IB DP Chemistry -R3.2.13 Standard cell potential - Study Notes - New Syllabus - 2026, 2027 & 2028
IB DP Chemistry – R3.2.13 Standard cell potential – Study Notes – New Syllabus
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Reactivity 3.2.13 — Standard Cell Potential, \( E^\circ_{\text{cell}} \)
Reactivity 3.2.13 — Standard Cell Potential, \( E^\circ_{\text{cell}} \)
The standard cell potential, \( E^\circ_{\text{cell}} \), is the electromotive force (voltage) produced by a redox reaction occurring in an electrochemical (galvanic) cell under standard conditions:
- Solutions with 1 mol dm−3 concentration
- Temperature of 298 K (25 °C)
- 1 atm pressure for any gases involved
- Electrodes are connected via an external circuit and a salt bridge completes the internal circuit
Formula for Calculation:
\( E^\circ_{\text{cell}} = E^\circ_{\text{cathode}} – E^\circ_{\text{anode}} \)
OR
\( E^\circ_{\text{cell}} = E^\circ_{\text{reduction}} – E^\circ_{\text{oxidation}} \)
Interpreting \( E^\circ \) Values:
- The more positive the standard reduction potential, the greater the substance’s tendency to gain electrons (be reduced).
- The more negative the value, the more readily the species loses electrons (gets oxidized).
Spontaneity and Feasibility:
- If \( E^\circ_{\text{cell}} > 0 \): the redox reaction is spontaneous in the forward direction.
- If \( E^\circ_{\text{cell}} < 0 \): the reaction is non-spontaneous (will only proceed in the reverse direction).
Visual Layout of a Galvanic Cell:
- Anode (oxidation): Electrons are released.
- Cathode (reduction): Electrons are accepted.
- Electrons flow: From anode to cathode in the external circuit.
- Salt bridge: Maintains charge neutrality by allowing ions to migrate.
Use of the Standard Hydrogen Electrode (SHE):
All standard electrode potentials are measured relative to the SHE, which is assigned an arbitrary value of \( E^\circ = 0.00\ \text{V} \).
IB Tip: You must always use values from the IB data booklet when answering questions. Don’t memorize E° values — refer to the booklet.
Example
Calculate the standard cell potential and determine if the following reaction is spontaneous:
\( \text{Zn}^{2+} + 2e^- \rightarrow \text{Zn}(s) \quad E^\circ = -0.76\ \text{V} \)
\( \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu}(s) \quad E^\circ = +0.34\ \text{V} \)
▶️Answer/Explanation
Zn is more negative → oxidized.
Cu2+ is reduced.
Oxidation half-equation (anode): \( \text{Zn}(s) \rightarrow \text{Zn}^{2+} + 2e^- \)
Reduction half-equation (cathode): \( \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu}(s) \)
Overall: \( \text{Zn}(s) + \text{Cu}^{2+} \rightarrow \text{Zn}^{2+} + \text{Cu}(s) \)
\( E^\circ_{\text{cell}} = +0.34 – (-0.76) = +1.10\ \text{V} \)
Spontaneous in the forward direction.
Example
Determine whether the following redox reaction is spontaneous in the forward direction:
\( \text{Pb}^{2+} + 2e^- \rightarrow \text{Pb}(s) \quad E^\circ = -0.13\ \text{V} \)
\( \text{Sn}^{2+} + 2e^- \rightarrow \text{Sn}(s) \quad E^\circ = -0.14\ \text{V} \)
▶️Answer/Explanation
Pb2+ is slightly more positive → gets reduced.
Sn is oxidized.
Ox: \( \text{Sn}(s) \rightarrow \text{Sn}^{2+} + 2e^- \)
Red: \( \text{Pb}^{2+} + 2e^- \rightarrow \text{Pb}(s) \)
Overall: \( \text{Sn}(s) + \text{Pb}^{2+} \rightarrow \text{Sn}^{2+} + \text{Pb}(s) \)
\( E^\circ_{\text{cell}} = -0.13 – (-0.14) = +0.01\ \text{V} \)
Spontaneous, but very weakly.