IB DP Chemistry - S2.2.11 Resonance structures- Study Notes - New Syllabus - 2026, 2027 & 2028
IB DP Chemistry – S2.2.11 Resonance structures- Study Notes – New Syllabus
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- IB DP Chemistry 2025 SL- IB Style Practice Questions with Answer-Topic Wise-Paper 1
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Structure 2.2.11 — Resonance Structures
Structure 2.2.11 — Resonance Structures
Resonance structures (also known as resonance forms) are two or more valid Lewis structures that can be drawn for a molecule or ion, where the position of electrons (especially π electrons and lone pairs) varies, but the arrangement of atoms remains the same.
Key Concepts:
- Resonance occurs in species where delocalized electrons are shared between more than two atoms.
- Instead of being fixed in a single position (as in a double bond), the electrons are spread out (delocalized) over multiple atoms.
- The true structure of the molecule is a resonance hybrid – an average of all valid resonance structures, not flipping between them.
- Double-headed arrows (↔) are used to indicate resonance between different Lewis structures.
- Resonance increases stability by spreading out charge or electron density.
Important Notes:
- Only electrons move between resonance forms — atom positions do not change.
- All resonance structures must follow the octet rule where applicable and be valid Lewis structures.
- Resonance is especially common in aromatic compounds, carboxylates, and polyatomic ions such as nitrate or sulfate.
Example:
- \( \text{CO}_3^{2-} \) (carbonate ion): Delocalized π electrons over three equivalent oxygen atoms.
Delocalization:
This refers to the spreading of electrons across multiple atoms. In resonance structures, π electrons are not associated with a single bond or atom, but are instead shared over a region (e.g. entire ring or carboxylate group).
Visual Representation:
For example, for the carbonate ion \( \text{CO}_3^{2-} \):
- Each resonance form has one double bond and two single bonds to oxygen.
- The actual structure has bond lengths between single and double bonds (delocalized).
Bond Order in Resonance Structures:
The bond order is the average number of bonds across all resonance forms.
For carbonate \( (\text{CO}_3^{2-}) \): \( \text{Bond order} = \frac{\text{Total number of bonds}}{\text{Number of positions}} = \frac{4}{3} \approx 1.33 \)
Example
Draw all resonance structures for the nitrate ion \( \text{NO}_3^- \) and determine the bond order for the N–O bonds.
▶️Answer/Explanation
Each resonance form places a double bond between nitrogen and one of the three oxygens, with the other two bearing single bonds and negative formal charges.
Bond order = \( \frac{4}{3} \approx 1.33 \), since the nitrogen is forming 4 total bonds to 3 oxygens in the resonance hybrid.
Example
Which of the following molecules or ions exhibits resonance?
- \( \text{CH}_4 \)
- \( \text{H}_2\text{O} \)
- \( \text{CO}_3^{2-} \)
- \( \text{NH}_4^+ \)
▶️Answer/Explanation
Correct answer: C — The carbonate ion has three resonance forms due to delocalized π electrons across the three O atoms.
Example
Which statement best describes resonance in the ozone molecule \( \text{O}_3 \)?
- It oscillates rapidly between one single and one double bond.
- It contains one short and one long oxygen–oxygen bond.
- It contains delocalized π electrons, making both bonds equal in length.
- It forms a linear molecule with different bond orders.
▶️Answer/Explanation
Correct answer: C — Ozone exhibits delocalization of π electrons between the two oxygen–oxygen bonds, making them equal in length and intermediate in bond order (~1.5).