IB DP Chemistry - R3.1.6 Strong and weak acids and bases- Study Notes - New Syllabus - 2026, 2027 & 2028
IB DP Chemistry – R3.1.6 Strong and weak acids and bases – Study Notes – New Syllabus
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Reactivity 3.1.6 – Strong and Weak Acids and Bases
Reactivity 3.1.6 – Strong and Weak Acids and Bases
Introduction to Ionization in Acids and Bases
- Acids and bases are classified as strong or weak depending on the extent to which they ionize (dissociate) in aqueous solution.
- Ionization refers to the process where an acid or base releases ions into solution, forming an equilibrium between the undissociated species and its ions.
- Strong acids and bases ionize almost completely; weak acids and bases ionize only partially, reaching a dynamic equilibrium.
Strong Acids
- A strong acid completely ionizes in water — nearly all acid molecules donate protons (H⁺) to water molecules.
- This means the concentration of hydrogen ions \( [\text{H}^+] \) is nearly equal to the concentration of the acid itself.
- The reaction goes essentially to completion with negligible reverse reaction:
- \( \text{HA}(aq) + \text{H}_2\text{O}(l) \rightarrow \text{H}_3\text{O}^+(aq) + \text{A}^-(aq) \)
Examples of strong acids:
- Hydrochloric acid – HCl
- Hydrobromic acid – HBr
- Hydroiodic acid – HI
- Nitric acid – HNO₃
- Sulfuric acid – H₂SO₄ (only the first proton is fully ionized)
Strong Bases
- Strong bases also fully dissociate in aqueous solution, releasing hydroxide ions \( \text{OH}^- \).
- These substances readily accept protons and shift the equilibrium far toward products.
- Group 1 hydroxides are the most common examples of strong bases in IB Chemistry.
Examples:
- Sodium hydroxide – NaOH
- Potassium hydroxide – KOH
- Rubidium hydroxide – RbOH
- Cesium hydroxide – CsOH
Weak Acids
- Weak acids partially ionize in solution and establish an equilibrium between the ionized and non-ionized forms.
- This means only a small fraction of the acid molecules donate H⁺ ions.
- The equilibrium lies to the left (towards the undissociated acid).
- \( \text{HA}(aq) + \text{H}_2\text{O}(l) \rightleftharpoons \text{H}_3\text{O}^+(aq) + \text{A}^-(aq) \)
Examples of weak acids:
- Ethanoic acid – CH₃COOH
- Carbonic acid – H₂CO₃
- Phosphoric acid – H₃PO₄
- Hydrofluoric acid – HF
Weak Bases
- Weak bases only partially accept protons in aqueous solution and also reach a state of equilibrium.
- This results in a relatively low concentration of OH⁻ in solution.
Examples:
- Ammonia – NH₃
- Methylamine – CH₃NH₂
- Pyridine – C₅H₅N
Key Differences Between Strong and Weak Acids/Bases
Property | Strong Acid/Base | Weak Acid/Base |
---|---|---|
Extent of ionization | Fully ionizes in water | Partially ionizes |
Equilibrium position | Far to the right (products dominate) | To the left (mostly reactants) |
Electrical conductivity | High (more free ions) | Low to moderate |
Reaction with metals/carbonates | Fast and vigorous | Slower, less vigorous |
pH of equal concentration solutions | Much lower (acid) or higher (base) | Closer to neutral |
Important IB Distinction: Strength vs. Concentration
- Strength refers to the degree of ionization of an acid or base.
- Concentration refers to the amount of solute (acid/base) per unit volume of solution (mol·dm⁻³).
- It is possible to have:
- A concentrated weak acid (high amount, but only partial ionization)
- A dilute strong acid (low amount, but fully ionized)
- This distinction is frequently tested in IB questions — do not confuse them!
Example
Compare 0.10 mol·dm⁻³ HCl (strong acid) with 0.10 mol·dm⁻³ CH₃COOH (weak acid).
▶️Answer/Explanation
HCl ionizes completely: \( [\text{H}^+] \approx 0.10 \, \text{mol·dm}^{-3} \)
CH₃COOH only partially ionizes: \( [\text{H}^+] \ll 0.10 \, \text{mol·dm}^{-3} \)
Thus, the HCl solution has a much lower pH and greater conductivity.
