IB DP Chemistry - R3.1.12 The pH of a salt solution - Study Notes - New Syllabus - 2026, 2027 & 2028
IB DP Chemistry – R3.1.12 The pH of a salt solution – Study Notes – New Syllabus
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Reactivity 3.1.12 — The pH of a salt solution
Reactivity 3.1.12 — The pH of a Salt Solution
- When an acid reacts with a base, a salt and water are formed in what is called a neutralization reaction.
- However, the term “neutralization” refers only to the stoichiometry of H+ and OH– reacting in equal amounts, and does not guarantee that the resulting solution is neutral in pH.
- In fact, the resulting salt solution can be acidic, basic, or neutral, depending on the nature of the acid and base from which the salt is derived.
Understanding how salts affect pH requires knowledge of conjugate acid-base pairs and hydrolysis.
- In aqueous solution, the ions from a salt may interact with water molecules in a process called hydrolysis. During hydrolysis, ions may react with water to either produce H+ (or H3O+) or OH–, thereby altering the pH of the solution.
- Whether hydrolysis occurs depends on the strength of the parent acid and base that formed the salt. More precisely, it depends on whether the resulting ions (from salt dissociation) are weak enough to act as Bronsted-Lowry acids or bases and react with water.
Key Concept:
Only the conjugate base of a weak acid and the conjugate acid of a weak base undergo significant hydrolysis in water. The conjugates of strong acids or strong bases are extremely weak and do not react appreciably with water.
Therefore, the pH of a salt solution depends on:
1. Whether the cation of the salt is a conjugate acid of a weak base
2. Whether the anion of the salt is a conjugate base of a weak acid
3. The relative strengths of these conjugate species (Ka and Kb values) if both are weak
Case-by-Case Explanation:
1. Salt of a strong acid and a strong base (e.g., NaCl):
HCl is a strong acid and NaOH is a strong base. The salt formed, NaCl, dissociates completely into Na+ and Cl–. These ions are spectator ions. Neither ion reacts with water to change the pH. Therefore, the solution remains neutral, with pH ≈ 7.
2. Salt of a strong acid and a weak base (e.g., NH4Cl):
HCl is a strong acid and NH3 is a weak base. The salt formed, NH4Cl, dissociates into NH4+ and Cl–. Cl– does not hydrolyze, but NH4+ is the conjugate acid of NH3. It hydrolyzes as follows:
NH4+ + H2O ⇌ NH3 + H3O+
This increases [H3O+], lowering the pH, making the solution acidic.
3. Salt of a weak acid and a strong base (e.g., CH3COONa):
CH3COOH is a weak acid and NaOH is a strong base. The salt CH3COONa dissociates into CH3COO– and Na+. Na+ does not hydrolyze, but CH3COO– is the conjugate base of CH3COOH. It hydrolyzes as follows:
CH3COO– + H2O ⇌ CH3COOH + OH–
This increases [OH–], raising the pH, making the solution basic.
4. Salt of a weak acid and a weak base (e.g., NH4CH3COO):
NH4+ is the conjugate acid of NH3 (weak base) and CH3COO– is the conjugate base of CH3COOH (weak acid). Both ions hydrolyze in water:
NH4+ + H2O ⇌ NH3 + H3O+
CH3COO– + H2O ⇌ CH3COOH + OH–
The final pH of the solution depends on the relative values of Ka for NH4+ and Kb for CH3COO–. If Ka > Kb, solution is acidic; if Ka < Kb, solution is basic; if Ka ≈ Kb, solution is neutral.
Table — How Parent Acid and Base Strength Influence Salt Solution pH
Parent Acid | Parent Base | Example Salt | pH Prediction | Why? |
---|---|---|---|---|
Strong | Strong | NaCl | pH ≈ 7 | No ions hydrolyze |
Strong | Weak | NH4Cl | pH < 7 | NH4+ donates H+ |
Weak | Strong | CH3COONa | pH > 7 | CH3COO– accepts H+ |
Weak | Weak | NH4CH3COO | Variable | Both ions hydrolyze |
How a salt affects the pH of its solution, we must analyze how its constituent ions behave in water. This involves:
- Dissociating the salt into its ions
- Identifying if the ions are conjugates of weak acids or weak bases
- Constructing the hydrolysis equations for the ions that react with water
- Predicting whether the ion produces H3O+ (acidic), OH– (basic), or neither (neutral)
Only ions that are conjugates of weak acids or weak bases undergo hydrolysis.
