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IB DP Chemistry – R3.2.9 Oxidation of organic compounds- Study Notes

IB DP Chemistry - R3.2.9 Oxidation of organic compounds- Study Notes - New Syllabus - 2026, 2027 & 2028

IB DP Chemistry – R3.2.9 Oxidation of organic compounds – Study Notes – New Syllabus

IITian Academy excellent Introduction to the Proton transfer reactions – Study Notes and effective strategies will help you prepare for your IB DP Chemistry  exam.

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Reactivity 3.2.9 — Oxidation of Organic Compounds

Reactivity 3.2.9 — Oxidation of Organic Compounds

Certain functional groups in organic compounds undergo oxidation reactions, particularly alcohols. These reactions result in a transformation of the functional group, depending on the type of alcohol and reaction conditions.

Types of Alcohols and Their Oxidation Behavior

  • Primary alcohols (1°) are oxidized first to aldehydes, and then to carboxylic acids under prolonged heating.
  • Secondary alcohols (2°) are oxidized to ketones.
  • Tertiary alcohols (3°) do not oxidize under typical conditions because they lack a hydrogen atom on the carbon bearing the hydroxyl group.

General Equations for Oxidation

Primary Alcohol

    • Step 1: Partial oxidation (mild conditions)

\( \text{CH}_3\text{CH}_2\text{OH} \rightarrow \text{CH}_3\text{CHO} \) (ethanol → ethanal)

    • Step 2: Full oxidation (stronger heating or excess oxidant)

\( \text{CH}_3\text{CHO} \rightarrow \text{CH}_3\text{COOH} \) (ethanal → ethanoic acid)

    • Overall (in presence of oxidizing agent):

\( \text{CH}_3\text{CH}_2\text{OH} \xrightarrow{[\text{O}]} \text{CH}_3\text{COOH} \)

Secondary Alcohol

    • Example: Propan-2-ol to propanone

\( \text{CH}_3\text{CH(OH)}\text{CH}_3 \xrightarrow{[\text{O}]} \text{CH}_3\text{COCH}_3 \)

Tertiary Alcohol

  • No oxidation under standard conditions.
  • This is due to the absence of a hydrogen atom on the carbon attached to the –OH group.

Experimental Set-ups

1. Distillation (To Obtain Aldehydes)

When oxidizing a primary alcohol to an aldehyde, the product is distilled off as it forms to prevent further oxidation.

  • Setup includes: round-bottom flask, condenser angled downward, thermometer, heat source.
  • Oxidizing agent: acidified potassium dichromate (\( \text{K}_2\text{Cr}_2\text{O}_7 \) with H2SO4)
  • Observation: Orange dichromate solution turns green as Cr6+ is reduced to Cr3+.

2. Reflux (To Complete Oxidation to Carboxylic Acid)

Refluxing allows heating for a prolonged time without losing volatile compounds, promoting full oxidation to the carboxylic acid.

  • Setup includes: round-bottom flask, vertical condenser, heat source.
  • Used for: Oxidation of aldehydes to acids or complete oxidation of primary alcohols.

Example 

A student oxidizes ethanol using acidified potassium dichromate. Describe the products formed under:

  • (a) Distillation
  • (b) Reflux
▶️Answer/Explanation

(a) Under distillation, the aldehyde formed is ethanal \( (\text{CH}_3\text{CHO}) \).
(b) Under reflux, full oxidation gives ethanoic acid \( (\text{CH}_3\text{COOH}) \).

Example 

Propan-2-ol is heated under reflux with acidified potassium dichromate. Identify the organic product and give the equation for the reaction.

▶️Answer/Explanation

The product is propanone \( (\text{CH}_3\text{COCH}_3) \).
Equation: \( \text{CH}_3\text{CH(OH)}\text{CH}_3 \xrightarrow{[\text{O}]} \text{CH}_3\text{COCH}_3 \)

Example 

Explain why tert-butanol \( (\text{CH}_3)_3\text{COH} \) does not undergo oxidation with acidified potassium dichromate.

▶️Answer/Explanation

Tertiary alcohols lack a hydrogen atom on the carbon bearing the –OH group. Oxidation requires this hydrogen for bond cleavage, so tert-butanol remains unreacted.

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