IB DP Chemistry - R3.2.10 Reduction of functional groups - Study Notes - New Syllabus - 2026, 2027 & 2028
IB DP Chemistry – R3.2.10 Reduction of functional groups – Study Notes – New Syllabus
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Reactivity 3.2.10 — Reduction of Organic Compounds
Reactivity 3.2.10 — Reduction of Organic Compounds
Functional groups in organic molecules can undergo reduction, which involves the gain of electrons (or hydrogen), resulting in the conversion of more oxidized groups to less oxidized ones. In the context of organic chemistry, the most common types of reductions include:
- Reduction of carboxylic acids to primary alcohols (via aldehydes)
- Reduction of ketones to secondary alcohols
Role of Hydride Ions (\( \text{H}^- \))
Reduction is commonly achieved using hydride ion donors such as \( \text{H}^- \). These hydride ions act as nucleophiles and add to the carbon of the polar C=O group in aldehydes and ketones, reducing them to alcohols.
Reduction Pathways
1. Reduction of Carboxylic Acids to Primary Alcohols
This occurs in two steps:
Step 1: Carboxylic acid to aldehyde
\( \text{RCOOH} \xrightarrow{[\text{H}]} \text{RCHO} \)
Step 2: Aldehyde to primary alcohol
\( \text{RCHO} \xrightarrow{[\text{H}]} \text{RCH}_2\text{OH} \)
Overall Reaction:
\( \text{RCOOH} \xrightarrow{[\text{H}]} \text{RCH}_2\text{OH} \)
Example:
Reduction of ethanoic acid:
\( \text{CH}_3\text{COOH} \xrightarrow{[\text{H}]} \text{CH}_3\text{CH}_2\text{OH} \)
2. Reduction of Ketones to Secondary Alcohols
Ketones are reduced in a single step:
\( \text{RCOR’} \xrightarrow{[\text{H}]} \text{RCH(OH)R’} \)
Example:
Reduction of propanone:
\( \text{CH}_3\text{COCH}_3 \xrightarrow{[\text{H}]} \text{CH}_3\text{CH(OH)}\text{CH}_3 \)
Example
Deduce the equations for the reduction of ethanoic acid to ethanol.
▶️Answer/Explanation
Step 1: \( \text{CH}_3\text{COOH} \xrightarrow{[\text{H}]} \text{CH}_3\text{CHO} \)
Step 2: \( \text{CH}_3\text{CHO} \xrightarrow{[\text{H}]} \text{CH}_3\text{CH}_2\text{OH} \)
Overall: \( \text{CH}_3\text{COOH} \xrightarrow{[\text{H}]} \text{CH}_3\text{CH}_2\text{OH} \)
Example
A student reduces propanone using a hydride ion source. Identify the product and write the equation.
▶️Answer/Explanation
Product: propan-2-ol
Equation: \( \text{CH}_3\text{COCH}_3 \xrightarrow{[\text{H}]} \text{CH}_3\text{CH(OH)}\text{CH}_3 \)