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IB DP Chemistry – R3.2.16 Electroplating- Study Notes

IB DP Chemistry - R3.2.16 Electroplating - Study Notes - New Syllabus - 2026, 2027 & 2028

IB DP Chemistry – R3.2.16 Electroplating- Study Notes – New Syllabus

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Reactivity 3.2.16 — Electroplating

Reactivity 3.2.16 — Electroplating

 Electroplating is the process of depositing a thin layer of metal onto the surface of another material using electrolysis. It is widely used in industry to enhance appearance, prevent corrosion, reduce friction, or improve wear resistance.

Components:

  • Cathode: The object to be plated (connected to the negative terminal)
  • Anode: A rod of the metal to be plated (connected to the positive terminal) or an inert electrode
  • Electrolyte: A solution containing ions of the plating metal (e.g., CuSO₄ for copper plating)

Basic Principle: Metal cations in the solution are reduced and deposited onto the cathode. If a metal anode is used, it dissolves into the solution to maintain the ion concentration.

 Copper Electroplating

Setup: Cathode = iron spoon, Anode = copper rod, Electrolyte = aqueous \( \text{CuSO}_4 \)

Electrode Reactions:

Cathode (Reduction):

\( \text{Cu}^{2+}(aq) + 2e^- \rightarrow \text{Cu}(s) \)

Anode (Oxidation):

\( \text{Cu}(s) \rightarrow \text{Cu}^{2+}(aq) + 2e^- \)

Net Effect: Copper metal from the anode dissolves and is redeposited on the cathode surface.

Key Points:

  • The mass of metal deposited is proportional to the quantity of electricity passed (Faraday’s Laws).
  • The electrolyte must contain ions of the metal to be deposited.
  • The object being plated must be clean and conductive.

Common Electroplating Metals:

  • Copper (for electrical conductivity and aesthetics)
  • Silver (for jewelry and tableware)
  • Chromium (for corrosion resistance and shine)
  • Nickel (for wear resistance and base layer)

Factors Affecting Electroplating:

  • Current density (controls rate of deposition)
  • Temperature (affects ion mobility and coating quality)
  • Electrolyte concentration

Example 

An iron key is electroplated with silver using silver nitrate solution and a silver anode. Write the electrode equations.

▶️Answer/Explanation

Cathode (Reduction):
\( \text{Ag}^+(aq) + e^- \rightarrow \text{Ag}(s) \)

Anode (Oxidation):
\( \text{Ag}(s) \rightarrow \text{Ag}^+(aq) + e^- \)

Silver is transferred from the anode and deposited onto the iron key.

Example 

A steel spoon is plated with nickel using nickel(II) sulfate solution. Identify the electrode materials and write the overall cell setup and reactions.

▶️Answer/Explanation

Cathode: steel spoon (to be coated)
Anode: nickel metal
Electrolyte: aqueous nickel(II) sulfate

Cathode reaction:
\( \text{Ni}^{2+}(aq) + 2e^- \rightarrow \text{Ni}(s) \)

Anode reaction:
\( \text{Ni}(s) \rightarrow \text{Ni}^{2+}(aq) + 2e^- \)

Example 

A nickel spoon is electroplated with silver using an aqueous solution of silver nitrate (\( \text{AgNO}_3 \)) and a silver anode. A constant current of 1.50 A is passed for 40.0 minutes. Calculate the mass of silver deposited on the spoon.

▶️Answer/Explanation

\( Q = I \times t = 1.50\ \text{A} \times 40.0 \times 60\ \text{s} = 3600\ \text{C} \)

\( n(e^-) = \frac{Q}{F} = \frac{3600}{96500} \approx 0.0373\ \text{mol} \)

\( \text{Ag}^+(aq) + e^- \rightarrow \text{Ag}(s) \)
So 1 mol of electrons deposits 1 mol of Ag.

Moles of Ag deposited = 0.0373 mol
Mass = \( 0.0373 \times 107.87 = 4.02\ \text{g} \)

\( \boxed{4.02\ \text{g of Ag is deposited on the spoon}} \)

Example 

How long (in minutes) must a current of 2.00 A be applied to electroplate 5.85 g of nickel (\( \text{Ni} \)) onto a metal surface from an aqueous solution of nickel(II) sulfate?

▶️Answer/Explanation

Molar mass of Ni = 58.69 g/mol
\( n(\text{Ni}) = \frac{5.85}{58.69} \approx 0.0997\ \text{mol} \)

\( \text{Ni}^{2+}(aq) + 2e^- \rightarrow \text{Ni}(s) \)
So, 2 moles of electrons per mole of Ni.
Moles of \( e^- \) = \( 0.0997 \times 2 = 0.1994\ \text{mol} \)

\( Q = n(e^-) \times F = 0.1994 \times 96500 \approx 19238\ \text{C} \)

\( t = \frac{Q}{I} = \frac{19238}{2.00} = 9619\ \text{s} \)
Convert to minutes: \( \frac{9619}{60} \approx 160.3\ \text{minutes} \)

\( \boxed{160\ \text{minutes (to 3 significant figures)}} \)

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