Question
Pea plants produce seeds in pods. The colour of pea pods is controlled by a single gene. Some pea pods are green and some are yellow.
The allele for green is dominant and is represented by the letter G.
The allele for yellow is recessive and is represented by the letter g.
(b) Fig. 5.1 is a pedigree diagram for the inheritance of pod colour in some pea plants. 
The possible genotypes for pea pod colour are GG, Gg and gg.
Determine the genotypes of individual 1 and individual 2 in Fig. 5.1. Explain how you determined your answer for each individual.
Complete the Punnett square to determine the possible genotypes of the offspring and calculate the expected phenotypic ratio.

▶️ Answer/Explanation
(a) An allele is an alternative form of a gene.
(b) Individual 1: $gg$ / homozygous recessive.
[cite_start]Explanation: The individual has the recessive phenotype (yellow pods), which is only expressed when no dominant allele is present.
Individual 2: $Gg$ / heterozygous.
Explanation: The individual has the dominant phenotype (green) but produced offspring with the recessive phenotype (yellow). This means they must possess one dominant allele ($G$) and one recessive allele ($g$) to pass on to the yellow offspring.
(c) Punnett Square:
Gametes: $G$ and $g$ for both parents.
Offspring Genotypes: $GG$, $Gg$, $Gg$, $gg$.
Phenotypic ratio: 3 green pods : 1 yellow pod.
Part (a): Defining Alleles
Genes determine specific traits (like pod colour), but these genes can exist in different versions. These versions are called alleles. For example, the gene for pod colour has a “green” version (allele) and a “yellow” version (allele).
Part (b): Interpreting the Pedigree
Pedigree diagrams show how traits are passed down through generations.
- Individual 1 (Yellow): The key indicates yellow is the recessive trait ($g$). A recessive trait is only expressed in the phenotype if the genotype is homozygous recessive ($gg$). Therefore, Individual 1 must be $gg$.
- Individual 2 (Green): This individual is green, so they must have at least one dominant allele ($G$). However, they are the parent of individuals 4 and 6, who are yellow ($gg$). For a child to be $gg$, they must inherit one $g$ from the mother and one $g$ from the father. [cite_start]Since Individual 2 passed a $g$ to the offspring, their genotype must be heterozygous ($Gg$).
Part (c): Monohybrid Cross
We are crossing two heterozygous plants ($Gg \times Gg$).We use a Punnett square to predict the offspring.
| $G$ | $g$ | |
| $G$ | $GG$ (Green) | $Gg$ (Green) |
| $g$ | $Gg$ (Green) | $gg$ (Yellow) |
There are 3 outcomes that result in a green phenotype ($GG, Gg, Gg$) and 1 outcome that results in a yellow phenotype ($gg$).
Ratio: 3 : 1.
