Home / IB DP / Chemistry / SL / Exam Style Questions / S 2.2 The covalent model SL Paper 1

IBDP Chemistry - Structure 2.2 The covalent model- IB Style Questions For SL Paper 1A - FA 2025

Question

The four labelled diagrams \(W\), \(X\), \(Y\) and \(Z\) represent stable allotropes of carbon. Which row in the table correctly matches each structure with graphene, fullerene, graphite and diamond?
 GrapheneFullereneGraphiteDiamond
AZYXW
BWZYX
CXWZY
DYXWZ
▶️ Answer/Explanation
Detailed solution

1. Identify each allotrope from its structure:
– \(W\): three-dimensional tetrahedral lattice of carbon atoms \(\Rightarrow\) diamond (\(\text{sp}^3\) hybridization).
– \(X\): stacked layers of hexagonal sheets with weak forces between layers \(\Rightarrow\) graphite (\(\text{sp}^2\) hybridization).
– \(Y\): roughly spherical cage of carbon atoms (e.g. \(\text{C}_{60}\)) \(\Rightarrow\) a fullerene.
– \(Z\): single extended hexagonal sheet of carbon atoms \(\Rightarrow\) graphene.

2. Match to the table:
Graphene \(\Rightarrow Z\)
Fullerene \(\Rightarrow Y\)
Graphite \(\Rightarrow X\)
Diamond \(\Rightarrow W\)

This pattern appears in row A.

Answer: (A)

Question

In which molecule does the central atom have an incomplete octet of electrons?
A. \(\;\text{H}_2\text{Se}\)
B. \(\;\text{PH}_3\)
C. \(\;\text{OF}_2\)
D. \(\;\text{BF}_3\)
▶️ Answer/Explanation
Detailed solution

An incomplete octet means the central atom has fewer than \(8\) electrons in its valence shell in the Lewis structure.

For \(\text{H}_2\text{Se}\), \(\text{PH}_3\) and \(\text{OF}_2\), the central atoms (Se, P, and O) each have \(8\) electrons in their valence shell (bonding pairs plus lone pairs), so they obey the octet rule.

In \(\text{BF}_3\), boron is the central atom. It forms three single bonds with fluorine: \[ \text{B} – \text{F}_3 \] This gives boron only \(3 \times 2 = 6\) valence electrons around it, not \(8\), so boron has an incomplete octet.

Therefore, the molecule with a central atom that has an incomplete octet is \(\text{BF}_3\).

Answer: (D)

Question

What is the electron domain geometry of sulfur dioxide, \(\text{SO}_2\)?
A. bent
B. linear
C. tetrahedral
D. trigonal planar
▶️ Answer/Explanation
Detailed solution

In \(\text{SO}_2\), sulfur is the central atom. It is bonded to two oxygen atoms and has one lone pair of electrons.

The electron domains around sulfur are therefore:

  • Two bonding domains (the two \(\text{S–O}\) bonds).
  • One non-bonding domain (one lone pair).

That gives a total of \(3\) electron domains around sulfur. According to VSEPR theory, \(3\) electron domains arrange themselves in a trigonal planar electron domain geometry.

(Note: the molecular shape of \(\text{SO}_2\) is bent, but the electron domain geometry is trigonal planar.)

Answer: (D)

Scroll to Top