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IB DP Chemistry – S1.2.2 Isotopes- Study Notes

IB DP Chemistry -S1.2.2 Isotopes - Study Notes - New Syllabus - 2026, 2027 & 2028

IB DP Chemistry – S1.2.2 Isotopes – Study Notes – New Syllabus

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Structure 1.2.2 – Isotopes and Relative Atomic Mass

Structure 1.2.2 – Isotopes and Relative Atomic Mass

Isotopes

Isotopes are atoms of the same element that have:

    • The same number of protons (and electrons, if neutral)
    • Different number of neutrons

This means their atomic number \( Z \) is the same, but their mass number \( A \) is different.

  • Since the electron arrangement remains unchanged, all isotopes of an element have identical chemical properties.
  • However, due to the difference in mass, they may show differences in physical properties.

Physical Property Differences Between Isotopes:

  • Mass: Heavier isotopes have greater mass.
  • Density: Heavier isotopes tend to be more dense.
  • Boiling and melting points: These may be slightly higher for heavier isotopes.
  • Rate of diffusion: Lighter isotopes diffuse faster (Graham’s law of diffusion).
  • Vibrational energy (IR): Used in spectroscopy to distinguish isotopes.

 Representation of Isotopes:

Isotopes are written using nuclear notation:

\( {}^A_Z\text{X} \),

where:

  • \( A \) = mass number = number of protons + neutrons
  • \( Z \) = atomic number = number of protons
  • \( \text{X} \) = chemical symbol of the element

Example: Isotopes of hydrogen:

  • \( {}^1_1\text{H} \) – 1 proton, 0 neutrons (hydrogen-1)
  • \( {}^2_1\text{H} \) – 1 proton, 1 neutron (deuterium)
  • \( {}^3_1\text{H} \) – 1 proton, 2 neutrons (tritium)

Relative Atomic Mass (Ar):

The relative atomic mass is the weighted average mass of all isotopes of an element based on their natural abundance.

Formula:

\( A_r = \frac{(a_1 \times m_1) + (a_2 \times m_2) + \ldots}{100} \)

  • \( a_1, a_2, \ldots \) are the percentage abundances
  • \( m_1, m_2, \ldots \) are the relative masses of each isotope

Note: The resulting \( A_r \) value is usually a non-integer.

Example

Naturally occurring chlorine consists of:

  • $75\%$ \( {}^{35}\text{Cl} \)
  • $25\%$ \( {}^{37}\text{Cl} \)

Calculate the relative atomic mass of chlorine.

▶️Answer/Explanation

Use the formula:
\( A_r = \frac{(75 \times 35) + (25 \times 37)}{100} \)
\( A_r = \frac{2625 + 925}{100} = \frac{3550}{100} = 35.5 \)
Relative atomic mass of chlorine is 35.5

Example

Explain why isotopes of an element show identical chemical behavior but differ in physical properties.

▶️Answer/Explanation

Chemical behavior depends on electron configuration, which is determined by the number of protons (same for all isotopes).
Physical properties depend on mass. Since isotopes have different numbers of neutrons, their masses vary, leading to different densities, boiling points, and diffusion rates.

Example

Which statement is correct about isotopes of the same element?

  1. They have different numbers of protons.
  2. They have different atomic numbers.
  3. They have identical chemical properties.
  4. They have the same mass number.
▶️Answer/Explanation

Correct Answer: C
Isotopes have the same number of electrons and thus behave the same chemically.

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