Acid–Base Equilibria and Conjugate Strengths
Understanding Conjugate Acid–Base Pairs
- According to the Brønsted–Lowry theory, acids are proton (H⁺) donors and bases are proton acceptors.
- Every acid–base reaction involves two conjugate pairs:
- The acid and its conjugate base
- The base and its conjugate acid
Example:
\( \text{HA}(aq) + \text{H}_2\text{O}(l) \rightleftharpoons \text{H}_3\text{O}^+(aq) + \text{A}^-(aq) \)
Here:
- HA = acid, A⁻ = conjugate base
- H₂O = base, H₃O⁺ = conjugate acid
Equilibrium Favors the Weaker Conjugate
- Acid–base reactions are equilibria that lie toward the weaker acid and weaker base.
- Stronger acid/base → reacts more readily → equilibrium favors the weaker side
- If the acid is strong, its conjugate base will be weak.
- Conversely, a weak acid has a stronger conjugate base because the forward donation of a proton is less favored.
- Therefore: The direction of equilibrium is determined by comparing the relative strength of the acid and base on both sides of the reaction.
Example
Two reactions are shown below:
(A) \( \text{HCl}(aq) + \text{H}_2\text{O}(l) \rightarrow \text{H}_3\text{O}^+(aq) + \text{Cl}^-(aq) \)
(B) \( \text{CH}_3\text{COOH}(aq) + \text{H}_2\text{O}(l) \rightleftharpoons \text{CH}_3\text{COO}^-(aq) + \text{H}_3\text{O}^+(aq) \)
Compare the two equilibria. For each reaction:
- Identify the strong or weak acid.
- State the position of the equilibrium.
- Explain your reasoning based on the relative strength of the conjugate base.
▶️Answer/Explanation
- Reaction A: HCl is a strong acid → full ionization. Cl⁻ is a very weak conjugate base → equilibrium lies far to the right.
- Reaction B: CH₃COOH is a weak acid → partial ionization. CH₃COO⁻ is a relatively strong conjugate base → equilibrium lies to the left.
- Conclusion: The position of equilibrium depends on the relative strengths of conjugate bases. It favors the formation of the weaker acid–base pair.
Relative Strengths of Conjugates
Acid | Strength | Conjugate Base | Strength |
---|---|---|---|
HCl | Strong | Cl⁻ | Extremely Weak |
HNO₃ | Strong | NO₃⁻ | Very Weak |
CH₃COOH | Weak | CH₃COO⁻ | Moderate |
NH₄⁺ | Weak Acid | NH₃ | Weak Base |
Implications for IB Chemistry
- This principle helps predict the extent of proton transfer in acid–base reactions.
- It is also crucial for understanding buffer behavior, titration curves, and pKa/pKb concepts (at HL).
- Key point: If you know which species are strong and weak, you can predict the direction of the equilibrium.
Example
Which direction will the equilibrium favor in the following reaction?
\( \text{NH}_4^+(aq) + \text{H}_2\text{O}(l) \rightleftharpoons \text{NH}_3(aq) + \text{H}_3\text{O}^+(aq) \)
▶️Answer/Explanation
NH₄⁺ is a weak acid and NH₃ is a weak base. H₃O⁺ is a stronger acid than NH₄⁺.
Therefore, equilibrium favors the left — toward NH₄⁺ and H₂O, the weaker acid and weaker base.
Conclusion: The reaction lies to the left.
