2.17)}{100} \] \[ = 55.90 \]
b. [1]
Iron has atomic number \(26\).
The ion \(^{56}\mathrm{Fe}^{2+}\) has lost two electrons.
Number of electrons \(= 26 – 2 = \mathbf{24}\).
c. [4]
Iron exhibits metallic bonding, consisting of a lattice of positive metal ions surrounded by a sea of delocalized electrons.
Electrical conductivity: The delocalized electrons are free to move through the lattice and carry charge.
Malleability: Layers of metal ions can slide past each other without breaking the metallic bonds because the attraction between ions and electrons remains.
