Question
After a race, athletes experience oxygen debt.
The diagram shows how the oxygen debt is removed.

What happens at $X$?
(B) aerobic respiration of lactic acid
(C) anaerobic respiration of glucose
(D) anaerobic respiration of lactic acid
▶️ Answer/Explanation
✅ Answer: (B)
Question
Which sequence of statements explains the build-up and removal of an oxygen debt?
1 Anaerobic respiration occurs in muscles during vigorous exercise.
2 Faster and deeper breathing continues after exercise.
3 Glucose is converted to lactic acid.
4 Lactic acid builds up in muscles causing an oxygen debt.
5 Oxygen enables the continued aerobic respiration of lactic acid.
(B) $1 \rightarrow 3 \rightarrow 2 \rightarrow 4 \rightarrow 5$
(C) $3 \rightarrow 4 \rightarrow 5 \rightarrow 1 \rightarrow 2$
(D) $3 \rightarrow 4 \rightarrow 1 \rightarrow 5 \rightarrow 2$
▶️ Answer/Explanation
The process begins when vigorous exercise triggers anaerobic respiration (1) because oxygen demand exceeds supply. This metabolic pathway converts glucose into lactic acid (3), which accumulates in the muscle tissues and creates an oxygen debt (4). To “repay” this debt after exercise stops, the body maintains faster and deeper breathing (2) to take in extra oxygen. This supplemental oxygen then facilitates the aerobic respiration of lactic acid (5) in the liver, breaking it down into carbon dioxide and water. This logical progression from the cause of the debt to its physiological resolution confirms the sequence.
✅ Answer: (A)
Question
Yeast can respire aerobically and anaerobically.
For each molecule of glucose used in yeast, how many more molecules of carbon dioxide gas are produced by aerobic respiration compared with anaerobic respiration?
(B) $2$ more
(C) $4$ more
(D) $6$ more
▶️ Answer/Explanation
To solve this, we compare the balanced equations for both types of respiration in yeast. In aerobic respiration, one molecule of glucose reacts with oxygen to produce $6$ molecules of $CO_{2}$ ($C_{6}H_{12}O_{6} + 6O_{2} \rightarrow 6CO_{2} + 6H_{2}O$). In anaerobic respiration (fermentation), yeast breaks down one molecule of glucose into ethanol and only $2$ molecules of $CO_{2}$ ($C_{6}H_{12}O_{6} \rightarrow 2C_{2}H_{5}OH + 2CO_{2}$). By subtracting the anaerobic yield from the aerobic yield ($6 – 2 = 4$), we find that aerobic respiration produces $4$ additional molecules of carbon dioxide per glucose molecule.
✅ Answer: (C)
