IB DP Chemistry -S1.4.2 Relative atomic and formula masses - Study Notes - New Syllabus - 2026, 2027 & 2028
IB DP Chemistry – S1.4.2 Relative atomic and formula masses – Study Notes – New Syllabus
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Structure 1.4.2 — Relative Atomic Mass \( A_r \) and Relative Formula Mass \( M_r \)
Structure 1.4.2 — Relative Atomic Mass \( A_r \) and Relative Formula Mass \( M_r \)
Relative Atomic Mass (\( A_r \))
The relative atomic mass \( A_r \) of an element is the weighted average mass of the atoms of an element, compared to 1/12 of the mass of a carbon-12 atom.
Key Features:
- \( A_r \) is dimensionless (has no units)
- Based on the carbon-12 scale where \( ^{12}\text{C} \) has a value of exactly 12.000
- Weighted average accounts for isotopic abundances
- Values are taken from the data booklet (to two decimal places)
Relative Formula Mass (\( M_r \))
The relative formula mass \( M_r \) of a compound is the sum of the relative atomic masses of all the atoms in the chemical formula.
- For molecules (covalent compounds), \( M_r \) is the relative molecular mass
- For ionic compounds, it’s referred to as relative formula mass (same symbol, \( M_r \))
- Also dimensionless (no units)
Important:
- Use values of \( A_r \) from the IB Chemistry Data Booklet (not periodic table values from other sources)
- Always round only at the final step of the calculation to maintain accuracy
Common \( A_r \) Values (from Data Booklet):
- H = 1.01
- C = 12.01
- O = 16.00
- Na = 22.99
- Cl = 35.45
- Mg = 24.31
- S = 32.07
Formula to Calculate \( M_r \):
Add the atomic masses (from the data booklet) of each atom in the formula:
\( M_r = \sum (A_r \times \text{number of atoms}) \)
Example: Sodium Hydrogen Carbonate is a common household chemical, otherwise known as bicarbonate of soda. Its molecular formula is NaHCO3.
Example
Calculate the relative molecular mass (\( M_r \)) of ethanol, \( \text{C}_2\text{H}_5\text{OH} \).
▶️Answer/Explanation
Use \( A_r \) values from data booklet:
C = 12.01, H = 1.01, O = 16.00
\( M_r = (2 \times 12.01) + (6 \times 1.01) + (1 \times 16.00) = 24.02 + 6.06 + 16.00 = 46.08 \)
Example
Determine the relative formula mass (\( M_r \)) of magnesium sulfate, \( \text{MgSO}_4 \).
▶️Answer/Explanation
Mg = 24.31, S = 32.07, O = 16.00
\( M_r = 24.31 + 32.07 + (4 \times 16.00) = 24.31 + 32.07 + 64.00 = 120.38 \)
Example
Chlorine has two isotopes: \( ^{35}\text{Cl} \) with 75.77% abundance and \( ^{37}\text{Cl} \) with 24.23% abundance. Calculate the relative atomic mass of chlorine.
▶️Answer/Explanation
\( A_r = (35 \times 0.7577) + (37 \times 0.2423) = 26.5195 + 8.9651 = 35.48 \)
So, the average atomic mass of chlorine is approximately 35.48.
Example
Calculate the mass of 0.250 mol of carbon dioxide, \( \text{CO}_2 \).
▶️Answer/Explanation
\( M_r(\text{CO}_2) = 12.01 + (2 \times 16.00) = 12.01 + 32.00 = 44.01 \, \text{g/mol} \)
Mass = \( n \times M_r = 0.250 \times 44.01 = 11.00 \, \text{g} \)