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IB DP Chemistry – S2.2.11 Resonance structures- Study Notes

IB DP Chemistry - S2.2.11 Resonance structures- Study Notes - New Syllabus - 2026, 2027 & 2028

IB DP Chemistry – S2.2.11 Resonance structures- Study Notes – New Syllabus

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Structure 2.2.11 — Resonance Structures

Structure 2.2.11 — Resonance Structures

 Resonance structures (also known as resonance forms) are two or more valid Lewis structures that can be drawn for a molecule or ion, where the position of electrons (especially π electrons and lone pairs) varies, but the arrangement of atoms remains the same.

Key Concepts:

  • Resonance occurs in species where delocalized electrons are shared between more than two atoms.
  • Instead of being fixed in a single position (as in a double bond), the electrons are spread out (delocalized) over multiple atoms.
  • The true structure of the molecule is a resonance hybrid – an average of all valid resonance structures, not flipping between them.
  • Double-headed arrows (↔) are used to indicate resonance between different Lewis structures.
  • Resonance increases stability by spreading out charge or electron density.

Important Notes:

  • Only electrons move between resonance forms — atom positions do not change.
  • All resonance structures must follow the octet rule where applicable and be valid Lewis structures.
  • Resonance is especially common in aromatic compounds, carboxylates, and polyatomic ions such as nitrate or sulfate.

Example:

  • \( \text{CO}_3^{2-} \) (carbonate ion): Delocalized π electrons over three equivalent oxygen atoms.

Delocalization:

This refers to the spreading of electrons across multiple atoms. In resonance structures, π electrons are not associated with a single bond or atom, but are instead shared over a region (e.g. entire ring or carboxylate group).

Visual Representation:

For example, for the carbonate ion \( \text{CO}_3^{2-} \):

  • Each resonance form has one double bond and two single bonds to oxygen.
  • The actual structure has bond lengths between single and double bonds (delocalized).

Bond Order in Resonance Structures:

The bond order is the average number of bonds across all resonance forms.

For carbonate \( (\text{CO}_3^{2-}) \): \( \text{Bond order} = \frac{\text{Total number of bonds}}{\text{Number of positions}} = \frac{4}{3} \approx 1.33 \)

Example 

Draw all resonance structures for the nitrate ion \( \text{NO}_3^- \) and determine the bond order for the N–O bonds.

▶️Answer/Explanation

Each resonance form places a double bond between nitrogen and one of the three oxygens, with the other two bearing single bonds and negative formal charges.

Bond order = \( \frac{4}{3} \approx 1.33 \), since the nitrogen is forming 4 total bonds to 3 oxygens in the resonance hybrid.

Example 

Which of the following molecules or ions exhibits resonance?

  1. \( \text{CH}_4 \)
  2. \( \text{H}_2\text{O} \)
  3. \( \text{CO}_3^{2-} \)
  4. \( \text{NH}_4^+ \)
▶️Answer/Explanation

Correct answer: C — The carbonate ion has three resonance forms due to delocalized π electrons across the three O atoms.

Example 

Which statement best describes resonance in the ozone molecule \( \text{O}_3 \)?

  1. It oscillates rapidly between one single and one double bond.
  2. It contains one short and one long oxygen–oxygen bond.
  3. It contains delocalized π electrons, making both bonds equal in length.
  4. It forms a linear molecule with different bond orders.
▶️Answer/Explanation

Correct answer: C — Ozone exhibits delocalization of π electrons between the two oxygen–oxygen bonds, making them equal in length and intermediate in bond order (~1.5).

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