IBDP Physics- A.3 Work, energy and power- IB Style Questions For SL Paper 1A -FA 2025
Question
(B) \(\frac{kx}{\Delta t}\)
(C) \(\frac{kx^{2}}{2\Delta t}\)
(D) \(\frac{kx^{2}}{\Delta t}\)
▶️ Answer/Explanation
1. Calculate Energy Stored:
The potential energy stored in a spring extended by \(x\) is given by \(E_p = \frac{1}{2}kx^2\).
2. Define Power:
Power is the rate at which work is done or energy is transferred.
\(P = \frac{\text{Energy}}{\text{Time}}\)
3. Calculate Average Power:
As the spring returns to its original length, it releases this stored energy over time \(\Delta t\).
\(P = \frac{\frac{1}{2}kx^2}{\Delta t} = \frac{kx^2}{2\Delta t}\).
✅ Answer: (C)
Question
B. \(0.8\,\text{m}\)
C. \(1.2\,\text{m}\)
D. \(2.0\,\text{m}\)
▶️ Answer / Explanation
Useful output power:
\(P_\text{useful} = \text{efficiency} \times P_\text{input}\)
\(P_\text{useful} = 0.40 \times 200 = 80\,\text{W}\)
Work done in \(1\,\text{s}\):
\(W = Pt = 80 \times 1 = 80\,\text{J}\)
This work equals the gain in gravitational potential energy:
\(W = mgh\)
\(80 = 10 \times 9.81 \times h\)
\(h \approx 0.815\,\text{m}\)
Rounded to one decimal place:
✅ Answer: B
Question
| Kinetic energy | Total energy | |
|---|---|---|
| A | constant | decreases |
| B | increases | decreases |
| C | constant | constant |
| D | increases | constant |
▶️ Answer/Explanation
At terminal velocity, the speed is constant, so the kinetic energy of the ball remains constant.
As the ball continues to fall, gravitational potential energy is transferred to the surroundings as thermal energy due to air resistance. So the total energy of the ball decreases.
✅ Answer: (A)