Hydrolysis Behavior of Common Ions:
Ion | Acts as | Hydrolysis Equation | Effect on pH |
---|---|---|---|
NH4+ | Weak acid (conjugate of NH3) | \( \text{NH}_4^+ + \text{H}_2\text{O} \rightleftharpoons \text{NH}_3 + \text{H}_3\text{O}^+ \) | Acidic (pH < 7) |
CH3COO– | Weak base (conjugate of CH3COOH) | \( \text{CH}_3\text{COO}^- + \text{H}_2\text{O} \rightleftharpoons \text{CH}_3\text{COOH} + \text{OH}^- \) | Basic (pH > 7) |
CO32– | Weak base (conjugate of HCO3–) | \( \text{CO}_3^{2-} + \text{H}_2\text{O} \rightleftharpoons \text{HCO}_3^- + \text{OH}^- \) | Basic (pH > 7) |
HCO3– | Amphiprotic (can act as acid or base) | Acid: \( \text{HCO}_3^- + \text{H}_2\text{O} \rightleftharpoons \text{CO}_3^{2-} + \text{H}_3\text{O}^+ \) Base: \( \text{HCO}_3^- + \text{H}_2\text{O} \rightleftharpoons \text{H}_2\text{CO}_3 + \text{OH}^- \) | Usually slightly basic, depends on Ka vs Kb |
Na+, K+, Cl–, NO3– | Spectator ions (from strong acid or base) | No hydrolysis | Neutral (pH ≈ 7) |
Step-by-Step Process for Determining pH Effect of a Salt:
- Write the formula of the salt and dissociate it into its ions.
- Identify the origin (parent acid/base) of each ion.
- Determine if the ion is a conjugate of a weak acid or base.
- If so, write the hydrolysis equation and identify if it produces H3O+ or OH–.
- Conclude whether the solution is acidic, basic, or neutral.
Example
Predict whether a solution of ammonium chloride (NH4Cl) is acidic, basic, or neutral. Write the hydrolysis equation for the relevant ion.
▶️Answer/Explanation
- NH4Cl is a salt of HCl (strong acid) and NH3 (weak base).
- Cl– is a spectator ion and does not react with water.
- NH4+ is the conjugate acid of a weak base and undergoes hydrolysis:
- \( \text{NH}_4^+ + \text{H}_2\text{O} \rightleftharpoons \text{NH}_3 + \text{H}_3\text{O}^+ \)
- Produces H3O+ → solution is acidic
Example
Predict the pH of a solution of ammonium ethanoate and write the hydrolysis equations for both ions.
▶️Answer/Explanation
- Salt of weak acid (CH3COOH) and weak base (NH3)
- Dissociates as: CH3COONH4 → NH4+ + CH3COO–
- Both ions hydrolyze:
NH4+ (acidic): \( \text{NH}_4^+ + \text{H}_2\text{O} \rightleftharpoons \text{NH}_3 + \text{H}_3\text{O}^+ \)
CH3COO– (basic): \( \text{CH}_3\text{COO}^- + \text{H}_2\text{O} \rightleftharpoons \text{CH}_3\text{COOH} + \text{OH}^- \)
- Since both ions hydrolyze, pH depends on Ka of NH4+ and Kb of CH3COO–
- If Ka = Kb, solution is neutral
- If Ka > Kb → acidic; if Kb > Ka → basic
- In most cases, CH3COO– is slightly stronger than NH4+ → solution is slightly basic
Amphiprotic Ions (e.g., HCO3–):
HCO3– can both donate and accept protons, leading to two possible hydrolysis reactions:
- As an acid: \( \text{HCO}_3^- + \text{H}_2\text{O} \rightleftharpoons \text{CO}_3^{2-} + \text{H}_3\text{O}^+ \)
- As a base: \( \text{HCO}_3^- + \text{H}_2\text{O} \rightleftharpoons \text{H}_2\text{CO}_3 + \text{OH}^- \)
The net pH depends on the relative Ka and Kb values. In most cases, the basic nature slightly dominates, and the solution is weakly basic.
Example
Predict the effect of NaHCO3 on the pH of water and construct both hydrolysis reactions for the HCO3– ion.
▶️Answer/Explanation
- NaHCO3 dissociates as: NaHCO3 → Na+ + HCO3–
- Na+ is a spectator ion (from strong base NaOH).
- HCO3– is amphiprotic (from H2CO3, a weak acid):
As an acid:
\( \text{HCO}_3^- + \text{H}_2\text{O} \rightleftharpoons \text{CO}_3^{2-} + \text{H}_3\text{O}^+ \)
As a base:
\( \text{HCO}_3^- + \text{H}_2\text{O} \rightleftharpoons \text{H}_2\text{CO}_3 + \text{OH}^- \)
- Compare Ka and Kb: HCO3– tends to behave more as a base, producing OH–
- Therefore, the solution is weakly basic
Conclusion:
- The pH of a salt solution is determined by whether its ions hydrolyze in water.
- Conjugates of weak acids produce OH– (basic), while conjugates of weak bases produce H3O+ (acidic).
- Spectator ions from strong acids/bases do not affect pH.
- If both ions hydrolyze, compare \( K_a \) and \( K_b \) to predict whether the solution is acidic or basic.