IB DP Chemistry - R3.1.3 Amphiprotic species - Study Notes - New Syllabus - 2026, 2027 & 2028
IB DP Chemistry – R3.1.3 Amphiprotic species – Study Notes – New Syllabus
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Reactivity 3.1.3 – Amphiprotic Species
Reactivity 3.1.3 – Amphiprotic Species
An amphiprotic species is a substance that can act as both a Brønsted–Lowry acid (proton donor) and a Brønsted–Lowry base (proton acceptor).
This dual behavior depends on the reaction conditions and the other species present in the system.
Key Characteristics
- They must contain at least one hydrogen atom that can be donated as \( \text{H}^+ \) and also a lone pair to accept a proton.
- Their role in a reaction (acid or base) is determined by the nature of the other reactant (whether it is a stronger acid or base).
Common Amphiprotic Species
- \( \text{H}_2\text{O} \): can donate \( \text{H}^+ \) to become OH⁻, or accept \( \text{H}^+ \) to become \( \text{H}_3\text{O}^+ \)
- \( \text{HSO}_4^- \): can donate a proton to form \( \text{SO}_4^{2-} \), or accept a proton to form \( \text{H}_2\text{SO}_4 \)
- \( \text{HCO}_3^- \): can donate \( \text{H}^+ \) to form \( \text{CO}_3^{2-} \), or accept a proton to form \( \text{H}_2\text{CO}_3 \)
Water acting as a Brønsted–Lowry acid:
- \( \text{H}_2\text{O} + \text{NH}_3 \rightarrow \text{OH}^- + \text{NH}_4^+ \)
- Water donates a proton (H⁺) to ammonia → acts as an acid.
Water acting as a Brønsted–Lowry base:
- \( \text{H}_2\text{O} + \text{HCl} \rightarrow \text{H}_3\text{O}^+ + \text{Cl}^- \)
- Water accepts a proton (H⁺) from hydrochloric acid → acts as a base.
Amphiprotic Behavior in Equilibrium
- In acid–base equilibria, amphiprotic species can appear on both sides of the equation, forming conjugate acid–base pairs with different reactants.
- Their ability to shift between roles makes them essential in buffer systems and many biological processes.
Interpreting and Formulating Equations with Amphiprotic Species
- To demonstrate the amphiprotic nature of a species, write two equations:
- One where it acts as a Brønsted–Lowry acid (donates a proton).
- One where it acts as a Brønsted–Lowry base (accepts a proton).
Step-by-Step Process
- Identify the amphiprotic species (e.g., \( \text{HCO}_3^- \), \( \text{H}_2\text{O} \)).
- Choose one species it could donate a proton to (weaker base), and one it could accept a proton from (stronger acid).
- Write both reactions and identify the conjugate pairs.
Difference between Amphiprotic and Amphoteric:
- Amphiprotic: A species is amphiprotic if it can both donate a proton (act as an acid) and accept a proton (act as a base) in different reactions. This is strictly within the Brønsted–Lowry theory of acids and bases.
Examples:
- \( \text{H}_2\text{O} \): can become \( \text{OH}^- \) (acid) or \( \text{H}_3\text{O}^+ \) (base)
- \( \text{HCO}_3^- \): can become \( \text{CO}_3^{2-} \) or \( \text{H}_2\text{CO}_3 \)
- Amphoteric: A species is amphoteric if it can act as either an acid or a base, but this definition is broader — it includes reactions outside proton transfer, such as Lewis acid–base behavior.
Examples:
- Metal oxides like \( \text{Al}_2\text{O}_3 \): react with both acids and bases but do not involve proton transfer
- \( \text{Zn(OH)}_2 \): dissolves in both acidic and basic solutions
Note:
All amphiprotic species are amphoteric (because proton transfer is one kind of acid–base behavior), but not all amphoteric species are amphiprotic (since some do not involve H⁺).
Example
Show that \( \text{HSO}_4^- \) is an amphiprotic species by writing two reactions.
▶️Answer/Explanation
1. Acting as an acid (proton donor):
\( \text{HSO}_4^-(aq) + \text{OH}^-(aq) \rightleftharpoons \text{SO}_4^{2-}(aq) + \text{H}_2\text{O}(l) \)
Here, HSO₄⁻ donates a proton to OH⁻, forming SO₄²⁻ → HSO₄⁻ acts as a Brønsted–Lowry acid.
2. Acting as a base (proton acceptor):
\( \text{HSO}_4^-(aq) + \text{H}_3\text{O}^+(aq) \rightleftharpoons \text{H}_2\text{SO}_4(aq) + \text{H}_2\text{O}(l) \)
Here, HSO₄⁻ accepts a proton from H₃O⁺ to form H₂SO₄ → HSO₄⁻ acts as a Brønsted–Lowry base.
These two reactions show that \( \text{HSO}_4^- \) can both donate and accept a proton, confirming it is an amphiprotic species.
Example
Show that aluminum oxide \( \text{Al}_2\text{O}_3 \) is amphoteric but not amphiprotic.
▶️Answer/Explanation
1. Acting as a base (reacting with acid):
\( \text{Al}_2\text{O}_3 + 6\text{HCl} \rightarrow 2\text{AlCl}_3 + 3\text{H}_2\text{O} \)
Al₂O₃ reacts with HCl to form aluminum chloride — it accepts protons indirectly (via Lewis acid–base reaction).
2. Acting as an acid (reacting with base):
\( \text{Al}_2\text{O}_3 + 2\text{NaOH} + 3\text{H}_2\text{O} \rightarrow 2\text{Na[Al(OH)}_4] \)
Al₂O₃ reacts with NaOH to form a soluble aluminate complex — it acts as a Lewis acid.
These reactions show that \( \text{Al}_2\text{O}_3 \) can behave as an acid or a base depending on the other reactant, making it amphoteric.
However, no proton transfer (H⁺) is involved — therefore, it is not amphiprotic.
Example
Compare the behavior of \( \text{Zn(OH)}_2 \) and \( \text{HCO}_3^- \) in acid–base reactions. Why is only one considered amphiprotic?
▶️Answer/Explanation
\( \text{Zn(OH)}_2 \) reacts with both acids and bases:
With acid: \( \text{Zn(OH)}_2 + 2\text{HCl} \rightarrow \text{ZnCl}_2 + 2\text{H}_2\text{O} \)
With base: \( \text{Zn(OH)}_2 + 2\text{OH}^- \rightarrow [\text{Zn(OH)}_4]^{2-} \)
→ This makes Zn(OH)₂ amphoteric, but no proton transfer occurs → not amphiprotic.
\( \text{HCO}_3^- \) also reacts with both acids and bases:
With base: \( \text{HCO}_3^- + \text{OH}^- \rightarrow \text{CO}_3^{2-} + \text{H}_2\text{O} \)
With acid: \( \text{HCO}_3^- + \text{H}_3\text{O}^+ \rightarrow \text{H}_2\text{CO}_3 + \text{H}_2\text{O} \)
→ In both cases, H⁺ is transferred → amphiprotic and also amphoteric.
Conclusion: Both are amphoteric, but only \( \text{HCO}_3^- \) meets the Brønsted–Lowry definition of an amphiprotic species.