Comparisons of Acids and Bases with respect to Equilibrium
Acid and Equilibrium Comparison Table
Acid | Strength | Extent of Ionization | Conjugate Base | Equilibrium Position |
---|---|---|---|---|
HCl | Strong | ~100% (complete) | Cl⁻ (very weak) | Far to the right (products favored) |
HNO₃ | Strong | ~100% | NO₃⁻ (very weak) | Far to the right |
H₂SO₄ (1st ionization) | Strong | Complete for first H⁺ | HSO₄⁻ (moderate) | Right (for first dissociation) |
CH₃COOH | Weak | Partial (~5%) | CH₃COO⁻ (moderate) | Left (reactants favored) |
H₂CO₃ | Weak | Partial | HCO₃⁻ | Left |
NH₄⁺ | Weak | Partial | NH₃ (moderate) | Left |
Base and Equilibrium Comparison Table
Base | Strength | Extent of Ionization/Proton Acceptance | Conjugate Acid | Equilibrium Position |
---|---|---|---|---|
NaOH | Strong | ~100% dissociation in water | H₂O (very weak acid) | Far to the right |
KOH | Strong | Complete | H₂O | Far to the right |
NH₃ | Weak | Partial proton acceptance | NH₄⁺ (weak acid) | Left (reactants favored) |
CH₃COO⁻ | Moderate | Moderate base strength | CH₃COOH | Left |
CO₃²⁻ | Weak to moderate | Partial reaction with water | HCO₃⁻ | Left |
HSO₄⁻ | Weak base | Limited proton acceptance | H₂SO₄ | Left |
Comparison of Strong and Weak Acids
Property | Strong Acid | Weak Acid |
---|---|---|
Position of Equilibrium | Far to the right (products heavily favored) | Left (reactants favored) |
Extent of Ionization | Complete (∼100%) | Partial (typically less than 5%) |
H⁺ Ion Concentration | High (equals acid concentration) | Low (much less than acid concentration) |
pH Calculation | Directly from concentration: \( \text{pH} = -\log[\text{H}^+] \) | Requires use of Ka and ICE table |
Conjugate Base | Very weak | Moderate to strong |
Electrical Conductivity | High (more free ions) | Lower (fewer free ions) |
Examples | HCl, HNO₃, H₂SO₄, HI, HBr | CH₃COOH, H₂CO₃, HF, HCN, NH₄⁺ |
Distinguishing Between Strong and Weak Acids
- Extent of Ionization:
- Strong acids ionize completely in aqueous solution.
- Weak acids only partially ionize in water.
- Position of Equilibrium:
- Strong acids: equilibrium lies far to the right.
- Weak acids: equilibrium lies to the left.
- pH and [H⁺] Concentration:
- Strong acids: low pH (typically below 3)
- Weak acids: higher pH (around 4–6)
- Ka (Acid Dissociation Constant):
- Strong acids: very large Ka (Ka → ∞)
- Weak acids: small Ka
- Electrical Conductivity:
- Strong acids: high conductivity
- Weak acids: lower conductivity
- Reaction Rates (with metals/carbonates):
- Strong acids: fast and vigorous
- Weak acids: slower
- Experimental Distinctions:
- pH Measurement: Strong acids give a lower pH.
- Conductivity Test: Strong acids show higher conductivity.
- Rate of Gas Evolution: Strong acids bubble more rapidly with metals/carbonates.
Comparison of Strong and Weak Bases
Property | Strong Base | Weak Base |
---|---|---|
Position of Equilibrium | Far to the right | Left |
Extent of Ionization / Proton Acceptance | Complete | Partial |
OH⁻ Ion Concentration | High | Low |
pOH / pH Calculation | \( \text{pOH} = -\log[\text{OH}^-] \), \( \text{pH} = 14 – \text{pOH} \) | Requires Kb and ICE table |
Conjugate Acid | Very weak | Moderate to strong |
Electrical Conductivity | High | Lower |
Examples | NaOH, KOH, Ba(OH)₂ | NH₃, CH₃NH₂, C₆H₅NH₂ |
Example
You have two 0.1 mol·dm⁻³ solutions — one of HCl and one of CH₃COOH. Compare their pH and conductivity.
▶️Answer/Explanation
HCl is a strong acid — it dissociates completely. So, [H⁺] = 0.1 mol·dm⁻³ →
\( \text{pH} = -\log(0.1) = 1.00 \)
CH₃COOH is a weak acid — it only partially dissociates. Its [H⁺] might be around \( 1.3 \times 10^{-3} \, \text{mol·dm}^{-3} \) →
\( \text{pH} = -\log(1.3 \times 10^{-3}) ≈ 2.89 \)
Since HCl produces more free ions, it also shows higher electrical conductivity than CH₃COOH.