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IBDP Physics SL Paper 1B- Data-Based Question- New Syllabus

Question 

A student investigates whether the Stefan-Boltzmann law, \(L=4\pi\sigma R^{2}T^{4}\), applies to stars.

\(L=\) luminosity of the star, in W

\(\sigma=\) Stefan-Boltzmann constant

\(R=\) radius of the star, in m

\(T=\) surface temperature of the star, in K

To verify the law, they obtain values from databases and manipulate the data as shown.

Star\(L\)\(R\)\(T\)\(\dfrac{L}{R^{2}}\)\(\log\left(\dfrac{L}{R^{2}}\right)\)\(\log(T)\)
10 Lacertae\(3.92\times10^{31}\)\(5.75\times10^{9}\)\(3.62\times10^{4}\)\(1.19\times10^{12}\)12.14.56
\(\sigma\)-Orionis A\(1.60\times10^{31}\)\(3.90\times10^{9}\)\(3.49\times10^{4}\)\(1.05\times10^{12}\)12.04.54
\(\sigma\)-Orionis B\(6.08\times10^{30}\)\(3.48\times10^{9}\)\(2.91\times10^{4}\)\(5.02\times10^{11}\)11.74.46
Polaris B\(1.50\times10^{27}\)\(9.60\times10^{8}\)\(6.90\times10^{3}\)\(1.63\times10^{9}\)9.213.84
\(\alpha\)-Centauri A\(5.77\times10^{26}\)\(8.49\times10^{8}\)\(5.79\times10^{3}\)\(8.00\times10^{8}\)8.903.76
\(\alpha\)-Centauri B\(1.92\times10^{26}\)\(5.97\times10^{8}\)\(5.26\times10^{3}\)\(5.39\times10^{8}\)8.733.72
\(\epsilon\)-Indi\(8.08\times10^{25}\)\(4.95\times10^{8}\)\(4.65\times10^{3}\)\(3.30\times10^{8}\)8.523.67
Sun\(3.85\times10^{26}\)\(6.96\times10^{8}\)\(5.78\times10^{3}\)\(7.95\times10^{8}\)8.903.76

(a) Complete the table with the missing values for Polaris B.

\(\boxed{\hspace{6cm}}\)

The student plots the variation in \(\log(T)\) of \(\log\left(\dfrac{L}{R^{2}}\right)\) and draws the line of best fit.

The student uses a GDC (graphical display calculator) to determine the equation of the line of best fit as

\(y=3.99x-6.15\)

(b) Explain how the gradient of the line of best fit relates to the Stefan-Boltzmann law.

\(\boxed{\hspace{9cm}}\)

(c) Calculate the Stefan-Boltzmann constant obtained in this investigation.

\(\boxed{\hspace{8cm}}\)

(d) Outline a conclusion for the investigation.

\(\boxed{\hspace{9cm}}\)

(e) Suggest a possible improvement of the investigation, related to the range of the surface temperatures of the stars selected.

\(\boxed{\hspace{9cm}}\)

▶️ Answer/Explanation

(a) Correct Answer: \( \boxed{1.63\times10^{9}} \) and \( \boxed{3.84} \)

For Polaris B,

\(\dfrac{L}{R^{2}}=\dfrac{1.50\times10^{27}}{(9.60\times10^{8})^{2}}\)

\(\dfrac{L}{R^{2}}\approx1.63\times10^{9}\)

Therefore,

\(\log\left(\dfrac{L}{R^{2}}\right)=\log(1.63\times10^{9})\approx9.21\)

Also, \(\log(6.90\times10^{3})\approx\boxed{3.84}\).

(b) Correct Answer:

The Stefan-Boltzmann law is

\(L=4\pi\sigma R^{2}T^{4}\)

Rearranging,

\(\dfrac{L}{R^{2}}=4\pi\sigma T^{4}\)

Taking logarithms gives

\(\log\left(\dfrac{L}{R^{2}}\right)=\log(4\pi\sigma)+4\log(T)\)

Comparing this with \(y=mx+c\), the gradient should therefore be \(4\).

The experimental gradient is \(3.99\), which is very close to \(4\), supporting the Stefan-Boltzmann law.

(c) Correct Answer: \( \boxed{5.63\times10^{-8}\,\mathrm{W\,m^{-2}\,K^{-4}}} \)

The intercept of the graph is \(-6.15\). From

\(\log\left(\dfrac{L}{R^{2}}\right)=4\log(T)+\log(4\pi\sigma)\)

the intercept is

\(\log(4\pi\sigma)=-6.15\)

Therefore,

\(4\pi\sigma=10^{-6.15}\)

\(\sigma=\dfrac{10^{-6.15}}{4\pi}\)

\(\sigma\approx5.63\times10^{-8}\,\mathrm{W\,m^{-2}\,K^{-4}}\)

Hence, \( \boxed{\sigma=5.63\times10^{-8}\,\mathrm{W\,m^{-2}\,K^{-4}}} \).

(d) Correct Answer:

The approximately linear graph has a gradient close to \(4\), as predicted by the Stefan-Boltzmann law.

The value of \(\sigma\) obtained experimentally is also close to the accepted value.

Therefore, the investigation provides evidence that the Stefan-Boltzmann law applies to stars.

(e) Correct Answer:

Use a wider range of stellar surface temperatures, including stars with temperatures both lower and higher than those currently selected. This would provide a greater range of data and make the relationship easier to test.

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