IB DP Chemistry - S1.3.5 Orbital configurations and rules - Study Notes - New Syllabus - 2026, 2027 & 2028
IB DP Chemistry – S1.3.5 Orbital configurations and rules – Study Notes – New Syllabus
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Structure 1.3.5 — Electron Configuration, Orbitals and Principles
Structure 1.3.5 — Electron Configuration, Orbitals and Principles
Each orbital is a region of space around the nucleus where there is a high probability of finding an electron. These orbitals are defined energy states within sublevels and can hold a maximum of two electrons with opposite spin.
Principles:
- Pauli Exclusion Principle: No two electrons in the same atom can have the same set of quantum numbers – each orbital holds a maximum of two electrons with opposite spins.
- Hund’s Rule: When electrons occupy orbitals of the same energy (degenerate orbitals), they fill singly first with parallel spins before pairing occurs.
- Aufbau Principle: Electrons fill lower energy orbitals first before occupying higher ones.
Sublevels and Number of Orbitals:
- s sublevel: 1 orbital → max 2 electrons
- p sublevel: 3 orbitals → max 6 electrons
- d sublevel: 5 orbitals → max 10 electrons
- f sublevel: 7 orbitals → max 14 electrons
Each main energy level (n) contains a specific number of sublevels, which are split into orbitals:
- n = 1 → 1s
- n = 2 → 2s, 2p
- n = 3 → 3s, 3p, 3d
- n = 4 → 4s, 4p, 4d, 4f
Electron configurations up to atomic number \( Z = 36 \) (Krypton) can be determined by applying these rules to distribute electrons among the orbitals in increasing energy order.
Applying Electron Configuration Rules (Z ≤ 36)
To deduce electron configurations for atoms and ions (up to atomic number 36), we apply three key principles:
1. Aufbau Principle: Electrons fill orbitals starting with the lowest available energy levels before moving to higher ones.
2. Hund’s Rule: Within a sublevel, electrons fill degenerate orbitals singly first (with parallel spins), and only pair when no empty orbital remains.
3. Pauli Exclusion Principle: Each orbital can hold a maximum of two electrons with opposite spins.
Order of Orbital Filling (up to Z = 36):
1s → 2s → 2p → 3s → 3p → 4s → 3d → 4p
Subshell Capacities: s (2 electrons), p (6), d (10), f (14)
Notice that within the same principal level, orbitals with a lower value of l have lower energy (E) and therefore, are filled first. So, for a given value of n:
$\text{E (s orbital) < E ( p orbital) < E (d orbital) < E ( f orbital)}$
Full and Condensed Electron Configurations
1. Full Electron Configuration: Lists all orbitals and the number of electrons in each. Example for sulfur (Z = 16):
\( 1s^2\, 2s^2\, 2p^6\, 3s^2\, 3p^4 \)
2. Condensed Electron Configuration (Noble Gas Core):
Use the configuration of the nearest noble gas in brackets, then continue from there:
Sulfur (Z = 16): \( [\text{Ne}]\, 3s^2\, 3p^4 \)
Why Use Condensed Configurations?
- Saves time and space when writing configurations
Orbital Diagrams (Arrow-in-Box)
Orbital diagrams show how electrons are arranged within orbitals, respecting Hund’s rule and Pauli’s exclusion principle
Stability of Half-Filled and Filled Sublevels:
The electron jumps from the $4s$ level to the $3d$ level compensating the energy uphill by a stabilization associated with half-filled orbitals.
Example: Nitrogen (Z = 7)
Electron configuration: \( 1s^2\, 2s^2\, 2p^3 \)
- Each box represents an orbital (e.g., 2p has three boxes: \( p_x \), \( p_y \), \( p_z \))
- Each arrow represents an electron (↑ = spin up, ↓ = spin down)
- Electrons fill degenerate orbitals singly before pairing (Hund’s Rule)
Additional Examples:
1. Sodium (Z = 11)
Full: \( 1s^2\, 2s^2\, 2p^6\, 3s^1 \)
Condensed: \( [\text{Ne}]\, 3s^1 \)
2. Oxygen (Z = 8)
Full: \( 1s^2\, 2s^2\, 2p^4 \)
Condensed: \( [\text{He}]\, 2s^2\, 2p^4 \)
3. Chromium (Z = 24) — Exception
Expected: \( [\text{Ar}]\, 4s^2\, 3d^4 \)
Actual: \( [\text{Ar}]\, 4s^1\, 3d^5 \)
Reason: A half-filled d-subshell (3d⁵) provides extra stability.
4. Copper (Z = 29) — Exception
Expected: \( [\text{Ar}]\, 4s^2\, 3d^9 \)
Actual: \( [\text{Ar}]\, 4s^1\, 3d^{10} \)
Reason: A fully-filled d-subshell (3d¹⁰) is more stable than expected configuration.
Tips:
- Always write in order of increasing energy, not by numerical sequence of shells.
- Use noble gas shorthand for longer configurations: e.g., \( [\text{Ne}]\, 3s^2\, 3p^4 \)
- For ions:
- Remove electrons from the highest energy level (4s before 3d for transition metals).
Example
Write the electron configuration of Calcium (Z = 20).
▶️Answer/Explanation
Follow the order of orbital filling:
\( \text{Ca}: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 \)
Total electrons = 20
Example
Deduce the electron configuration of Fe²⁺ (Z = 26).
▶️Answer/Explanation
Neutral Fe: \( 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^6 \)
Remove 2 electrons from 4s:
\( \text{Fe}^{2+}: 1s^2 2s^2 2p^6 3s^2 3p^6 3d^6 \)
Example
Which element has the electron configuration: \( 1s^2 2s^2 2p^6 3s^2 3p^5 \)?
▶️Answer/Explanation
Add the electrons: 2 + 2 + 6 + 2 + 5 = 17
This is Chlorine (Z = 17)
Example
Explain why chromium (Z = 24) has the unusual configuration \( [\text{Ar}]\, 4s^1 3d^5 \)
▶️Answer/Explanation
This is due to increased stability of half-filled d sublevel:
Instead of \( 4s^2 3d^4 \), chromium prefers \( 4s^1 3d^5 \), giving all five d orbitals one electron (Hund’s Rule).
Example
A sample of a diatomic element (gas at STP) weighs 5.60 g and occupies a volume of 3.36 dm³ at 273 K and 100 kPa. Identify the element, write its full and condensed electron configuration, and calculate the number of electrons in the 3d sublevel of one atom of the element.
▶️Answer/Explanation
Use ideal gas law to calculate number of moles
Use molar volume at STP: 1 mol = 22.7 dm³
\( n = \frac{V}{22.7} = \frac{3.36}{22.7} = 0.148 \, \text{mol} \)
Calculate molar mass
\( M = \frac{m}{n} = \frac{5.60}{0.148} ≈ 37.8 \, \text{g mol}^{-1} \)
Since it’s a diatomic molecule, atomic mass ≈ \( \frac{37.8}{2} ≈ 18.9 \) → Closest element is chlorine (Cl), \( A_r = 35.5 \), so molecule is likely \( \text{Cl}_2 \)
Electron configuration of chlorine (Z = 17)
Full: 1s² 2s² 2p⁶ 3s² 3p⁵
Condensed: [Ne] 3s² 3p⁵
Number of electrons in the 3d sublevel
Cl has no electrons in the 3d sublevel since 3d is filled only after 4s
Answer: 0 electrons in the 3d sublevel